giúp mình với ạ!!! (mình quên cái đề mất rồi)
1/1*6+1/6*11+1/6*16+...+1/51*56.
Mình cần gấp lắm ạ!!!
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\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
\(\left(6:3,5-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\\ =\left(\dfrac{12}{7}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\\ =\left(\dfrac{17}{7}-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)\\ =\dfrac{10}{7}:9\\ =\dfrac{10}{63}\)
\(\left(6:\dfrac{3}{5}-1\dfrac{1}{6}\times\dfrac{6}{7}\right):\left(4,2\times\dfrac{10}{11}+5\dfrac{2}{11}\right)\)
\(=\left(6\times\dfrac{5}{3}-\dfrac{7}{6}\times\dfrac{6}{7}\right):\left(\dfrac{21}{5}\times\dfrac{10}{11}+\dfrac{57}{11}\right)\)
\(=\left(10-1\right):\left(\dfrac{42}{11}+\dfrac{57}{11}\right)=9:9=1\)
a, \(\dfrac{1}{2}\) - ( - \(\dfrac{1}{3}\) ) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= \(\dfrac{5}{6}\) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= 1 + \(\dfrac{1}{23}\)
= \(\dfrac{24}{23}\)
b, \(\dfrac{11}{24}\) - \(\dfrac{5}{41}\) + \(\dfrac{13}{24}\) + 0,5 - \(\dfrac{36}{41}\)
= (\(\dfrac{11}{24}\) + \(\dfrac{13}{24}\)) - ( \(\dfrac{5}{41}\) + \(\dfrac{36}{41}\)) + 0,5
= 1 - 1 + 0,5
= 0,5
c,\(-\dfrac{1}{12}-\left(\dfrac{1}{6}-\dfrac{1}{4}\right)\)
=\(-\dfrac{1}{12}-\left(-\dfrac{1}{12}\right)\)
=0
d, \(\dfrac{1}{6}-\left[\dfrac{1}{6}-\left(\dfrac{1}{4}+\dfrac{9}{12}\right)\right]\)
= \(\dfrac{1}{6}-\left[\dfrac{1}{6}-1\right]\)
= \(\dfrac{1}{6}-\left(-\dfrac{5}{6}\right)\)
= 1
TL
S= ( 1+ 3+ 3^2+ 3^3+ 3^4+ 3^5+ 3^6+ 3^7+ 3^8+ 3^9)
3.S=3.( 1+ 3+ 3^2+ 3^3+ 3^4+ 3^5+ 3^6+ 3^7+ 3^8+ 3^9)
3S=3+3^2+3^3+....+3^10
3S-S=3+3^2+3^3+....+3^10-(1+ 3+ 3^2+ 3^3+ 3^4+ 3^5+ 3^6+ 3^7+ 3^8+ 3^9)
2S=3^10-1
S=3^10-1/2
HỌC TỐT NHÉ
đặt A = 2/2 + 2/6 + 2/12 + .... + 2/ x(x+1)
A = 2 . ( 1/2 + 1/6 + 1/12 + ...+ 1/x(x+1) )
A = 2 . ( 1/ 1.2 + 1/2.3 + .......+ 1/ x(x+1) )
A = 2 . ( 1 - 1/2 + 1/2 - 1/3 + ....+ 1/x - 1/x+1 )
A = 2 . ( 1 - 1/x+1) = 2 . x / x+1 = 2x/ x+1
thay A vào đề bài ta có
2x/x+1 = 8/5 => 2x . 5 = 8 . (x+1)
<=> 10x = 8x+8
<=> 10x -8x = 8 => 2x = 8 => x=4
vậy x = 4 ( cách làm là vậy đó ko biết có đúng ko, ủng hộ mik nha)
Link nè: https://dethi.violet.vn/present/show/entry_id/11006794\
Chúc bạn hoc tốt ~ !
ta có: 1/1*6+1/6*11+1/6*16+...+1/51*56.
=1/5.(5/1.6+5/6.11+5/6.16+...+5/51.56)
=1/5.(1/1-1/6+1/6-...-1/56)
=1/5.(1-1/56)
=1/5.(55/56)
=11/56
11/56