Viết các tập hợp:
a) Ư (15); Ư (27); ƯC (15; 27)
b) Ư (16); Ư (20); Ư (30); ƯC (16; 20; 30)
c) BC (25; 39)
d) BC (100; 120; 140)
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a) Ư (15) = {1;3;5;15}
Ư (27) = {1;3;9;27}
ƯC (15; 27) = {1;3}
b) ƯC (16; 20; 30) = {1;2}
c) BC (25; 39) = {0;975;1950;…}
d) BC (100; 120; 140) = {0;4200;…}
a) Ư (12) = {1;2;3;4;6;12}
Ư (16) = {1;2;4;8;16}
Ư (24) = {1;2;3;4;6;8;12;24}
ƯC (12; 16; 24) = {1;2;4}
b) ƯC (5; 15; 35) = {1;5}
c) BC (8; 12; 24) = {0;24;48}
d) BC (5; 15; 35) = {0;105;210;…}
Bài toán 1 : Viết các tập hợp sau.
a)Ư:(6,9,12) d) B(23) ; B(10) ; B(8)
b)Ư(7) ; Ư(18) ; Ư(10) e) B(3) ; B(12) ; B(9)
c)Ư(15) ; Ư(16) ; Ư(250 g) B(18) ; B(20) ; B(14)
\(a)\)
\(Ư (6) = \) \(\left\{1;2;3;6\right\}\)
\(Ư\left(9\right)=\left\{1;3;9\right\}\)
\(Ư\left(12\right)=\left\{1;2;3;4;6;12\right\}\)
\(b)\)
\(Ư\left(7\right)=\left\{1;7\right\}\)
\(Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)
\(Ư\left(10\right)=\left\{1;2;5;10\right\}\)
\(c)\)
\(Ư\left(15\right)=\left\{1;3;5;15\right\}\)
\(Ư\left(16\right)=\left\{1;2;4;8;16\right\}\)
\(Ư\left(250\right)=\left\{1;2;5;10;25;50;125;250\right\}\)
\(d)\)
\(B\left(23\right)=\left\{0;23;46;69;...\right\}\)
\(B\left(10\right)=\left\{0;10;20;30;...\right\}\)
\(B\left(8\right)=\left\{0;8;16;24;...\right\}\)
\(e)\)
\(B\left(3\right)=\left\{0;3;6;9;...\right\}\)
\(B\left(12\right)=\left\{0;12;24;36;...\right\}\)
\(B\left(9\right)=\left\{0;9;18;27;...\right\}\)
\(g)\)
\(B\left(18\right)=\left\{0;18;36;54;...\right\}\)
\(B\left(20\right)=\left\{0;20;40;60;...\right\}\)
\(B\left(14\right)=\left\{0;14;28;42;...\right\}\)
\(a,ƯC\left(6,9\right)=\left\{\pm1;\pm3\right\}\)
\(b,ƯC\left(7,8\right)=\left\{\pm1\right\}\)
\(c,ƯC\left(4;6;8\right)=\left\{\pm1;\pm2\right\}\)
a)
\(Ư\left(12\right)=\left\{1;2;3;4;6;12\right\}\)
\(Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)
=> \(ƯC\left(12;18\right)=\left\{1;2;3;6;\right\}\)
b) \(B\left(15\right)=\left\{0;15;30;45;60;90;105...\right\}\)
\(B\left(21\right)=\left\{0;21;42;63;84;105;...\right\}\)
=> \(BC\left(15;21\right)=\left\{0;105;...\right\}\)
c)
\(20=2^2.5\)
\(24=2^3.3\)
\(28=2^2.7\)
=> \(BCNN\left(20;24;28\right)=2^3.3.5.7=840\)
=> \(BC\left(20;24;28\right)=B\left(840\right)=\left\{0;840;1680;...\right\}\)
ƯC(15)={ 1;3;5;15}
TÍCH GIÚP MÌNH ĐI BẠN !!!!!!!!!!!!!!!!!!!!!!!!!!