2+2
2+2= 1+1+12-3
=
K
Khách
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MS
1
N
30 tháng 11 2018
\(B=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{12}\left(1+2+3+...+12\right)\)
\(B=1.\left(\frac{1.2}{2}\right)+\frac{1}{2}.\left(\frac{2.3}{2}\right)+\frac{1}{3}.\left(\frac{3.4}{2}\right)+....+\frac{1}{12}.\left(\frac{12.13}{2}\right)\)
\(B=\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+....+\frac{13}{2}=\frac{2+3+4+....+13}{2}=\frac{90}{2}=45\)
NT
3
N
4 tháng 12 2018
\(M=54-\frac{1}{2}.\left(1+2\right)-\frac{1}{3}.\left(1+2+3\right)-....-\frac{1}{12}.\left(1+2+...12\right)\)
\(M=54-\left[\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+....+\frac{1}{12}.\left(1+2+...+12\right)\right]\)
\(M=54-\left(\frac{1}{2}\cdot\frac{2.3}{2}+\frac{1}{3}\cdot\frac{3.4}{2}+....+\frac{1}{12}\cdot\frac{12.13}{2}\right)\)
\(M=54-\left(\frac{3}{2}+\frac{4}{2}+...+\frac{13}{2}\right)=54-44=10\)
Vậy M=10
KS
0
14 tháng 8 2020
a)2/3 + 5+3/7:2+4/49.(-7)+1/2.(-2)\(^4\)
= 2/3+5+3/14+-4/7+8
=(2/3+3/14+-4/7)+(5+8)
=13/42+13
=559/42
b)2+3/4.(-0,4)-1-3/5.2,75+(-1/2):4/11
=2+(-0,3) - 1 - 1,65 + (-11/8)
= -2,325
c)( 2 + 1/3 +3 +1/2 ) : ( -4 - 1/6 +3 +1/7 ) +7 +1/2
=35/6 : -43/42 + 7 + 1/2
= -245/43 +7 +1/2
= 155/86
d) 2/3+ -5/12
= 8/12 + -5/12
= 3/12
e) -2/3 . -9/12
= \(\frac{-2.-9}{3.12}\)
= 18/36
=1/2
14 tháng 8 2020
f) -2/9 - 7/12
=\(\frac{-24}{108}\)- \(\frac{14}{108}\)
= \(\frac{-38}{108}\)
=\(\frac{-19}{54}\)
g) 2/3 : -4/9
= \(\frac{2}{3}\). \(\frac{-9}{4}\)
= -3/2
h) 4 . ( -1/3)\(^3\)- 2 . ( -1/2)\(^2\)+3 .( 1/2 ) +1
=- 4 . 1/27 - 2 . 1/4 + 3 .1/2 +1
= -4/27 - 1/2 + 3/2 + 1
= 50 / 27
k ) ( 4 - 5/12 ) : 2 +5/24
= 43/12 : 2 +5/24
= 43/24 + 5/24
= 48/24
= 2
HB
0
YS
14 tháng 5 2017
Bài giải:
Câu 1: a, \(\left(-2\right).4.5.38.\left(-25\right)\)
\(=\left[\left(-2\right).5\right].\left[4.\left(-25\right)\right].38\)
\(=\left(-10\right).\left(-100\right).38\)
\(=1000.38=38000\)
b,\(\frac{1}{3}+\frac{3}{8}-\frac{7}{12}\)
\(=\left(\frac{1}{3}+\frac{3}{8}\right)-\frac{7}{12}\)
\(=\frac{17}{24}-\frac{7}{12}=\frac{1}{8}\)
c, \(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)
\(=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
\(=\frac{-5}{8}.1+\frac{17}{8}\)
\(=\frac{3}{2}\)
Câu 2: a, \(x-\frac{2}{5}=0,24\)
\(x-0,4=0,24\)
\(x=0,24+0,4\)
\(\Rightarrow x=0,64\left(\frac{16}{25}\right)\)
b,\(\frac{2}{3}.x+\frac{1}{12}=\frac{1}{10}\)
\(\frac{2}{3}.x=\frac{1}{10}-\frac{1}{12}\)
\(\frac{2}{3}.x=\frac{1}{60}\)
\(x=\frac{1}{60}:\frac{2}{3}\)
\(\Rightarrow x=\frac{1}{40}\)
c, \(\left(3\frac{1}{2}-2x\right).1\frac{1}{3}=7\frac{1}{3}\)
\(\frac{7}{2}-2x=\frac{22}{3}:\frac{4}{3}\)
\(\frac{7}{2}-2x=\frac{11}{2}\)
\(2x=\frac{7}{2}-\frac{11}{2}\)
\(2x=-2\)
\(\Rightarrow x=-2:2\)
\(x=-1\)
2+ 2=4 ,1+ 1+ 12 - 3= 11
=2 nhé bạn