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\(\frac{x}{-\frac{3}{5}}=\frac{-10}{21}\)
\(\Leftrightarrow21x=-10\cdot\frac{-3}{5}\)
\(\Leftrightarrow21x=6\Leftrightarrow x=\frac{2}{7}\)
\(\frac{x}{\frac{41}{3}}=-25\)
\(\Leftrightarrow x=-25\cdot\frac{41}{3}=\frac{-1025}{3}\)
3.Đề sao thế nhỉ???
\(a,\dfrac{6}{5}=\dfrac{18}{x}\\ \Rightarrow x=18:\dfrac{6}{5}\\ \Rightarrow x=15\\ b,\dfrac{3}{4}=\dfrac{-21}{x}\\ \Rightarrow x=-21:\dfrac{3}{4}\\ \Rightarrow x=-28\\ c,\dfrac{2}{-7}=\dfrac{18}{x}\\ \Rightarrow x=18:\dfrac{2}{-7}\\ \Rightarrow x=-63\\ d,\dfrac{-5}{2}=\dfrac{10}{-x}\\ \Rightarrow x=-10:\dfrac{-5}{2}\\ \Rightarrow x=4\)
\(a,\dfrac{6}{5}=\dfrac{18}{x}\Rightarrow6.x=5.18=90\\ \Rightarrow6.x=90\\ \Rightarrow x=15\\ b,\dfrac{3}{4}=\dfrac{-21}{x}\Rightarrow3.x=4.21=84\\ \Rightarrow x=28\)
a)x-5/7=-2/3+1/3
x-5/7=-1/3
x=-1/3+5/7
x=8/21
b)1/3x+5/7=-9/4
x+5/7=-9/4:1/3
x+5/7=-27/4
x=-27/4-5/7
x=-209/28
a: x-5/7=-2/3+1/3
=>x-5/7=-1/3
=>x=-1/3+5/7=8/21
b: 1/3*x+5/7=-9/4
=>x*1/3=-9/4-5/7=-83/28
=>x=-83/28:1/3=-83/28*3=-249/28
c: 1/6x:1/4=-1/24
=>1/6x=-1/96
=>x=-1/16
Sửa đề: Tìm x là số nguyên
a) -27/3 < x < 12/4
⇒ -9 < x < 3
⇒ x ∈ {-8; -7; -6; ...; 1; 2}
b) -28/4 ≤ x ≤ -12/6
⇒ -7 ≤ x ≤ -2
⇒ x ∈{-7; -6; -5; -4; -3; -2}
\(\frac{1}{5x}+\frac{4}{5x}=-10\Rightarrow\frac{1+4}{5x}=-10\)
\(\frac{5}{5x}=10\Rightarrow\frac{1}{x}=10\Rightarrow x=\frac{1}{10}\)
Thế này à :
\(\frac{1}{5}x+\frac{4}{5}x=-10\)
\(x\left(\frac{1}{5}+\frac{4}{5}\right)=-10\)
\(x.1=-10\)
\(=>x=-10:1=-10\)
\(\frac{3}{4}+\frac{-1}{3}+\frac{-5}{18}\)
\(=\frac{5}{12}+\frac{-5}{18}\)
\(=\frac{5}{36}\)
a, Ta có : \(-\dfrac{3}{2}-2x+\dfrac{3}{4}=-2\)
\(\Rightarrow-2x=-2+\dfrac{3}{2}-\dfrac{3}{4}=-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{5}{8}\)
Vậy ...
b, Ta có : \(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)\left(-\dfrac{3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)
\(\Rightarrow-\dfrac{29}{6}\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)=\dfrac{2}{5}\)
\(\Rightarrow-\dfrac{2}{3}x-\dfrac{3}{5}=-\dfrac{12}{145}\)
\(\Rightarrow-\dfrac{2}{3}x=-\dfrac{12}{145}+\dfrac{3}{5}=\dfrac{15}{29}\)
\(\Rightarrow x=-\dfrac{45}{58}\)
Vậy...