kết quả của phép tính 2012/2013-2011/2012 nhanh lên nha giúp mình đi thank you
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\(...=2022+2020+\left(-2019+2016-2018+2015-2017+2014\right)+...+\left(6-3+5-2+4-1\right)\)
\(=2022+2020+\left(-3-3-3\right)+\left(-3-3-3\right)+...+\left(-3-3-3\right)+\left(-3-2-1\right)\)
\(=2022+2020+\left(-9\right)+\left(-9\right)+...\left(-9\right)+\left(-6\right)\)
\(=2022+2020+\left(-9\right).\left[\left(2019-9\right):6+1\right].\left[\left(2019+6\right)\right]:2+\left(-6\right)\)
\(=2022+2020+\left(-9\right).336.2025:2+\left(-6\right)\)
\(=2022+2020-3061800-6\)
\(=-3057764\)
A = 2013 x 2012 - 1997
A = ( 2013 x 2012 ) - 1997
A = 4050156 - 1997
A = 4048159
B = 2012 x 2011 + 2015
B = ( 2012 x 2011 ) + 2015
B = 4046132 + 2015
B = 4048147
\(\dfrac{2010}{2011}+\dfrac{2011}{2012}+\dfrac{2012}{2013}+\dfrac{2013}{2011}\)
=1-\(\dfrac{1}{2011}\)+1\(-\dfrac{1}{2012}\)+1-\(\dfrac{1}{2013}\)+1-\(\dfrac{1}{2011}\)
=4-(\(\dfrac{2}{2011}+\dfrac{1}{2012}+\dfrac{1}{2013}\)) < 4
m=\(\dfrac{2010}{2011}+\dfrac{2011}{2012}+\dfrac{2012}{2013}+\dfrac{2013}{2011}\)
=\(1-\dfrac{1}{2011}+1-\dfrac{1}{2012}+1-\dfrac{1}{2013}+1+\dfrac{2}{2011}\)
=4+\(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}\)
vì:
do \(\dfrac{1}{2011}< 1\)
\(\dfrac{1}{2012}< 1\)
\(\dfrac{1}{2013}< 1\)
nên \(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 1-1-1=-1\)
hay \(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 0\)
nên 4+\(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 4\)
vậy tổng m <4
bài này mình tưởng phải lên cấp 2 mới có thế mà mấy em lớp 4 đã phải làm á
Ta có: 2011+2012/2012+2013
=(2011/2012+2013)+(2012/2012+2013)
Vì 2011/2012>2011/2012+2013và 2012/2013>2012/2012+2013
Suy ra:2011/2012+2012/2013>(2011/2012+2013)+(2012/2012+2013)
hay A>b
Vậy A>B
Ta có:\(\frac{2010+2011+2012}{2011+2012+2013}=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2013}{2011+2012+2013}\)
MÀ:\(\frac{2010}{2011+2012+2013}< \frac{2010}{2011}\)
\(\frac{2011}{2011+2012+2013}< \frac{2011}{2012}\)
\(\frac{2012}{2011+2012+2013}< \frac{2012}{2013}\)
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2011+2012+2013}\)
2010/2011+2012+2013>2010+2011+2012/2011+2012+2013
2011/2011+2012+2013>2010+2011+2012/2011+2012+2013
2012/2011+2012+2013>2010+2011+2012/2011+2012+2013
suy ra:2010/2011+2011/2012+2012/2013>2010+2011+2012/2011+2012+2013
A = \(\frac{2011+2012}{2012+2013}=\frac{2011+2012}{4025}\)
Ta có:
\(\frac{2011}{2012}>\frac{2011}{4025}\)
\(\frac{2012}{2013}>\frac{2012}{4025}\)
=> \(\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011}{4025}+\frac{2012}{4025}\)
=> \(B>\frac{2011+2012}{4025}\)
=>\(B>A\)
\(\frac{2012}{2013}-\frac{2011}{2012}\)
= 2.4690407e-7