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a ( 1+2+3+4+....+99)*(13*15-12*25-15)
= ( 1+2+3+4+....+99)*[15*(13-1)-12*25)]
=( 1+2+3+4+....+99)*[15*12-12*25]
=( 1+2+3+4+....+99)*[12*(15-25)]
=( 1+2+3+4+....+99)*[12*(-10)]
=( 1+2+3+4+....+99)*(-120)
= -594000
b 3*5*36+15+42+30*11
=15*36+15*1+42+15*22
=15*(36+1+22)+42
=15*59+42
=885+42
=927
Tick cho mk nha
a. ( 1+2+3+4+....+99)*(13*15-12*25-15)
=( 1+2+3+4+....+99) . 0
=0
b 3*5*36+15+42+30*11
=540 + 15 +42 + 330
=927
a) 12 + 13 + 14 + 15 + 16 + 17+ 18
= (12 + 18) + ( 13 + 17) + (14 + 16) + 15
= 30 + 30 + 30 + 15
= 105
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19
=(1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+10
=20+20+20+20+20+20+20+20+20+10
=20*9+10
=180+10=190
1+2+3+4+5+6+7+8+9+10+11+12+13 +14 +15+16+17+18+19
= 19 - 1( tức là trừ đi số 10 vì nó tròn chục )
= 18 : 2
= 9 x ( 19 + 1 ) + 10
= 9 x 20 + 10
= 180 + 10
= 190
$#Shả$
`A)=5/17xx(15/34+19/34)`
`=5/17xx1=5/17`
`B)=(13/12+7/12)+1/3`
`=5/3+1/3=2`
\(\frac{14}{9}:\frac{13}{12}+\frac{4}{3}:\frac{13}{12}\)
\(=\frac{14}{9}\cdot\frac{12}{13}+\frac{4}{3}\cdot\frac{12}{13}\)
\(=\left(\frac{14}{9}+\frac{4}{3}\right)\cdot\frac{12}{13}\)
\(=\frac{26}{9}\cdot\frac{12}{13}=\frac{8}{3}\)
( 6 x 8 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= (48 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0 : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0
(20+10)-(11+19)+(12+18)-(13+17)+(14+16)-15
=30-30+30-30-15+30
=15
10-11+12-13+14-15+16-17+18-19+20
= (10+20)+(-11-19)+(12+18)+(-13-17)+(14+16)-15
= 30-30+30-30+30-15
= 15
a. ( 6 x 8 – 48 ) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= (48 – 48) : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0 : ( 10 + 11 + 12 + 13 + 14 + 15 )
= 0
\(\frac{15}{13}+\frac{1}{13}+\frac{12}{13}\) = \(\frac{15+1+12}{13}\) = \(\frac{28}{13}\)
15+1+12/13
=28/13