(x+5)+(x+10)+(x+15)+…+(x+100)=1110
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\(\left(x+5\right)+\left(x+10\right)+\left(x+15\right)+...+\left(x+100\right)=1110\)
\(\Leftrightarrow x+5+x+10+x+15+...+x+100=1110\)
\(\Leftrightarrow20x+\left(5+10+15+...+100\right)=1110\)
\(\Leftrightarrow20x+\frac{\left(100+5\right)\left[\left(100-5\right)\div5+1\right]}{2}=1110\)
\(\Leftrightarrow20x+\frac{2100}{2}=1110\)
\(\Leftrightarrow20x+1050=1110\)
\(\Leftrightarrow20x=1110-1050\)
\(\Leftrightarrow20x=60\)
\(\Leftrightarrow x=60\div20\)
\(\Leftrightarrow x=3\)
Vậy x = 3
\((x+5)+(x+10)+(x+15)+...+(x+100)=1110\)
\(\Rightarrow x+5+x+10+x+15+...+x+100=1110\)
\(\Rightarrow(x+x+x+...+x)+(5+10+15+...+100)=1110\)
\(\Rightarrow100x+\frac{(5+100)\cdot20}{2}=1110\)
\(\Rightarrow100x+1050=1110\)
\(\Rightarrow100x=1110-1050\)
\(\Rightarrow100x=60\)
....
\(20x+5+10+15+..+100=1110\)
\(20x+1050=1110\)
\(20x=50\)
\(x=2,5\)
Ai tích mk mk tích lại cho
( x + 5 ) + ( x + 10 ) + ...+ ( x + 100 ) = 1110
=> ( x+x+x+...+x) + ( 5+10+15+...+100) = 1110
=> x . 20 + 1050
=> x . 20 = 60
=> x = 3
vậy x = 3
( x + 5 ) + ( x + 10 ) + ( x + 15 ) + ........ + ( x + 100 ) = 1110. Tìm x
=> ( x + x + x + ... + x ) + ( 5 + 10 + 15 + ... + 100 ) = 1110
=> X x 20 + 1050
=> X x 20 = 60
=> X = 3
Vậy x bằng : 3
( x + 5 ) + ( x + 10 ) + ( x + 15 ) + ...... + ( x + 100 ) = 1110
20x + ( 5 + 10 + 15 + ..... + 100 ) = 1110
20x + ( 105 x 10 ) = 1110
20x + 1050 = 1110
20x = 1110 - 1050
20x = 60
x = 60 : 20
x = 3
Vậy x = 3
Tra loi:
(x+5)+(x+10)+x+15+.....+(x+100)=1110
=>( x+x+.....+x) + (5+10+...+100)=1110
=> 20x +1050=1110
=> 20x=60
=> x=3
( x + 5 ) + ( x + 10 ) + ( x + 15 ) +...................+ ( x + 100 ) = 1110:
(100-5): 5 + 1=20
= x+ ( 5+ 10)x20:2)= 1110
=x+ 150=1110
x= 1110 - 150
x= 960
( x + 5 ) + ( x + 10 ) + . . . + ( x + 100 ) = 1110
=> x × 20 + ( 5 + 10 + . . . + 100 ) = 1110
=> x × 20 + 1050 = 1110
=> x × 20 = 60
=> x = 60 : 20
=> x = 3
Số số hạng của dãy là:(100-5):5+1=20
(x+x+...+x)+(5+10+15+...+100)=1110
x × 20+(100+5)×20:2=1110
x×20+1050=1110
x×20=1110-1050
x×20=60
x=60:20
x=3
( x + 5 ) + ( x + 10 ) + ...+ ( x + 100 ) = 1110
=> ( x+x+x+...+x) + ( 5+10+15+...+100) = 1110
=> x . 20 + 1050
=> x . 20 = 60
=> x = 3
vậy x = 3
<=>(x+x+x+...+x)+(5+10+...+100)=1110
=>20x+1050=1110
=>20x=1110-1050
=>20x=60
=>x=3
a: \(\Leftrightarrow\left(\dfrac{x+2001}{5}+1\right)+\left(\dfrac{x+1999}{7}+1\right)+\left(\dfrac{x+1997}{9}+1\right)+\left(\dfrac{x+1995}{11}+1\right)=0\)
=>x+2006=0
=>x=-2006
b: \(\Leftrightarrow\left(\dfrac{x-15}{100}-1\right)+\left(\dfrac{x-10}{105}-1\right)+\left(\dfrac{x-100}{5}-1\right)=\left(\dfrac{x-100}{15}-1\right)+\left(\dfrac{x-105}{10}-1\right)+\left(\dfrac{x-110}{5}-1\right)\)
=>x-105=0
=>x=105
3. cái này tớ thi trong violympic rồi. đảm bảo luôn
tk cho tớ nhé