Question

[Ling ling 2k7]

Hộ bài 3 hoặc 5, bài 5 thì càng tốt

Answer 1

[Nguyễn Lê Phước Thịnh]

Bài 5: 

a) Ta có: \(P=\left(\dfrac{1}{x-1}-\dfrac{1}{x}\right):\left(\dfrac{x+1}{x-2}-\dfrac{x+2}{x-1}\right)\)

\(=\left(\dfrac{x}{x\left(x-1\right)}-\dfrac{x-1}{x\left(x-1\right)}\right):\left(\dfrac{\left(x+1\right)\left(x-1\right)}{\left(x-2\right)\left(x-1\right)}-\dfrac{\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x-1\right)}\right)\)

\(=\dfrac{x-x+1}{x\left(x-1\right)}:\dfrac{x^2-1-\left(x^2-4\right)}{\left(x-2\right)\left(x-1\right)}\)

\(=\dfrac{1}{x\left(x-1\right)}:\dfrac{x^2-1-x^2+4}{\left(x-2\right)\left(x-1\right)}\)

\(=\dfrac{1}{x\left(x-1\right)}\cdot\dfrac{\left(x-2\right)\left(x-1\right)}{3}\)

\(=\dfrac{x-2}{3x}\)

Answer 2

[Ling ling 2k7]

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