(x-15)/100 +(x-10)/105 +(x-5)/110 = (x-100)/15 +(x-105)/10 +(x-110)/5
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(\Leftrightarrow\left(\dfrac{x+2001}{5}+1\right)+\left(\dfrac{x+1999}{7}+1\right)+\left(\dfrac{x+1997}{9}+1\right)+\left(\dfrac{x+1995}{11}+1\right)=0\)
=>x+2006=0
=>x=-2006
b: \(\Leftrightarrow\left(\dfrac{x-15}{100}-1\right)+\left(\dfrac{x-10}{105}-1\right)+\left(\dfrac{x-100}{5}-1\right)=\left(\dfrac{x-100}{15}-1\right)+\left(\dfrac{x-105}{10}-1\right)+\left(\dfrac{x-110}{5}-1\right)\)
=>x-105=0
=>x=105
Đề đoạn cuối hình như phải là x-400/100 chứ bạn
=> (x+5/105 - 1) + (x+6/106 - 1) + (x+10/110 - 1) + (x-400/100 + 3) = 0
=> x-100/105 + x-100/106 + x-100/110 + x-100/100 = 0
=> (x-100).(1/105 + 1/106 + 1/110 + 1/100) = 0
=> x-100 = 0 ( vì 1/105 + 1/106 + 1/110 + 1/100 > 0 )
=> x = 100
Vậy x = 100
Tk mk nha
a, (-4) . (+125) . (-25) . 6 . (-8)
=[ (-4) . (-25) ] . [ (+125) . (-8) ] . 6
= 100 . (-1000) . 6
= -100 000 . 6
= -600 000
b, 122 . (-12345) + 12345 . (-78)
= 12345 . [ (-122) + (-78) ]
= 12345 . (-200)
= -2 469 000
a, 100 - 7 x ( x - 5 ) = 58
7 x ( x - 5 ) = 100 - 58
7 x ( x - 5 ) = 42
( x - 5 ) = 42 : 7
x - 5 = 6
x = 6 + 5
x = 11
b, 24 + 5 * x = 49
5 * x = 49 - 24
5 * x = 25
x = 25 : 5
x = 5
c, x - 105 : 21 = 15
x - 5 = 15
x = 15 + 5
x = 20
d, ( x - 105 ) : 21 = 15
( x - 105 ) = 15 x 21
x - 105 = 315
x = 315 + 105
x = 420
1) \(2^x-15=17\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
2) \(\left(7x-11\right)^3=25\cdot5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=825\)
\(\Leftrightarrow7x-11=\sqrt[3]{825}\)
\(\Leftrightarrow7x=11+\sqrt[3]{825}\)
\(\Rightarrow x=\frac{11+\sqrt[3]{825}}{7}\)
3) \(\left(x+1\right)^{100}-3\left(x+1\right)^{99}=0\)
\(\Leftrightarrow\left(x+1\right)^{99}\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{99}=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)
4) \(4x+5\left(x+3\right)=105\)
\(\Leftrightarrow9x+15=105\)
\(\Leftrightarrow9x=90\)
\(\Rightarrow x=10\)
5) \(5\cdot\left(x-2\right)+10\left(x+3\right)=170\)
\(\Leftrightarrow5\left[x-2+2\left(x+3\right)\right]=170\)
\(\Leftrightarrow3x+4=34\)
\(\Leftrightarrow3x=30\)
\(\Rightarrow x=10\)
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
C=3-1+4-1+5-1+....+102-1+103-1
C=2+3+4+5+...+101+102
Tổng đã cho có: (102-2):1+1=101 (số hạng)
C=(102+2)*101:2=5252
Vậy 5252 là tổng của tập hợp C.
\(\frac{x-15}{100}+\frac{x-10}{105}+\frac{x-5}{110}=\frac{x-100}{15}+\frac{x-105}{10}+\frac{x-110}{5}\)
=> \(\left(\frac{x-15}{100}-1\right)+\left(\frac{x-10}{105}-1\right)+\left(\frac{x-5}{110}-1\right)=\left(\frac{x-100}{15}-1\right)+\)
\(\left(\frac{x-105}{10}-1\right)+\left(\frac{x-110}{5}-1\right)\)
=> \(\frac{x-115}{100}+\frac{x-115}{105}+\frac{x-115}{110}=\frac{x-115}{15}+\frac{x-115}{10}+\frac{x-115}{5}\)
=> \(\left(x-115\right)\left(\frac{1}{100}+\frac{1}{105}+\frac{1}{110}-\frac{1}{15}-\frac{1}{10}-\frac{1}{5}\right)=0\)
=> x - 115 = 0 (Vì \(\frac{1}{100}+\frac{1}{105}+\frac{1}{110}-\frac{1}{15}-\frac{1}{10}-\frac{1}{5}\ne0\)
=> x = 115