Bài 5 (0,5 điểm): Tính A = 2^0 + 2^1 + 2^2 + 2^3 + .... + 2^19 .
mình đang cần gấp
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)=-7/21+8/24
=-1/3+1/3
=0
b)=-3/5.(2/7+5/7)+23/5
=-3/5.7/7+23/5
=-3/5.1+23/5
=-3/5+23/5
=20/5=4
c)=75/100-11/2+5/10:5/12+1/4
=3/4-11/2+1/2:5/12+1/4
=3/4+-11/2+1/2.12/5+1/4
=3/4+-22/4+6/5+1/4
=-19/4+6/5+1/4
=(-19/4+1/4)+6/5
=-18/4+6/5
=-9/2+6/5
=-45/10+12/10
=-23/10
`2^2 .2^3-(2022^0+19):2^2`
`=4.8-(1+19):4`
`=4.8-20:4`
`=32-5`
`=27`
\(2^2\cdot2^3-\left(2022^0+19\right):2^2=4\cdot8-\left(1+19\right):4=32-20:4=32-5=27\)
c)
\(\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+....+\left(1-\frac{1}{42}\right)+\left(1-\frac{1}{56}\right)\)
\(\left(1+1+1+....+1+1\right)+\left(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{6\times7}+\frac{1}{7\times8}\right)\)(Có 7 số 1)
\(7+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(7+1-\frac{1}{8}=\frac{63}{8}\)
Gợi ý 1 bài c) còn d) e) cũng làm như vậy nhé
Chúc bạn học tốt !!!
a) \(-\left(76-35+15\right)+\left[18-27+\left(-17\right)\right]\)
\(=-76+35+15+18-27-17\)
\(=-52\)
b) \(167+\left[127-235-\left(-16\right)\right]+\left(-67\right)\)
\(=167+127-235+16-67\)
\(=8\)
c) \(\left(-19\right)+165-\left[27+\left(-21\right)-\left(+72\right)\right]\)
\(=\left(-19\right)+165-27+21+72\)
\(=212\)
d) \(89.\left(-2\right)+\left[20+\left(-2\right).\left(-5\right)-85\right]\)
\(=\left(-178\right)+\left(20+10-85\right)\)
\(=\left(-178\right)+20+10-85\)
\(=-233\)
A = (30: 7\(\dfrac{1}{2}\)) : (\(\dfrac{1}{15}\):0,5) -1,5\(\times\)(4\(\dfrac{1}{2}\)-\(\dfrac{9}{2}\))
A = (30 : \(\dfrac{15}{2}\)): (\(\dfrac{1}{15}\) \(\times\) 2) - 1,5 \(\times\) (\(\dfrac{9}{2}\) - \(\dfrac{9}{2}\))
A = (30 \(\times\) \(\dfrac{2}{15}\)) : \(\dfrac{2}{15}\) - 1,5 \(\times\) 0
A = 4 \(\times\) \(\dfrac{15}{2}\) - 0
A = 30
=0+2+4+8+16+32+64+128+256+512+1024+2048+4096+8192+16384+32768+65536 +131072+262144+524288=?Em mới lớp 4 chúc anh học tốt!