x:4/7=6/7-1/3 ai trả lời đúng đc 1 tick
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Để \(x\left(2+x^2\right)\left(7-x\right)=0\hept{\begin{cases}x=0\\2+x^2=0\\7-x=0\end{cases}}\)
Mà \(2+x^2>0\) => \(\orbr{\begin{cases}x=0\\7-x=0\end{cases}}\)=> \(\orbr{\begin{cases}x=0\\x=7\end{cases}}\)
Vậy x = { 0; 7 }
x - 4/5 = 3/7
x = 3/7 + 4/5
x = 43/35
x + 3/7 = 4/5
x = 4/5 - 3/7
x = 13/35
19/20 - x = 8/5 - 3/4
19/20 - x = 17/20
x = 19/20 - 17/20
x = 2/20 = 1/10
4/5 x X = 6/9 - 4/7
4/5 x X = 2/21
x = 2/21 : 4/5
x =5/42
x : 7/9 = 6/8
x = 6/8 x 7/9
x = 7/12
2/3 - x/6 = 6/18
x/6 = 2/3 - 6/18
x/6 = 1/3
x/6 = 2/6
=> x =2
1. x = 43/35
2. x = 13/35
3. x = 1/10
còn lại tự tính nhá
tui bận òi
(dấu . là dấu nhân )
a, \(\frac{3}{2}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{3}{2}\)
= \(\frac{3}{2}\left(\frac{4}{7}+\frac{3}{7}\right)\)
=\(\frac{3}{2}\cdot\frac{7}{7}=\frac{3}{2}\)
b, \(\frac{12}{5}\cdot4-4\cdot\frac{7}{5}\)
=\(4\left(\frac{12}{5}-\frac{7}{5}\right)=4\cdot\frac{5}{5}=4\)
c, \(\frac{5}{11}:\frac{1}{2}+\frac{6}{11}:\frac{1}{2}\)
=\(2\left(\frac{5}{11}+\frac{6}{11}\right)=2\cdot\frac{11}{11}=2\)
a;3/2x(4/7+3/7)
=3/2x1
=3/2
b;12/5x4-4x7/5
=4x(12/5-7/5)
=4x1
=4
c;5/11:1/2+6/11:1/2
=1/2:(5/11+6/11)
=1/2:1
=1/2
\(\left(\frac{2}{3}x-1\right)\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)
=>\(\frac{2}{3}x-1=0\) hoặc \(\frac{3}{4}x+\frac{1}{2}=0\)
+)Nếu \(\frac{2}{3}x-1=0\)
=>\(\frac{2}{3}x=1\Rightarrow x=\frac{3}{2}\)
+)Nếu \(\frac{3}{4}x+\frac{1}{2}=0\)
=>\(\frac{3}{4}x=-\frac{1}{2}\Rightarrow x=-\frac{2}{3}\)
Vậy \(x=\frac{3}{2}\) hoặc \(x=-\frac{2}{3}\)
\(x:\dfrac{4}{7}=\dfrac{6}{7}-\dfrac{1}{3}\\ \Rightarrow x:\dfrac{4}{7}=\dfrac{18}{21}-\dfrac{7}{21}\\ \Rightarrow x:\dfrac{4}{7}=\dfrac{11}{21}\\ \Rightarrow x=\dfrac{11}{21}\times\dfrac{4}{7}\\ \Rightarrow x=\dfrac{44}{147}\)
\(x\div\dfrac{4}{7}=\dfrac{6}{7}-\dfrac{1}{3}\)
\(x\div\dfrac{4}{7}=\dfrac{11}{21}\)
\(x=\dfrac{11}{21}\times\dfrac{4}{7}\)
\(x=\dfrac{44}{147}\)