Bài 1
a.7/6-3/4=
b.21/18-10/9=
c.35/28-48/64=
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a)=-50
b)=-33
c)=13
d)=46
e)=-33
f)=-54
g)=29
h)=-11
i)=-120
k)=-196
l)=-108
m)=100
a)=-50
b)=-33
c)=13
d)=46
e)=-33
f)=-54
g)=29
h)=-11
i)=-120
k)=-196
l)=-108
m)=100
\(\dfrac{4}{7}-\dfrac{1}{3}< \dfrac{1}{2}-\dfrac{2}{9}\)
\(\dfrac{125}{100}-\dfrac{48}{64}< \dfrac{6}{7}-\dfrac{14}{28}\)
\(\dfrac{7}{5}-\dfrac{22}{25}=\dfrac{1}{5}+\dfrac{4}{10}\)\(\dfrac{45}{75}+\dfrac{22}{33}>\dfrac{4}{5}+\dfrac{4}{6}\)
a; \(\dfrac{9}{4}\) - \(\dfrac{-11}{4}\)
= \(\dfrac{9}{4}\) + \(\dfrac{11}{4}\)
= \(\dfrac{20}{4}\)
= 5
b; \(\dfrac{7}{8}\) - \(\dfrac{3}{-8}\) - \(\dfrac{1}{8}\)
= \(\dfrac{7}{8}\) + \(\dfrac{3}{8}\) - \(\dfrac{1}{8}\)
= \(\dfrac{7+3-1}{8}\)
= \(\dfrac{9}{8}\)
c; \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) - \(\dfrac{-1}{21}\)
= \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) + \(\dfrac{1}{21}\)
= \(\dfrac{-5-25+1}{21}\)
= \(\dfrac{-29}{21}\)
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50=1275
\(\dfrac{7}{15}+\dfrac{4}{5}\)
\(=\dfrac{7}{15}+\dfrac{12}{15}\)
\(=\dfrac{19}{15}\)
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\(\dfrac{35}{28}-\dfrac{48}{64}\)
\(=\dfrac{2240}{1792}-\dfrac{1344}{1792}\)
\(=\dfrac{896}{1792}=\dfrac{1}{2}\)
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\(\dfrac{10}{13}:\dfrac{3}{4}\)
\(=\dfrac{10}{13}\)x\(\dfrac{4}{3}\)
\(=\dfrac{40}{39}\)
b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16
= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8
= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)
= 1 + 1 + 7/4
= 2 + 7/4 = 15/4
c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16
= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2
= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2
= 14/7 + 12/6 + 5/8 + 1/2
= 2 + 2 + 5/8 + 1/2
= 4 + 9/8 = 41/8
mk kím ny k9 trở lên là nam , mk là Linh k10 ạ
\(a,\frac{7}{6}-\frac{3}{4}=\frac{14}{12}-\frac{9}{12}=\frac{5}{12}\)
\(b,\frac{21}{18}-\frac{10}{9}=\frac{21}{18}-\frac{20}{18}=\frac{1}{18}\)
\(c,\frac{35}{28}-\frac{48}{64}=\frac{5}{4}-\frac{3}{4}=\frac{2}{4}=\frac{1}{2}\)
\(HT\)