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a) (x.7 +8):5=10
x.7 +8= 10.5=50
x.7= 50-8=42
x= 42:7=6
b) 280: (7+3.x)=4
7+3.x= 4.280= 1120
3.x= 1120-7 =1113
x= 1113: 3= 371
c) (x.5) .19:13= 57
(x.5). 19= 57.13= 741
x.5= 741: 19= 39
x= 39:5 =7,8
d) 6.(28-8).x = 72
20.x= 72:6= 12
x= 12: 20= 0,6
e) 4. (36-4.x)= 3,2
36-4.x= 32:4= 0,8
-4.x= 0,8- 36= -35,2
x= -35,2 : -4 = 8,8
f) (x-15).3 :12= 6
(x-15).3 = 6. 12= 72
x-15= 72: 3= 24
x= 24+ 15= 39
g) (x:4+ 6) . 7 = 70
x:4+6= 70:7= 10
x:4= 10-6= 4
x= 4.4 = 16
h) (x:2+50) :5= 12
x:2+ 50= 12.5= 60
x:2= 60-50= 10
x= 10.2=20
l) 5.(7+3.x)= 140
7+3.x= 140:5 = 28
3.x= 28-7 =21
x= 21: 3= 7
k cho mình nhe
\(\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{2}{7}:\frac{3}{5}+\frac{9}{10}\)
\(\frac{2}{3}.\frac{5}{x}=\frac{2}{7}.\frac{5}{3}+\frac{9}{10}-\frac{5}{7}\)
\(\frac{10}{3}:x=\frac{10}{21}+\frac{9}{10}-\frac{5}{7}=\frac{100+189-150}{210}=\frac{139}{210}\)
\(x=\frac{700}{139}\)
Ta có :
\(\left(x-7\right)\left(x+3\right)< 0\)
Trường hợp 1 :
\(\hept{\begin{cases}x-7< 0\\x+3>0\end{cases}\Leftrightarrow\hept{\begin{cases}x< 7\\x>-3\end{cases}\Leftrightarrow}-3< x< 7}\)
Mà \(x\inℤ\) nên \(x\in\left\{-2;-1;0;1;2;3;4;5;6\right\}\)
Trường hợp 2 :
\(\hept{\begin{cases}x-7>0\\x+3< 0\end{cases}\Leftrightarrow\hept{\begin{cases}x>7\\x< -3\end{cases}}}\) ( loại )
Vậy \(x\in\left\{-2;-1;0;1;2;3;4;5;6\right\}\)
Chúc bạn học tốt ~
\(x=\left(\frac{33}{5}:6-0,125\cdot8+\frac{32}{15}\cdot0,03\right)\cdot\frac{11}{4}\)
\(x=\left(\frac{33}{5}\cdot\frac{1}{6}-\frac{1}{8}\cdot8+\frac{32}{15}\cdot\frac{3}{100}\right)\cdot\frac{11}{4}\)
\(x=\left(\frac{11}{10}-1+\frac{8}{125}\right)\cdot\frac{11}{4}\)
\(x=\frac{41}{250}\cdot\frac{11}{4}\)
\(x=\frac{451}{100}\)
\(x=\left(\frac{33}{5}:6-0,125.8+\frac{32}{15}.0,03\right).\frac{11}{4}\)
\(< =>x=\left(\frac{33}{30}-1+\frac{32}{15}.\frac{3}{100}\right).\frac{11}{4}\)
\(< =>x=\left(\frac{3}{30}+\frac{32}{500}\right).\frac{11}{4}\)
\(< =>x=\left(\frac{1}{10}+\frac{8}{125}\right).\frac{11}{4}\)
\(< =>x=\frac{41}{250}.\frac{11}{4}=\frac{451}{100}\)
1. . 7,2 : 2,4 x X = 4,5
3 x X = 4,5
X = 4,5 : 3
X = 1,5
2. X x 4,8 + 5,2 x X = 160
=> X x ( 5,2 + 4,8 ) = 160
X x 10 = 160
X = 160 : 10
X = 16
3. 9,15 x X + 2,85 x X =48
=> ( 9,15 + 2,85 ) x X = 48
12 x X = 48
X = 48 : 12
X = 4
4. ( X x 3 + 4 ) : 5 = 8
X x 3 + 4 = 8x 5
X x 3 + 4 = 40
X x 3 = 40 - 4
X x 3 = 36
X = 36 : 3
X = 12
5. ( 15 x 28 - x ) : 2/5 = 200 : 0,4
15 x 28 - x = 200 : 0,4 x 2/5
15 x 28 - x = 200
15 x 28 = 200 + x
420 = 200 + x
x = 420 - 200
x = 220
6. 7 x ( 8 + 2 x X ) = 210
8 + 2 x X = 210 : 7
8 + 2x = 30
=> 2x = 30 - 8
2x = 22
x= 22 : 2
x = 11
7. X x 5,6 + 4,4 x X = 130
X x ( 5,6 + 4,4 ) = 130
X x 10 = 130
X = 130 : 10
X = 13
8. ( x - 12 ) x 17 : 11 = 51
x - 12 = 51 x 11 : 17
x - 12 = 33
x = 33 + 12
x = 45
9. 9,15 x X + 2,85 x X = 48
X x ( 9,15 + 2,85 ) = 48
X x 10 = 48
X = 48 : 10
X = 4,8
BÀI \(1\):
\(\left(-1005\right).\left(x+2\right)=0\)
\(x+2=0:\left(-1005\right)\)
\(x+2=0\)
\(x=0-2\)
\(x=-2\)
BÀI \(2\):
\(x+x+x+91=-2\)
\(3x=\left(-2\right)-91\)
\(3x=-93\)
\(x=\left(-93\right):3\)
\(x=-31\)
BÀI \(3\):
\(\left|5x+1\right|=11\)
Có hai trường hợp:
\(TH^{ }1:_{ }5x+1=11\)
\(5x=11-1\)
\(5x=10\)
\(x=10:5\)
\(x=2\)
\(TH2:^{ }5x+1=-11\)
\(5x=\left(-11\right)-1\)
\(5x=-12\)
\(x=\left(-12\right):5\)
\(x=-2,4\)
\(k\)\(minh\)\(nhe\)\(.\)
(x-5).(x+7)=0
-> x-5=0 hoặc x+7=0
-> x=5 hoặc x--7
\(\left(x-5\right)\left(x+7\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x+7=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=-7\end{cases}}}\)