2/5.15/7-[10/7:2 1/5-1]
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cố hỉu nha bn:
a, A = (-1/2)2 - |-7/8| - 5/12 - 3/4
= 1/4 - 7/8 - 5/12 - 3/4
= ( 1/4 - 3/4 ) - ( 7/8 - 5/12 )
= -1/2 - 11/24
= -23/24
A= \(\frac{25^3.5^3}{6.5^{10}}\)= \(\frac{\left(5^2\right)^3.5^3}{6.5^{10}}\)= \(\frac{5^6.5^3}{6.5^{10}}\)= \(\frac{5^9}{6.5^{10}}\)= \(\frac{5}{6}\)
B = \(\frac{2^5.6^3}{8^2.9^2}\)= \(\frac{2^5.\left(2.3\right)^3}{\left(2^3\right)^2.\left(3^2\right)^2}\)=\(\frac{2^5.2^3.3^3}{2^6.3^4}\)= \(\frac{2^8.3^3}{2^6.3^4}\)= \(\frac{2^2}{3}\)= \(\frac{4}{3}\)
C = \(\frac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}\)= \(\frac{5^3.3^3+5.5^2.3^2-5^3}{6^3.3^3+6.6^2.3^2-6^3}\)= \(\frac{5^3+5^3.3^2-5^3}{6^3.3^3+6^3.3^2-6^3}\)= \(\frac{5^3.\left(1+3^2-1\right)}{6^3.\left(3^3+3^2-1\right)}\)= \(\frac{5^3.9}{6^3.35}\)
=\(\frac{5^3.3^2}{2^3.3^3.7.5}\)
= \(\frac{25}{168}\)
D = \(\frac{\left(7^4-7^3\right)^2}{49^3}\)= \(\frac{[7^3\left(7-1\right)]^2}{\left(7^2\right)^3}\)= \(\frac{7^6.6^2}{7^6}\)= \(36\)
g)\(=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right).\dfrac{7}{3}+\left(\dfrac{3}{5}+-\dfrac{1}{4}\right).\dfrac{7}{3}\)
\(=\left(-\dfrac{3}{4}+-\dfrac{1}{4}+\dfrac{2}{5}+\dfrac{3}{5}\right).\dfrac{7}{3}\)
\(=\left(-1+1\right).\dfrac{7}{3}=0.\dfrac{7}{3}=0\)
f) \(\dfrac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}\)
\(=\dfrac{3^3.5^3+5.5^2.3^2-5^3}{3^3.6^3+6.6^2.3^2-6^3}\)
\(=\dfrac{5^3.\left(3^3+3^2-1\right)}{6^3.\left(3^3+3^2-1\right)}\)
\(=\dfrac{5^3}{6^3}\)
\(=\dfrac{125}{216}\)
\(\frac{2^5\cdot6^{14}\cdot10^7}{2\cdot8^8\cdot3^5\cdot15^7}\)
\(=\frac{2^5\cdot2^{14}\cdot3^{14}\cdot2^7\cdot5^7}{2\cdot2^8\cdot2^8\cdot2^8\cdot3^5\cdot3^7\cdot5^7}\)
\(=\frac{2^{26}\cdot3^{14}\cdot5^7}{2^{25}\cdot3^{12}\cdot5^7}\)
\(=2\cdot3^2\)
= 2 x 9
= 18
\(\frac{2^5\cdot2^{14}\cdot3^{14}\cdot2^7\cdot5^7}{2\cdot\left(2^3\right)^8\cdot3^5\cdot3^7\cdot5^7}=\frac{2^{26}\cdot3^{14}\cdot5^7}{2^{25}\cdot3^{12}\cdot5^7}=2\cdot3^2=18\)
=6/7-[(10/7:21/5)-1]
=6/7-[50/147-1]
=6/7-(-97/147)
=6/7+97/147
=1561/1029=>TỐI GIẢN =223/147 NHA