5^x-2=1
4^x-3=64
3^x+1 +1=244
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a: \(A=\left[111\cdot\left(38\cdot3-133\right)\right]\cdot2018\)
\(=111\cdot\left(-19\right)\cdot2018=-4255962\)
b: \(B=\left[25\left(1+3\cdot3-5\cdot2\right)\right]:20182019\)
\(=25\left(1+9-10\right):20182019=0\)
c: \(C=\dfrac{\left[244\left(395-195\right)\right]}{122\cdot200}=\dfrac{244}{122}=2\)
d: \(D=\dfrac{355\cdot45\cdot55}{11\cdot9\cdot7}=\dfrac{355\cdot5\cdot5}{7}=\dfrac{8875}{7}\)
1: \(=\dfrac{-\left[\left(x+5\right)^2-9\right]}{\left(x+2\right)^2}=\dfrac{-\left(x+5-3\right)\left(x+5+3\right)}{\left(x+2\right)^2}\)
\(=\dfrac{-\left(x+2\right)\left(x+8\right)}{\left(x+2\right)^2}=\dfrac{-\left(x+8\right)}{x+2}\)
2: \(=\dfrac{2x\left(x^2-4x+16\right)}{\left(x+4\right)\left(x^2-4x+16\right)}=\dfrac{2x}{x+4}\)
3: \(=\dfrac{5x\left(x^2+1\right)}{\left(x^2-1\right)\left(x^2+1\right)}=\dfrac{5x}{x^2-1}\)
4: \(=\dfrac{3\left(x^2-4x+4\right)}{x\left(x^3-8\right)}=\dfrac{3\left(x-2\right)^2}{x\left(x-2\right)\left(x^2+2x+4\right)}\)
\(=\dfrac{3\left(x-2\right)}{x\left(x^2+2x+4\right)}\)
5: \(=\dfrac{2a\left(a-b\right)}{a\left(c+d\right)-b\left(c+d\right)}=\dfrac{2a\left(a-b\right)}{\left(c+d\right)\left(a-b\right)}=\dfrac{2a}{c+d}\)
6: \(=\dfrac{x\left(x-y\right)}{\left(x-y\right)\left(x+y\right)}\cdot\left(-1\right)=\dfrac{-x}{x+y}\)
7: \(=\dfrac{2\left(1-a\right)}{-\left(1-a^3\right)}=\dfrac{-2\left(1-a\right)}{\left(1-a\right)\left(1+a+a^2\right)}=-\dfrac{2}{1+a+a^2}\)
8: \(=\dfrac{x^4\left(x^3-1\right)}{\left(x^3-1\right)\left(x^3+1\right)}=\dfrac{x^4}{x^3+1}\)
9: \(=\dfrac{\left(x+2-x+2\right)\left(x+2+x-2\right)}{16x}=\dfrac{4\cdot2x}{16x}=\dfrac{1}{2}\)
10: \(=\dfrac{0.5\left(49x^2-y^2\right)}{0.5x\left(7x-y\right)}=\dfrac{1}{x}\cdot\dfrac{\left(7x-y\right)\left(7x+y\right)}{7x-y}\)
\(=\dfrac{7x+y}{x}\)
a) 2x - 15 = 13
=> 2x = 13 + 15
=> 2x = 28
=> x = 14
128 - (x + 5) = 23
=> x + 5 = 128 - 23
=> x + 5 = 105
=> x = 105 - 5
=> x = 100
[(x2 + 54) - 32] . 2 = 244
=> (x2 + 54) - 32 = 244 : 2
=> (x2 + 54) - 32 = 122
=> x2 + 54 = 122 + 32
=> x2 + 54 = 154
=> x2 = 154 - 54
=> x2 = 100
=> x2 = 102
=> x = 10
(3x - 1)3 = 125
=> (3x - 1)3 = 53
=> 3x - 1 = 5
=> 3x = 5 + 1
=> 3x = 6
=> x = 2
Bài 1: Tìm x biết
a, 2x - 15= 13
2x = 13 + 15
2x = 28
x = 28 : 2
x = 14
Vậy x = 14
128 - (x + 5)= 23
x + 5 = 128 - 23
x + 5 = 105
x = 105 - 5
x = 100
Vậy x = 100
