bài 1 Tính bằng cách thuận tiện nhất
a) ( 12+ 14+ 16+18 + …+ 66+ 68) x( a : 1 – a x1)
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a) 52 x 2 + 48 x 2
= (52 + 48) x 2
= 100 x 2
= 200
b) 10 + 12 + 14 + 16 + 18 + 20
= (12 + 18) + (14 + 16) + (20 + 10)
= 30 + 30 + 30
= 90
a) 16 x 8 + 12 x 6
= 4 x 4 x 8 + 4 x 3 x 6
= 4 x 32 + 4 x 18
= 4 x ( 32 + 18 )
= 4 x 50
= 200
b) 16 x 7 + 14 x 2
= 8 x 2 x 7 + 14 x 2
= 8 x 14 + 14 x 2
= ( 8 + 2 ) x 14
= 10 x 14
= 140
c) 8 x 12 - 96
= 8 x 12 - 12 x 8
= 0
a / 16 x 8 + 12 x 6
= ( 8 x 2 ) x ( 8 x 1 ) + ( 6 x 2 ) x ( 6x1 )
= 8 x ( 2 x 1 ) + 6 x ( 2 x 1 )
= 8 x 2 + 6 x 2
= 2 x ( 8 + 6 )
= 2 x 14
= 28
b / 16 x 7 + 14 x 2
= 16 x 7 + ( 7 x 2 ) x2
= 16 x 7 + 7 x 2 x 2
= 7 x ( 16 + 2 ) x 2
= 7 x 18 x2
= 7 x ( 6 x 3 ) x2
= 7 x6 x3 x2
= 7 x 6 x ( 3 x 2 )
= 7 x 6 x6
= ( 7 x 6 ) x ( 6 x 1 )
= 6 x ( 7 x 1 )
= 6 x 7
= 42
c / 8 x 12 - 96
= ( 8 x 12 ) - 96
= 96 - 96
= 0
tớ k chắc cho lắm
a) 12 + 13 + 14 + 15 + 16 + 17+ 18
= (12 + 18) + ( 13 + 17) + (14 + 16) + 15
= 30 + 30 + 30 + 15
= 105
(20+10)-(11+19)+(12+18)-(13+17)+(14+16)-15
=30-30+30-30-15+30
=15
10-11+12-13+14-15+16-17+18-19+20
= (10+20)+(-11-19)+(12+18)+(-13-17)+(14+16)-15
= 30-30+30-30+30-15
= 15
b; \(\dfrac{5}{14}\) \(\times\) \(\dfrac{7}{13}\) x \(\dfrac{26}{25}\)
= \(\dfrac{5\times7\times2\times13}{7\times2\times13\times5\times5}\)
= \(\dfrac{5\times7\times2\times13}{5\times7\times2\times13}\) x \(\dfrac{1}{5}\)
= 1 x \(\dfrac{1}{5}\)
= \(\dfrac{1}{5}\)
=9/4x2/3+16/9x4/3
=18/12+64/36
=54/36+64/36=118/36=59/18
\(\frac{1}{2}\cdot\frac{18}{14}+\frac{1}{2}\cdot\frac{3}{14}-\frac{1}{2}\cdot\frac{7}{14}\)
\(=\frac{1}{2}\left(\frac{18}{14}+\frac{3}{14}-\frac{7}{14}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)
( 12 + 14 + 16 + 18 + ... + 66 + 68 ) x ( a : 1 - a x 1 )
= ( 12 + 14 + 16 + 18 + ... + 66 + 68 ) x ( a - a )
= ( 12 + 14 + 16 + 18 + ... + 66 + 68 ) x 0
= 0