Chia các phân thức sau:
a) 27 − a 3 5 a + 10 : a − 3 3 a + 6 với a ≠ − 2 và a ≠ 3
b) ( 2 b 2 − 32 ) : b + 4 7 b − 2 với b ≠ − 4 và b ≠ 2 7 .
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a) Ta có: \(\dfrac{3a^2-10a+3}{2\left(a-3\right)}\)
\(=\dfrac{3a^2-9a-a+3}{2\left(a-3\right)}\)
\(=\dfrac{3a\left(a-3\right)-\left(a-3\right)}{2\left(a-3\right)}\)
\(=\dfrac{\left(a-3\right)\left(3a-1\right)}{2\left(a-3\right)}\)
\(=\dfrac{3a-1}{2}\)
\(=\dfrac{3}{2}a-\dfrac{1}{2}\)(đpcm)
b) Ta có: \(\dfrac{b^2+3b+9}{b^3-27}\)\(=\dfrac{b^2+3b+9}{\left(b-3\right)\left(b^2+3b+9\right)}\)
\(=\dfrac{1}{b-3}\)
\(=\dfrac{b-2}{\left(b-3\right)\left(b-2\right)}\)
\(=\dfrac{b-2}{b^2-5b+6}\)(đpcm)
Bài 1:
Quy đồng mẫu số các phân số:
a; \(\dfrac{2}{5}\) và \(\dfrac{3}{4}\); \(\dfrac{2}{5}\) = \(\dfrac{2\times4}{5\times4}\) = \(\dfrac{8}{20}\); \(\dfrac{3}{4}\) = \(\dfrac{3\times5}{4\times5}\) = \(\dfrac{15}{20}\)
b; \(\dfrac{2}{7}\) và \(\dfrac{5}{14}\); \(\dfrac{2}{7}\) = \(\dfrac{2\times2}{7\times2}\) = \(\dfrac{4}{14}\)
c; \(\dfrac{4}{9}\) và \(\dfrac{5}{27}\); \(\dfrac{4}{9}\) = \(\dfrac{4\times3}{9\times3}\) = \(\dfrac{12}{27}\);
d; \(\dfrac{2}{3};\dfrac{4}{5}\);\(\dfrac{5}{6}\)
\(\dfrac{2}{3}\) = \(\dfrac{2\times10}{3\times10}\) = \(\dfrac{20}{30}\); \(\dfrac{4}{5}\) = \(\dfrac{4\times6}{5\times6}\) = \(\dfrac{24}{30}\); \(\dfrac{5\times5}{6\times5}\) = \(\dfrac{25}{30}\)
\(a,\sqrt{\left(\sqrt{3}+1\right)^2}+\sqrt{\left(\sqrt{3}-1\right)^2}=\left|\sqrt{3}+1\right|+\left|\sqrt{3}-1\right|=\sqrt{3}+1+\sqrt{3}-1=2\sqrt{3}\)
\(b,A=\dfrac{\sqrt{a}}{\sqrt{a}-5}-\dfrac{10\sqrt{a}}{a-25}-\dfrac{5}{\sqrt{a}+5}\)
\(\Rightarrow A=\dfrac{\sqrt{a}\left(\sqrt{a}+5\right)}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}-\dfrac{10\sqrt{a}}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}-\dfrac{5\left(\sqrt{a}-5\right)}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}\)
\(\Rightarrow A=\dfrac{a+5\sqrt{a}}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}-\dfrac{10\sqrt{a}}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}-\dfrac{5\sqrt{a}-25}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}\)
\(\Rightarrow A=\dfrac{a+5\sqrt{a}-10\sqrt{a}-5\sqrt{a}+25}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}\)
\(\Rightarrow A=\dfrac{a-10\sqrt{a}+25}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}\)
\(\Rightarrow A=\dfrac{\left(\sqrt{a}-5\right)^2}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}\)
\(\Rightarrow A=\dfrac{\sqrt{a}-5}{\sqrt{a}+5}\)
a: \(=\sqrt{3}+1+\sqrt{3}-1=2\sqrt{3}\)
b: \(A=\dfrac{a+5\sqrt{a}-10\sqrt{a}-5\sqrt{a}+25}{\left(\sqrt{a}-5\right)\left(\sqrt{a}+5\right)}=\dfrac{\left(\sqrt{a}-5\right)^2}{a-25}=\dfrac{\sqrt{a}-5}{\sqrt{a}+5}\)
a) − 3 5 ( 9 + 3 a + a 2 ) b) 2(b-4)(7b-2)