Rut gon phan so
a) \(\frac{3024-12}{5292-21}\)
b) \(\frac{2^3.3}{2^2.3^2.5}\)
c) \(\frac{2^4.5^2.7}{2^3.5.7^2.11}\)
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TA CÓ : \(\frac{2^3.3^4}{2^2.3^2.5}\)= \(\frac{2^3.3^4}{\left(2.3\right)^2.5}\)= \(\frac{2^3.3^4}{6^2.5}\)= \(\frac{2^3.3^4}{36.5}\)= \(\frac{8.81}{180}\)= \(\frac{648}{180}\)= 648 : 180 = 3,6 HOẶC \(\frac{648}{180}\)= \(\frac{18}{5}\)
Ta có:
\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)
\(a.\frac{2\cdot\left(-13\right)\cdot9\cdot10}{\left(-3\right)\cdot4\cdot\left(-5\right)\cdot26}\)
\(=\frac{2\cdot\left(-13\right)\cdot3\cdot3\cdot2\cdot5}{\left(-3\right)\cdot2\cdot2\cdot\left(-5\right)\cdot13\cdot2}\)
\(=-\frac{3}{2}\)
b) \(\frac{2^3\cdot3^4}{2^2\cdot3^2\cdot5}=\frac{2\cdot3^2}{5}=\frac{2\cdot9}{5}=\frac{18}{5}\)
\(\frac{2^4\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}=\frac{2\cdot1\cdot11\cdot1}{1\cdot5\cdot7\cdot1}=\frac{22}{35}\)
c) \(\frac{121\cdot75\cdot130\cdot169}{39\cdot60\cdot11\cdot198}=\frac{11\cdot11\cdot13\cdot10\cdot169}{13\cdot3\cdot6\cdot10\cdot11\cdot11\cdot6\cdot3}\)
\(=\frac{169}{3\cdot6\cdot6\cdot3}=\frac{169}{324}\)
d) \(\frac{1998\cdot1990+3978}{1992\cdot1991-3984}\)
a) \(\dfrac{2^4\cdot5^2\cdot7}{2^3\cdot5\cdot7^2\cdot11}=\dfrac{2^3\cdot5\cdot10\cdot7}{2^3\cdot5\cdot7\cdot77}=\dfrac{10}{77}\)
\(\dfrac{2^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot2^4\cdot5^3\cdot14}=\dfrac{2^3\cdot3\cdot5^3\cdot7\cdot3^2\cdot8}{3\cdot2^3\cdot2\cdot5^3\cdot14}=\dfrac{7\cdot3^2\cdot8}{2\cdot14}=\dfrac{63\cdot8}{2\cdot14}=18=\dfrac{1386}{77}\)
b)\(\frac{-15.8+10.7}{5.6+20.3}=\frac{-15.8+10.7}{5.2.3+5.4.3}=\frac{-90+70}{5.3.\left(2+4\right)}=\frac{-20}{90}=-\frac{2}{9}\)
\(\frac{2^4.5^2.7}{2^3.5.7^2.11}=\frac{2.5.1}{1.1.7.11}=\frac{10}{77}\)
MSC:77.9=693
\(\frac{-2}{9}=\frac{-2.693}{9.693}=\frac{-1386}{6237}\)
\(\frac{10}{77}=\frac{10.693}{77.693}=\frac{6930}{53361}\)
a) \(\frac{4.5+4.11}{8.7+4.3}=\frac{4.\left(5+11\right)}{56+12}=\frac{4.16}{68}=\frac{64}{68}=\frac{16}{17}.\)
Mình chỉ làm câu a) thôi nhé.
Chúc bạn học tốt!
\(\frac{2^4.5^2.7}{2^3.5.7^2.11}=\frac{2^3.5.5.7}{2^3.5.7.7.11}=\frac{5}{7.11}=\frac{5}{77}\)
ko
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A.\(\frac{2^3.9^2}{2^2.3^2.5}=\frac{2^2.2.\left(3^2\right)^2}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)
B.\(\frac{2^4.5^5.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^3.5^2.11.11.7}{2^3.5^3.7.7.11}=\frac{2.5^2.11}{7}=\frac{61}{7}\)
a) \(\frac{3024-12}{5292-21}=\frac{3012}{5271}=\frac{4}{7}\)
b) \(\frac{2^3.3}{2^2.3^2.5}=\frac{2^1.1}{1.3^1.5}=\frac{2}{15}\)
c) dễ mà đợi mk tính rùi làm sau
duyệt đi
c) = \(\frac{2^1.5^1.1}{1.1.7^1.11}=\frac{10}{77}\)
ko bít đúng ko
duyệt đi