6/11 + 11/3 + 3/22
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Những câu hỏi liên quan
PB
0
C
0
25 tháng 2 2022
\(A=\dfrac{5}{11}.\dfrac{5}{7}+\dfrac{5}{11}.\dfrac{2}{7}+\dfrac{6}{11}=\dfrac{5}{11}\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\dfrac{6}{11}=\dfrac{5}{11}.1+\dfrac{6}{11}=\dfrac{5}{11}+\dfrac{6}{11}=\dfrac{11}{11}=1\)
\(B=\dfrac{3}{13}.\dfrac{6}{11}+\dfrac{3}{13}.\dfrac{9}{11}-\dfrac{3}{13}.\dfrac{4}{11}=\dfrac{3}{13}\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}.1=\dfrac{3}{13}\)
\(C=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right)\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)=\left(\dfrac{12}{16}-\dfrac{31}{22}+\dfrac{14}{91}\right).0=0\)
NT
3
NH
7 tháng 2 2023
a)
\(\dfrac{6}{13}\cdot\dfrac{8}{7}\cdot\dfrac{-26}{3}\cdot\dfrac{-7}{8}\)
\(=\dfrac{6}{13}\cdot\dfrac{-26}{3}\cdot\dfrac{8}{7}\cdot\dfrac{-7}{8}\)
\(=-4\cdot\left(-1\right)\\ =4\)
b)
\(\dfrac{6}{11}+\dfrac{11}{3}\cdot\dfrac{3}{22}\)
\(=\dfrac{6}{11}+\dfrac{1}{2}\\ =\dfrac{12}{22}+\dfrac{11}{22}\\ =\dfrac{23}{22}\)
HD
15 tháng 4 2020
\(m.\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)\)
\(=\frac{31}{23}-\frac{7}{32}-\frac{8}{23}\)
\(=\left(\frac{31}{23}-\frac{8}{23}\right)-\frac{7}{32}\)
\(=1-\frac{7}{32}=\frac{25}{32}\)
\(n.\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(=\frac{1}{3}+\left(-1\right)+1\)
\(=\frac{1}{3}\)
\(o.\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)
\(=\frac{38}{45}-\frac{8}{45}+\frac{17}{51}+\frac{3}{11}\)
\(=\left(\frac{38}{45}-\frac{8}{45}\right)+\left(\frac{17}{51}+\frac{3}{11}\right)\)
\(=\frac{2}{3}+\frac{20}{33}\)
\(=\frac{22}{33}+\frac{20}{33}=\frac{42}{33}=\frac{14}{11}\)
27 tháng 4 2020
BÀI 1
a, \(5\times\frac{-7}{10}=\frac{-35}{10}=\frac{-7}{2}\)
b, \(\frac{4}{5}\times\frac{-7}{10}=\frac{-28}{50}=\frac{-14}{25}\)
c, \(\frac{4}{9}+\frac{4}{3}\times\frac{16}{4}=\frac{4}{9}+\frac{16}{3}=\frac{52}{9}\)
d, \(\frac{11}{22}-\frac{3}{9}\times\frac{14}{21}=\frac{11}{22}-\frac{2}{9}=\frac{55}{198}=\frac{5}{18}\)
BÀI 2
\(A=\frac{6}{13}\times\frac{5}{7}+\frac{6}{13}\times\frac{2}{7}+\frac{17}{13}\)
\(A=\frac{30}{91}+\frac{12}{91}+\frac{17}{13}\)
\(A=\frac{30}{91}+\frac{12}{91}+\frac{119}{91}\)
\(A=\frac{161}{91}=\frac{23}{13}\)
\(B=\frac{11}{15}\times\frac{4}{11}+\frac{11}{15}\times\frac{5}{11}+\frac{11}{15}\times\frac{2}{11}\)
\(B=\frac{4}{15}+\frac{1}{3}+\frac{2}{15}\)
\(B=\frac{11}{15}\)
\(C=\left(\frac{19}{64}-\frac{33}{22}+\frac{24}{51}\right)\times\left(\frac{1}{5}-\frac{1}{15}-\frac{2}{15}\right)\)
\(C=\frac{-797}{1088}\times0\)
\(C=0\)
\(D=\frac{8}{13}\times\frac{7}{12}+\frac{8}{13}\times\frac{5}{12}-\frac{1}{12}\)
\(D=\frac{14}{39}+\frac{10}{39}-\frac{1}{12}\)
\(D=\frac{83}{156}\)
LT
3 tháng 10 2021
bạn biết câu náy không (24 + 11) . {546 - [14 . (64 - 2^{3}3) : 2]} =
HQ
Hà Quang Minh
Giáo viên
5 tháng 10 2023
a) \(\dfrac{7}{8} + \dfrac{7}{8}:\dfrac{1}{8} - \dfrac{1}{2}\)
\(\begin{array}{l} = \dfrac{7}{8} + \dfrac{7}{8}.8 - \dfrac{1}{2}\\ = \dfrac{7}{8}.1 + \dfrac{7}{8}.8 - \dfrac{1}{2}\\ = \left( {\dfrac{7}{8}.1 + \dfrac{7}{8}.8} \right) - \dfrac{1}{2}\\ = \dfrac{7}{8}.\left( {1 + 8} \right) - \dfrac{1}{2} = \dfrac{7}{8}.9 - \dfrac{1}{2}\\ = \dfrac{{63}}{8} - \dfrac{1}{2} = \dfrac{{63}}{8} - \dfrac{4}{8} = \dfrac{{63 - 4}}{8} = \dfrac{{59}}{8}\end{array}\)
b) \(\dfrac{6}{{11}} + \dfrac{{11}}{3}.\dfrac{3}{{22}}\)
\(\begin{array}{l} = \dfrac{6}{{11}} + \dfrac{{11.3}}{{3.22}} = \dfrac{6}{{11}} + \dfrac{1}{2}\\ = \dfrac{{12}}{{22}} + \dfrac{{11}}{{22}} = \dfrac{{12 + 11}}{{22}} = \dfrac{{23}}{{22}}\end{array}\)
TL
6/11+11/3+3/11
=139/33+3/11
=287/66
nha bn
HT
\(\frac{6}{11}+\frac{11}{3}+\frac{3}{22}=\frac{36}{66}+\frac{242}{66}+\frac{9}{66}=\frac{36+242+9}{66}=\frac{287}{66}\)
HT