[( x2+54) - 32].2= 244
( \(x^2\) + 54 ) - 32 = 244 : 2
( x2+54) - 32 = 122
x2+54 = 122 + 32
x2+54 = 154
x2 = 154 - 54
x2 = 100
\(x^2\) = \(10^2\)
x =10
(3x -1)3= 125
\(\left(3x-1\right)^3\) = \(5^3\)
3x -1 = 5
3x = 5 + 1
x = 6 : 3
x = 2
b, 100: ( 2x+5 )= 4
2x + 5 = 100 : 4
2x + 5 = 25
2x = 45 - 5
2x = 40
x = 40 : 2
x = 20
[( 8x-14 ) :2 - 2]. 31= 341
( 8x - 14 ) : 2 - 1 = 341 : 31
( 8x - 14 ) :2 -2 = 11
( 8x - 14 ) : 2 = 11 + 2
( 8x - 14 ) : 2 = 13
8x - 14 = 13 . 2
8x - 14 = 26
8x = 26 + 14
8x = 40
x = 40 : 8
x = 5
1230 :3 (x - 20 )= 10
3 ( x - 20 ) = 1230 : 10
3 ( x - 20 ) = 123
x - 20 = 123 : 3
x- 20 = 41
x = 41 + 20
x= 61
Câu cuối mk chịu
Tk mk nha
|7 - \(\dfrac{3}{4}\)\(x\)| - \(\dfrac{3}{2}\) = \(\dfrac{1}{\dfrac{1}{2}}\)
|7 - \(\dfrac{3}{4}x\)| - \(\dfrac{3}{2}\) = 2
|7 - \(\dfrac{3}{4}\)\(x\)| = 2 + \(\dfrac{3}{2}\)
|7 - \(\dfrac{3}{4}x\)| = \(\dfrac{7}{2}\)
\(\left[{}\begin{matrix}7-\dfrac{3}{4}x=\dfrac{7}{2}\\7-\dfrac{3}{4}x=-\dfrac{7}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}\dfrac{3}{4}x=7-\dfrac{7}{2}\\\dfrac{3}{4}=7+\dfrac{7}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}\dfrac{3}{4}x=\dfrac{7}{2}\\\dfrac{3}{4}x=\dfrac{21}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{14}{3}\\x=14\end{matrix}\right.\)
5 - |\(x-3\)| = 5
|\(x-3\)| = 5 - 5
|\(x-3\)| = 0
\(x-3\) = 0
\(x\) = 3
4 x 2 x 5 = ?
Cách 1: 4 x 2 x 5 = (4 x 2) x 5 = 8 x 5 = 40
Cách 2: 4 x 2 x 5 = 4 x (2 x 5) = 4 x 10 = 40
7 x 2 x 3 = ?
Cách 1: 7 x 2 x 3 = (7 x 2) x 3 = 14 x 3 = 42
Cách 2: 7 x 2 x 3 = 7 x (2 x 3) = 7 x 6 = 42
6 x 3 x 3 = ?
Cách 1: 6 x 3 x 3 = (6 x 3) x 3 = 18 x 3 = 54
Cách 2: 6 x 3 x 3 = 6 x (3 x 3) = 6 x 9 = 54
6 x 2 x 4 = ?
Cách 1: 6 x 2 x 4 = (6 x 2) x 4 = 12 x 4 = 48
Cách 2: 6 x 2 x 4 = 6 x (2 x 4) = 6 x 8 = 48
X+\(\dfrac{2}{7}\)=\(\dfrac{1}{2}\)
X = \(\dfrac{1}{2}\)-\(\dfrac{2}{7}\)
X = \(\dfrac{3}{14}\)
Chọn đáp án A. \(\dfrac{3}{14}\)
a: \(=\dfrac{2}{5}+\dfrac{3}{5}\cdot\dfrac{10}{3}\cdot\dfrac{1}{2}=\dfrac{2}{5}+\dfrac{10}{5}\cdot\dfrac{1}{2}=\dfrac{2}{5}+1=\dfrac{7}{5}\)
a: \(\dfrac{x}{0.9}=\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{3}{4}\)
b: \(\dfrac{-6}{x}=\dfrac{9}{-15}\)
\(\Leftrightarrow x=10\)
c: \(\dfrac{\dfrac{14}{15}}{\dfrac{9}{10}}=\dfrac{x}{\dfrac{3}{7}}\)
\(\Leftrightarrow x=\dfrac{3}{7}\cdot\dfrac{14}{15}:\dfrac{9}{10}=\dfrac{2}{5}\cdot\dfrac{10}{9}=\dfrac{20}{45}=\dfrac{4}{9}\)