64-35+10=?
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\(\dfrac{7}{15}+\dfrac{4}{5}\)
\(=\dfrac{7}{15}+\dfrac{12}{15}\)
\(=\dfrac{19}{15}\)
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\(\dfrac{35}{28}-\dfrac{48}{64}\)
\(=\dfrac{2240}{1792}-\dfrac{1344}{1792}\)
\(=\dfrac{896}{1792}=\dfrac{1}{2}\)
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\(\dfrac{10}{13}:\dfrac{3}{4}\)
\(=\dfrac{10}{13}\)x\(\dfrac{4}{3}\)
\(=\dfrac{40}{39}\)
\(\dfrac{4^9\cdot36+64^4}{100\cdot16^4}=\dfrac{2^{20}\cdot3^2+2^{24}}{2^{18}\cdot5^2}=\dfrac{2^{20}\left(3^2+2^4\right)}{2^{18}\cdot5^2}=4\)
1/5+4/10+9/15+25/25+36/30+49/35+64/40+81/45
=1/5 + (4/10:2) + (9/15:3)+25/25 + (36/30:6)+ (49/35:7) + (64/40:8) + (81/45:9)
=1/5 + 1/5 + 1/5 + 1 + 1/5 + 1/5 + 1/5 + 1/5
=1/5 x 7 + 1
=12/5
a/ 2130-(x+130)+72=-64
\(2130-\left(x+130\right)=-64-72\) \(2130-\left(x+130\right)=-136\)\(x+130=2130+136\)\(x+130=2266\)\(x=2266-130\)\(x=2136\)vậy x=2136
a/ 2130-(x+130)+72=-64
<=> -x-130+72+2130=-64
<=> x=2130+72-130+64=2136
b/135-|9-x|=35
<=> |9-x|=135-35=100
<=> \(\left[\begin{array}{nghiempt}9-x=100\\9-x=-100\end{array}\right.\)
<=>\(\left[\begin{array}{nghiempt}x=-91\\x=109\end{array}\right.\)
c/10-|x+3|=-4-(-10)
<=> |x+3|=10+4+(-10)
<=>|x+3|=4
<=>\(\left[\begin{array}{nghiempt}x+3=4\\x+3=-4\end{array}\right.\)
<=>\(\left[\begin{array}{nghiempt}x=1\\x=-7\end{array}\right.\)
\(\frac{1}{5}+\frac{4}{10}+\frac{9}{15}+\frac{16}{20}+1+\frac{36}{30}+\frac{49}{35}+\frac{64}{40}+\frac{81}{45}\)
\(=\left(\frac{1}{5}+\frac{81}{45}\right)+\left(\frac{4}{10}+\frac{49}{35}\right)+\left(\frac{9}{15}+\frac{49}{35}\right)+\left(\frac{16}{20}+\frac{36}{30}\right)+1\)
\(=2+2+2+2+1\)
\(=2\times4+1\)
\(=9\)
~ Hok tốt ~
Ta có: \(\dfrac{1}{5}+\dfrac{4}{10}+\dfrac{9}{15}+\dfrac{16}{20}+\dfrac{25}{25}+\dfrac{36}{30}+\dfrac{49}{35}+\dfrac{64}{40}+\dfrac{81}{45}\)
\(=\dfrac{1}{5}+\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{4}{5}+\dfrac{5}{5}+\dfrac{6}{5}+\dfrac{7}{5}+\dfrac{8}{5}+\dfrac{9}{5}\)
\(=\dfrac{45}{5}=9\)
= 39
~HT~
39 nha