tìm x \(\frac{44}{ }\frac{:}{60}\frac{x}{ }\)= 1 phần 3
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HP
30 tháng 9 2016
- đặt \(\sqrt{X+1}\)=t →x+1=t2→x=t2-1 →\(1+\sqrt{1+x}\)=t+1 →2+\(\frac{x}{1+\sqrt{ }1+x}\)=t-1 .........cmttu nha t-1=44→t=45→x=2024................rồi nha
25 tháng 3 2018
\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)
\(\Leftrightarrow\left(\frac{x-2}{27}-1\right)+\left(\frac{x-3}{26}-1\right)+\left(\frac{x-4}{25}-1\right)+\left(\frac{x-5}{24}-1\right)\)\(+\left(\frac{x-44}{5}+3\right)=1-1\)
\(\Leftrightarrow\frac{x-29}{27}+\frac{x-29}{26}+\frac{x-29}{25}+\frac{x-29}{24}\)\(+\frac{x-29}{5}=0\)
\(\Leftrightarrow\left(x-29\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\right)=0\)
Mà \(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\ne0\)
=> x - 29 = 0
=> x = 29.
LD
5
LD
2
XO
22 tháng 7 2019
\(\frac{1}{5^x}.\frac{1}{5^8}.\frac{1}{25^3}=\frac{1}{5^{60}}\)
=> \(\frac{1}{5^x.5^8.25^3}=\frac{1}{5^{60}}\)
=> \(\frac{1}{5^x.5^8.\left(5^2\right)^3}=\frac{1}{5^{60}}\)
=> \(\frac{1}{5^x.5^8.5^{2.3}}=\frac{1}{5^{60}}\)
=> \(\frac{1}{5^x.5^8.5^6}=\frac{1}{5^{60}}\)
=> \(\frac{1}{5^{x+8+6}}=\frac{1}{5^{60}}\)
=> \(\frac{1}{5^{x+14}}=\frac{1}{5^{60}}\)
=> \(x+14=60\)
=> \(x=46\)
22 tháng 7 2019
1 . 1 . 1 = 1
5^x 5^8 25^3 5^60
<=> 1 . 1 . 1 = 1
5^x 5^8 5^6 5^60
<=> 1.1.1 = 1
5^x . 5^8 . 5^6 5^60
<=> 1 = 1
5^x+14 5^60
<=> x+14 =60
<=> x = 60-14
=> x = 46
DL
6 tháng 5 2018
pt \(\Leftrightarrow\left(\frac{x-2}{27}-1\right)+\left(\frac{x-3}{26}-1\right)+\left(\frac{x-4}{25}-1\right)+\left(\frac{x-5}{24}-1\right)+\left(\frac{x-44}{5}+3\right)=0\)
\(\Leftrightarrow\frac{x-29}{27}+\frac{x-29}{26}+\frac{x-29}{25}+\frac{x-29}{24}+\frac{x-29}{5}=0\)
\(\Leftrightarrow\left(x-29\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\right)=0\)
Mà \(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\ne0\)
\(\Rightarrow x-29=0\Leftrightarrow x=29\)
6 tháng 3 2016
Ta có:
\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)=\left(-4\right)+1+1+1+1\)
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)
\(\Rightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)
Mà \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\ne0\)
\(\Rightarrow x+329=0\)
\(\Rightarrow x=-329\)
44/60 : 1/3
11/5