-6/12=x/8=-7/y=z/-18
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HQ
1
2
28 tháng 12 2021
Ta có :
\(\frac{-6}{12}=\frac{x}{8}=\frac{-7}{y}=\frac{z}{-18}=\frac{-1}{2}\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{8}=\frac{-1}{2}\Rightarrow x=\left(-4\right)\\\frac{-7}{y}=\frac{-1}{2}\Rightarrow y=14\\\frac{z}{-18}=\frac{-1}{2}\Rightarrow z=9\end{cases}}\)
Vậy ...
DT
1
26 tháng 3 2016
-6 /12 = x /8 = -7 /y = z /-18
=>-6*8=12*x
-48=12*x
-48:12=x
=>x=-4
thayx:-6 /12=-4/8=-7/y=z/-18
=>-4*y=8*7
-4*y=56
y=56:(-4)
y=14
=>y=14
thayy:-6/12=-4/8=-7/14=z/18
-4*18=8*z
-72=8*z
-72:8=z
-9=z
=>z=-9
vayx=-4;y=14;z=-9
HD
2
27 tháng 4 2016
mình cũng muốn giup nhưng mình hơi nhác
xin lỗi nhiều nha!!!!!!!
CC
1
DD
6 tháng 5 2018
Giải:
Theo đề ra, ta có:
\(\dfrac{x}{8}=-\dfrac{7}{y}=\dfrac{z}{-18}=\dfrac{16}{t}=-\dfrac{6}{12}\)
\(\Leftrightarrow\dfrac{x}{8}=-\dfrac{7}{y}=-\dfrac{z}{18}=\dfrac{16}{t}=-\dfrac{1}{2}\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{8}=-\dfrac{1}{2}\\-\dfrac{7}{y}=-\dfrac{1}{2}\\-\dfrac{z}{18}=-\dfrac{1}{2}\\\dfrac{16}{t}=-\dfrac{1}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{1}{2}.8\\y=-7:\left(-\dfrac{1}{2}\right)\\z=-\dfrac{1}{2}.\left(-18\right)\\t=16:\left(-\dfrac{1}{2}\right)\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-4\\y=14\\z=9\\t=-32\end{matrix}\right.\)
Vậy ...
15 tháng 2 2021
Bài 9:
Ta có: \(\dfrac{12}{-6}=\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{z}{-17}=\dfrac{-t}{-9}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{-z}{17}=\dfrac{t}{9}=-2\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{5}=-2\\\dfrac{-y}{3}=-2\\\dfrac{-z}{17}=-2\\\dfrac{t}{9}=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-10\\-y=-6\\-z=-34\\t=-18\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-10\\y=6\\z=34\\t=-18\end{matrix}\right.\)
Vậy: (x,y,z,t)=(-10;6;34;-18)
Bài 11:
Ta có: \(\dfrac{-7}{6}=\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{u}{-78}\)
\(\Leftrightarrow\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{u}{-78}=\dfrac{-7}{6}\)
Ta có: \(\dfrac{x}{18}=\dfrac{-7}{6}\)
\(\Leftrightarrow x=\dfrac{18\cdot\left(-7\right)}{6}=-21\)
Ta có: \(\dfrac{-98}{y}=\dfrac{-7}{6}\)
\(\Leftrightarrow y=\dfrac{-98\cdot6}{-7}=84\)
Ta có: \(\dfrac{-14}{z}=\dfrac{-7}{6}\)
\(\Leftrightarrow z=\dfrac{-14\cdot6}{-7}=12\)
Ta có: \(\dfrac{u}{-78}=\dfrac{-7}{6}\)
\(\Leftrightarrow u=\dfrac{-78\cdot\left(-7\right)}{6}=\dfrac{78\cdot7}{6}=91\)
Ta có: \(\dfrac{t}{102}=\dfrac{-7}{6}\)
\(\Leftrightarrow t=\dfrac{-7\cdot102}{6}=-7\cdot17=-119\)
Vậy: (x,y,z,t,u)=(-21;84;12;-119;91)
29 tháng 1 2024
a: \(\dfrac{-4}{8}=\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}\)
=>\(\dfrac{x}{-10}=\dfrac{-7}{y}=\dfrac{z}{-24}=\dfrac{-1}{2}\)
=>\(\left\{{}\begin{matrix}x=\left(-10\right)\cdot\dfrac{\left(-1\right)}{2}=5\\y=\dfrac{-7\cdot2}{-1}=14\\z=\dfrac{-24\cdot\left(-1\right)}{2}=\dfrac{24}{2}=12\end{matrix}\right.\)
b: \(\dfrac{-3}{6}=\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{-z}{24}\)
=>\(\dfrac{x}{-2}=\dfrac{-18}{y}=\dfrac{z}{-24}=\dfrac{-1}{2}\)
=>\(\dfrac{x}{2}=\dfrac{18}{y}=\dfrac{z}{24}=\dfrac{1}{2}\)
=>\(x=2\cdot\dfrac{1}{2}=1;y=18\cdot\dfrac{2}{1}=36;z=\dfrac{24}{2}=12\)
3 tháng 5 2016
Ta có:\(\frac{-6}{12}=\frac{x}{8}\)
=>12x = -6.8
x=-6.8:12
x=-4
\(\frac{-6}{12}=\frac{-7}{y}\) => -6y=-7.12
y=-7.12:-6
y=14
\(\frac{-6}{12}=\frac{z}{-18}\) =>12z = -6.-18
z= -6.-18:12
z= 9
TL
8 tháng 4 2016
-6/12=-1/2
suy ra : x=(-1/2)*8=-4
y=(-7)/(-1/2)=14
z=(-1/2)*(-18)=9
+-6/12= x/8=> 12.x= -48
x= -48: 12
x=-4 (thoả mãn)
+-6/12=-7/y=> -6.y= -84
y= -84 : -6
y= 14 ( thoả mãn)
+-6/12=z/-18=> 12.z= 108
z= 108:12
z=9 (t/m)