xy-8x+x2-8y
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\(C=-\left(x^2+4x+4\right)-\left(y^2-8y+16\right)+22\\ =-\left(x^2+2x.2+2^2\right)-\left(y^2-2.y.4+4^2\right)+22\\ =-\left(x+2\right)^2-\left(y-4\right)^2+22\\ Vậy:max_C=22.khi.x=-2.và.y=4\)
\(x^2-xy-8x+8y\)
\(=x\left(x-y\right)-8\left(x-y\right)=\left(x-8\right)\left(x-y\right)\)
1.
\(a,\left(-xy\right)\left(-2x^2y+3xy-7x\right)\)
\(=2x^3y^2-3x^2y^2+7x^2y\)
\(b,\left(\dfrac{1}{6}x^2y^2\right)\left(-0,3x^2y-0,4xy+1\right)\)
\(=-\dfrac{1}{20}x^4y^3-\dfrac{1}{15}x^3y^3+\dfrac{1}{6}x^2y^2\)
\(c,\left(x+y\right)\left(x^2+2xy+y^2\right)\)
\(=\left(x+y\right)^3\)
\(=x^3+3x^2y+3xy^2+y^3\)
\(d,\left(x-y\right)\left(x^2-2xy+y^2\right)\)
\(=\left(x-y\right)^3\)
\(=x^3-3x^2y+3xy^2-y^3\)
2.
\(a,\left(x-y\right)\left(x^2+xy+y^2\right)\)
\(=x^3-y^3\)
\(b,\left(x+y\right)\left(x^2-xy+y^2\right)\)
\(=x^3+y^3\)
\(c,\left(4x-1\right)\left(6y+1\right)-3x\left(8y+\dfrac{4}{3}\right)\)
\(=24xy+4x-6y-1-24xy-4x\)
\(=\left(24xy-24xy\right)+\left(4x-4x\right)-6y-1\)
\(=-6y-1\)
#Toru
⇒(x−1)^2+4(y+1)^2+(z−3)^2≥0
x^2+4y^2+z^2-2x-6z+8y+15
=x^2+4y^2+z^2-2x-6z+8y+1+1+4+9
=(x^2-2x+1)+(4y^2+8y+4)+(z^2-6z+9)+1
=(x-1)^2+4(y+1)^2+(z-3^)2+1
Ta thấy:(x−1)^2≥0
4(y+1)^2≥0
(z−3)^ 2≥0
{(x−1)^24(y+1)^2(z−3)^2≥0
⇒(x−1)^2+4(y+1)^2+(z−3)^2≥0
⇒(x−1)2+4(y+1)2+(z−3)2+1≥0+1=1>0
\(=x\left(x-8\right)+y\left(x-8\right)=\left(x-8\right)\left(x+y\right)\)