34+66-55+115-150x10:5+850=????
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Ta có :
\(\xrightarrow[34^{18}>32^{18}=\left(2^5\right)^{18}=290]{63^{15}< 64^{15}=\left(2^6\right)^{15}=2^{90}}\Rightarrow63^{15}< 54^{18}\)
a)
Ta có:
\(63^{15}< 64^{15}\Rightarrow63^{15}< \left(2^5\right)^{15}\Rightarrow63^{15}< 2^{90}\)
\(34^{18}>32^{18}\Rightarrow34^{18}>\left(2^5\right)^{18}\Rightarrow34^{18}>2^{90}\)
\(\Leftrightarrow34^{18}>63^{15}\)
b)
\(55^{66}=\left(55^6\right)^{11}=330^{11}\)
\(66^{55}=\left(66^5\right)^{11}=330^{11}\)
\(\Leftrightarrow55^{66}=66^{55}\)
-5-9-11-24
=-14-11-24
=-25-24
=-49
-14-7-12-24
=-21-12-24
=-33-24
=-57
12+38-30-22
=50-30-22
=20-22
=-2
34+(-43)+66-55
=-9+66-55
=57-55
=2
-10-14-16+43
=-24-16+43
=-40+43
=3
4
1
62
31
321
3132132
3145461320...................22222222222222222222222223130
2222222222222222222222222222222222226
30.
3062+958*+96
33
.36+9.03693
.36363.
(45+75)*66+(75+45)*34
=(45+75)*(66+34)
=120*100
=12000
11+22+33+44+55+66+77+88+99:11
=11+22+33+44+55+66+77+88+9
=(11+9)+(22+88)+(33+77)+(44+66)+55
=20+110*3+55
=20+330+55
=405
Ta có :
a, (45 + 75) x 66 + (75 + 45) x 34
= (45 + 75) x (66 + 34)
= 120 x 100
= 12000
11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99 : 11
= 33 + 77 + 121 + 165 + 9
= 405
\(=\left[66+34+77+23+12+88+45+55\right]\times\left[1808\times\left(25-25\right)\right]\\ =0\)
42 + 43 + 44 + 45 - 32 - 33 - 34 - 35
= (42 - 32)+(43 - 33)+(44 - 34)+(45 - 35)
= 10+10+10+10
= 40
(64+65+66+67+68) - (54+55+56+57+58)
= 64+65+66+67+68 - 54-55-56-57-58
= (64 - 54)+(65 - 55) +(66 - 56) + (67- 57) + (68 -58)
= 10+10+10+10+10
= 50
(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)
=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200-45200)
=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0
=0
34 . ( 66 - 5 ) - 66 . ( 34 + 5 )
= 34 . 61 - 66 . 39
= 2074 - 2574
= - 500
Ta có 34.(66 - 5) - 66.(34 + 5)
= 34.66 - 34.5 - 66.34 - 66.5
= -5.(34 + 66)
= - 5.100 = - 500
34(66-5)-66(34+5)=34.66-34.5-34.66-66.5=(34.66-34.66)-5(34+66)=-500
710 nhân chia trước cộng trừ sau
34 + 66 -55 + 115 - 300+850 = 710
= 710
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