39+13-13=?
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\(a,\left(x-2\right)\cdot13=0\\ \Rightarrow x-2=0\\ \Rightarrow x=2\)
Vậy x = 2
\(b,\left(x-2\right)\cdot13=13\\ \Rightarrow x-2=1\\ \Rightarrow x=3\)
Vậy x = 3
\(c,\left(x-2\right):13=1\\ \Rightarrow x-2=13\\ \Rightarrow x=15\)
Vậy x = 15
\(d,13:\left(x-2\right)=1\\ \Rightarrow x-2=13\\ \Rightarrow x=15\)
Vậy x = 15
\(e,13:\left(x-2\right)=13\\ \Rightarrow x-2=1\\ \Rightarrow x=3\)
Vậy x = 3
a,(x−2)⋅13=0⇒x−2=0⇒x=2a,(x−2)⋅13=0⇒x−2=0⇒x=2
Vậy x = 2
b,(x−2)⋅13=13⇒x−2=1⇒x=3b,(x−2)⋅13=13⇒x−2=1⇒x=3
Vậy x = 3
c,(x−2):13=1⇒x−2=13⇒x=15c,(x−2):13=1⇒x−2=13⇒x=15
Vậy x = 15
d,13:(x−2)=1⇒x−2=13⇒x=15d,13:(x−2)=1⇒x−2=13⇒x=15
Vậy x = 15
e,13:(x−2)=13⇒x−2=1⇒x=3e,13:(x−2)=13⇒x−2=1⇒x=3
Vậy x = 3
=87.13-87.39-13.87-13.39
=13.(87-87)-39.(87+13)
=13.0-39.100
=0-3900
=-3900
\(\dfrac{70}{39}\times\dfrac{13}{14}-\dfrac{13}{25}:\dfrac{39}{50}=\dfrac{5}{3}-\dfrac{13}{25}\times\dfrac{50}{39}=\dfrac{5}{3}-\dfrac{2}{3}=1\)
\(\dfrac{70}{39}\cdot\dfrac{13}{14}-\dfrac{13}{25}:\dfrac{39}{50}\)
\(=\dfrac{5}{3}-\dfrac{13}{25}\cdot\dfrac{50}{39}\)
\(=\dfrac{5}{3}-\dfrac{2}{3}\)
=1
a, ( x - 21 x 13 ) : 11 = 39 Tich mk cau b) ti nua mk lam cho gio phai di hoc them rui
x - 273 = 39 x 11
x - 273 = 429
x = 429 + 273
x = 702
a, ( x - 21 x 13 ) : 11 = 39 b, ( x - 21 ) x 13 : 11 = 39
( x - 21 x 13 ) = 39 x 11 ( x - 21 ) x 13 = 39 x 11
( x - 21 x 13 ) = 429 ( x - 21) x 13 = 429
x - 273 = 429 ( x - 21 ) = 429 : 13
x = 429 + 273 ( x - 21 ) = 33
x = 702 x = 33 + 21
x = 54
(7 . 13 + 8 . 13) / (8 + 21 - x) = 39
13 (7 + 8) / (8 + 21 - x) = 39
13 . 15 / (8 + 21 - x) = 39
13 . 3 . 5 / (8 + 21 - x) = 39
39 . 5 / (8 + 21 - x) = 39
5 / (29 - x) = 1
29 - x = 5
x = 24
39+13-13= 52-13
=39
bằng 39 nhé