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Giải toán 6 bài Ôn tập chương 2 | Giải bài tập Toán lớp 6 hay nhất tại VietJack
1 It isn't a pen
2 Nam and Ba aren't fine
3 They aren't twenty
4 Are you Thu?
5 Are you eighteen?
6 Is she Lan
Bài 2
1 What is your name/
2 I am Lan
3 Is this phong?
4 How are you today?
5 We are fine, thank you
6 I am Lan and this is Hoa
7 Hello, I am Ann
8 This is my mom her name is Mai
9 They are 18 years old
10 He is not fine today
Rewrite sentences without changing the meaning
Question 11: I find cooking in my free time relaxing.
A. It’s relaxing to me to cook in my free time.
B. Cooking is relaxing for free time.
C. Free time relaxing is cooking.
D. I spend cooking my free time.
Question 12: I close friend gave me a wonderful present on my birthday
A. I gave my friend a wonderful present on my birthday.
B. I was given a wonderful present on my birthday.
C. A wonderful present was given me on my birthday.
D. My birthday gave a wonderful present.
Question 13: Skateboarding is her hobby.
A. She doesn’t like skateboarding.
B. Skateboarding is fun.
C. Hobby includes skateboarding.
D. Her favourite leisure activity is skateboarding.
Question 14: He likes to listen to pop music than to watch TV after school.
A. He prefers listening to pop music to watching TV after school.
B. He like watching TV more than listening to music after school.
C. Listening to pop music is more exciting than watching TV.
D. Watching TV is less interesting than listening to pop music.
Question 15: My parents insist me on learning Spanish.
A. My parents want me to study Spanish.
B. My parents teach me to study Spanish.
C. My parents make me to study Spanish.
D. My parents remind me to study Spanish.
\(a.A=\left(\dfrac{x}{x^2-4}+\dfrac{1}{x+2}-\dfrac{2}{x-2}\right):\left(1-\dfrac{x}{x+2}\right)\left(đk:x\ne\pm2\right)\)
\(=\left[\dfrac{x}{x^2-4}+\dfrac{x-2}{x^2-4}-\dfrac{2\left(x+2\right)}{x^2-4}\right]:\left(\dfrac{x+2}{x+2}-\dfrac{x}{x+2}\right)\)
\(=\dfrac{x+x-2-2x-4}{x^2-4}:\dfrac{x+2-x}{x+2}\)
\(=\dfrac{-6}{\left(x+2\right)\left(x-2\right)}.\dfrac{x+2}{2}\)
\(=\dfrac{-3}{x-2}\left(1\right)\)
\(b.\) Thay x = 2023 vào (1), ta được:
\(\dfrac{-3}{2023-2}=-\dfrac{3}{2021}\)
\(c.\) Để A là một số nguyên thì \(x-2\inƯ_{\left(-3\right)}\)
Vậy x - 2 có các giá trị sau:
\(\left[{}\begin{matrix}x-2=1\\x-2=-1\\x-2=3\\x-2=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\\x=5\\x=-1\end{matrix}\right.\)