Tìm x , biết :
a) -0,6 .x -7/3 =5.4
b) 2.8 :(1/5-3.x)=1 2/5
c) /x+1/2/=1/6
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b: \(x+\dfrac{5}{6}=\dfrac{3}{8}\)
=>\(x=\dfrac{3}{8}-\dfrac{5}{6}\)
=>\(x=\dfrac{9}{24}-\dfrac{20}{24}=-\dfrac{11}{24}\)
c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{5}{6}\)
=>\(\dfrac{2}{3}x=\dfrac{5}{6}+\dfrac{1}{2}=\dfrac{8}{6}=\dfrac{4}{3}\)
=>2x=4
=>x=4/2=2
d: \(\dfrac{x}{7}=\dfrac{6}{-21}\)
=>\(\dfrac{x}{7}=\dfrac{-2}{7}\)
=>x=-2
e: \(\left(\dfrac{7}{3}x-0,6\right):\dfrac{3^2}{5}=1\)
=>\(\dfrac{7}{3}x-0,6=\dfrac{3^2}{5}=1,8\)
=>\(\dfrac{7}{3}x=2,4\)
=>\(x=2,4:\dfrac{7}{3}=2.4\cdot\dfrac{3}{7}=\dfrac{7.2}{7}=\dfrac{36}{35}\)
f: \(\dfrac{x}{45}=\dfrac{5}{6}+\dfrac{-29}{30}\)
=>\(\dfrac{x}{45}=\dfrac{25}{30}-\dfrac{29}{30}=-\dfrac{4}{30}=-\dfrac{2}{15}\)
=>\(x=-\dfrac{2}{15}\cdot45=-6\)
g: \(\left(4,5-2x\right)\cdot\left(-\dfrac{1^4}{7}\right)=\dfrac{11}{14}\)
=>\(4,5-2x=\dfrac{11}{14}:\dfrac{-1}{7}=\dfrac{-11}{2}\)
=>\(2x=4,5+\dfrac{11}{2}=\dfrac{20}{2}=10\)
=>x=10/2=5
h: \(-\dfrac{2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\)
=>\(\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}\)
=>4x=7
=>\(x=\dfrac{7}{4}\)
a) \(2\frac{1}{2}-\left(q-\frac{1}{2}\right)=\frac{3}{5}\)
\(\Rightarrow q-\frac{1}{2}=2\frac{1}{2}-\frac{3}{5}=\frac{19}{10}\)
\(\Rightarrow q=\frac{19}{10}+\frac{1}{2}=\frac{12}{5}=2,4\)
\(\Rightarrow q=2,4\)
b) \(\frac{1}{3}\cdot q-\frac{1}{5}\cdot q=0,6\)
\(=q\cdot\left(\frac{1}{3}-\frac{1}{5}\right)=0,6\)
\(=q\cdot\frac{2}{15}=0,6\)
\(\Rightarrow q=0,6:\frac{2}{15}=\frac{9}{2}=4,5\)
\(\Rightarrow q=4,5\)
c) \(\frac{3}{5}-q:\frac{1}{2}=\frac{1}{7}\)
\(\Rightarrow q:\frac{1}{2}=\frac{3}{5}-\frac{1}{7}=\frac{16}{35}\)
\(\Rightarrow q=\frac{16}{35}\cdot\frac{1}{2}=\frac{8}{35}\)
\(\Rightarrow q=\frac{5}{35}\)
Ở câu b áp dụng phân phối giữa phép nhân vs phép trừ.
a) \(\left(2x-1\right)+\frac{3}{15}=\frac{3}{2}\)
\(\Rightarrow2x-1=\frac{3}{2}-\frac{3}{15}=\frac{13}{10}\)
\(\Rightarrow2x=\frac{13}{10}+1=\frac{23}{10}\)
\(\Rightarrow x=\frac{23}{20}\)
b) \(x+\frac{46}{15}=1,5\)
\(\Rightarrow x+\frac{46}{15}=\frac{3}{2}\)
\(\Rightarrow x=\frac{3}{2}-\frac{46}{15}\)
\(\Rightarrow x=\frac{-47}{30}\)
c) \(\left(-2x+1\right)+\frac{3}{15}=\frac{5}{3}\)
\(\Rightarrow-2x+1=\frac{5}{3}-\frac{3}{15}=\frac{22}{15}\)
\(\Rightarrow-2x=\frac{7}{15}\Rightarrow x=\frac{-7}{30}\)
Câu 5 nữa bạn cố gắng làm giúp mik nha ko thì mình 0 điểm á, nha iu nhìu lém
2,8 : ( \(\frac{1}{5}-3x\)) = \(\frac{7}{5}\)
\(\frac{1}{5}-3x=2,8:\frac{7}{5}\)
\(\frac{1}{5}-3x=2\)
\(3x=\frac{1}{5}-2\)
\(3x=\frac{1}{5}-\frac{10}{5}\)
\(3x=\frac{-9}{5}\)
\(x=\frac{-3}{5}\)
Vậy \(x=\frac{-3}{5}\)
2,8 : (1/5 - 3x) = 7.5
=> 1/5 - 3x = 2,8 : 7/5 = 14/5 . 5/7 ( áp dụng a:b=c thì b=a:c ấy )
=> 1/5 - 3x=2
=> 3x= 1/5 - 2= -9/5 ( áp dụng a-b=c thì b= a-c nha )
=> x= -9/5 : 3 = -9/5 . 1/3 = -3/5
1, Thực hiện phép tính
a, (-23).(-3).(+4).(-7)
=69.(-28)
=(-1932)
b, 2.8.(-14).(-3)
=16.42
=672
2, Tìm x
a, 2436 : x = 12 b, 6. x - 5 = 613
x =2436 : 12 6. x = 613 + 5 = 618
x = 203 x =618 : 6 = 103
c, 12. (x - 1) = 0 d, 0 : x = 0
x - 1 = 12 : 0 = 0 x = 0 : 0
x = 0 + 1 = 1 x = 0
1.
a) \(\left(-23\right).\left(-3\right).4.\left(-7\right)=[\left(-23\right).\left(-3\right).\left(-7\right)].4\)
\(=-483.4=-1932\)
b) \(=16.42=672\)
2.
a) \(\Rightarrow x=2436\div12=203\)
b) \(\Rightarrow6x=618\Rightarrow x=103\)
c) \(\Rightarrow x-1=0\Rightarrow x=1\)
d) Ko có gtr nào của x thỏa mãn 0:x=0
~ HỌC TỐT ~
# Q.TRANG #
-3/5x = 27/5 + 7/3
-3/5x= 116/15