GIÚP MÌNH BÀI NÀY NHA CÁC BẠN !!!
Tính tổng M = \(\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)
Nhanh nha các bạn !!!
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(S=3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}\)=> \(2S=6+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^8}\)
=>\(2S-S=\left(6+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^8}\right)-\left(3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^9}\right)\)
=>\(S=3+\frac{3}{2}-\frac{3}{2^9}\) tự tính nốt
\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)
\(M=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)
\(M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{14}\right)+\frac{10}{3}.\left(\frac{1}{14}-\frac{1}{20}\right)+\frac{10}{3}.\left(\frac{1}{20}-\frac{1}{26}\right)+\frac{10}{3}.\left(\frac{1}{26}-\frac{1}{32}\right)\)
\(M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)
\(M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{32}\right)\)
\(M=\frac{10}{3}.\frac{3}{32}\)
\(M=\frac{5}{16}\)
M =20/8.14 +20/14.20 +20/20.26 +20/26.32
M= 20/6 .(1/8-1/14 +1/14-......+1/26-1/32)
M = 20/6 .(1/8 -1/32)
M=20/6 .3/32
M=5 /16
M = \(\frac{5}{16}\)
Ai thấy mk làm đúng nhớ li-ke nha! Thanks!!! Chúc các bạn học tốt nhé! Kì thi cuối học kì 2 cũng đã tới, em xin chúc các anh chị Trung học, chị chúc các em Tiểu học và mình cũng chúc các bạn thi đạt điểm cao nhé! (Đặc biệt các bạn lớp 5 nhớ thi được điểm cao để vào lớp chọn nha!)
Ta có:
\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)
\(\Rightarrow M=20\left(\frac{1}{8.14}+\frac{1}{14.20}+\frac{1}{20.26}+\frac{1}{26.32}\right)\)
\(\Rightarrow M=\frac{20}{6}\left(\frac{6}{8.14}+\frac{6}{14.20}+\frac{6}{20.26}+\frac{6}{26.32}\right)\)
\(\Rightarrow M=\frac{10}{3}\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)
\(\Rightarrow M=\frac{10}{3}.\left(\frac{1}{8}-\frac{1}{32}\right)\)
\(\Leftrightarrow M=\frac{10}{3}.\frac{3}{32}=\frac{5}{16}\)
Vậy \(M=\frac{5}{16}\)
\(M=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)
\(M=\frac{20}{6}\left(\frac{6}{8.14}+\frac{6}{14.20}+\frac{6}{20.26}+\frac{6}{26.32}\right)\)
\(M=\frac{20}{6}\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)
\(M=\frac{20}{6}\left(\frac{1}{8}-\frac{1}{32}\right)\)
\(M=\frac{20}{6}.\frac{3}{32}\)
\(M=\frac{5}{16}\)
k nha
\(M=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+\frac{5}{208}\)
\(M=\frac{5}{3}\cdot\left(\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+\frac{3}{13\cdot16}\right)\)
\(M=\frac{5}{3}\cdot\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}...\frac{1}{13}-\frac{1}{16}\right)\)
\(M=\frac{5}{3}\cdot\left(\frac{1}{4}-\frac{1}{16}\right)\)
\(M=\frac{5}{3}\cdot\frac{3}{16}\)
\(M=\frac{5}{16}\)
\(M=\frac{15}{56}+\frac{1}{14}+\frac{1}{26}+\frac{5}{208}\)
\(M=\frac{15}{56}+\frac{4}{56}+\frac{8}{208}+\frac{5}{208}\)
\(M=\frac{19}{56}+\frac{13}{208}=\frac{45}{112}\)
Câu Q có Ước chung lớn nhất là 1680
<=> Q = 378/1680 - 308/1680 - 260/1680 - 225/1680
Q= (378-308-260-255)/1680
Q= -445/1680
Q=-89/336
\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)
\(M=\frac{20}{8.14}+\frac{20}{14.20}+\frac{20}{20.26}+\frac{20}{26.32}\)
\(M=\frac{20}{6}.\left(\frac{6}{8.14}+\frac{6}{14.20}+\frac{6}{20.26}+\frac{6}{26.32}\right)\)
\(M=\frac{20}{6}.\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)
\(M=\frac{20}{6}.\left(\frac{1}{8}-\frac{1}{32}\right)\)
\(M=\frac{20}{6}.\frac{3}{32}\)
\(M=\frac{5}{16}\)
\(M=\frac{20}{112}+\frac{20}{280}+\frac{20}{520}+\frac{20}{832}\)
\(\Rightarrow\frac{1}{M}=\frac{112}{20}+\frac{280}{20}+\frac{520}{20}+\frac{832}{20}\)
\(\Rightarrow\frac{1}{M}=\frac{1744}{20}=\frac{436}{5}\)
\(\Rightarrow M=\frac{5}{436}\)
\(\frac{20}{8\cdot14}+\frac{20}{14\cdot20}+\frac{20}{20\cdot26}+\frac{20}{26\cdot32}\)\(\Rightarrow\frac{10}{3}\left(\frac{6}{8\cdot14}+\frac{6}{14\cdot20}+\frac{6}{20\cdot26}+\frac{6}{26+32}\right)\)
\(M=\frac{10}{3}\left(\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\)\(\Rightarrow M=\frac{10}{3}\left(\frac{1}{8}-\frac{1}{32}\right)=\frac{10}{3}\cdot\frac{3}{32}=\frac{10}{32}\)
k cho mình nha!