Tìm x , biết:
b. 4,775 − x = 4,775 + 3,6×( 0,01 − 1 100 )
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3,6 : 0,01 + 3,6 : 0,25 + 3,6 - 3,6 x 95
= 3,6 x 100 + 3,6 x 4 + 3,6 x 1 - 3,6 x 95
= 3,6 x (100 + 4 + 1 - 95)
= 3,6 x 10
= 36
a: =472x2+472x5+472x2=472x9=4248
b: =28,8+28,8-14,4=43,2
c: =2,4(6,2+3,8)=24
\(2x\left(x+3\right)-3\left(x^2+1\right)=x+1-x\left(x-2\right)\)
\(\Leftrightarrow2x^2+6x-3x^2-3=x+1-x^2+2x\)
\(\Leftrightarrow-x^2+6x-3=-x^2+3x+1\)
\(\Leftrightarrow3x=4\)
hay \(x=\dfrac{4}{3}\)
\(2x\left(x+3\right)-3\left(x^2+1\right)=x+1-x\left(x-2\right)\)
\(\Leftrightarrow2x^2+6x-3x^2-3=x+1-x^2+2x\)
\(\Leftrightarrow3x=4\Leftrightarrow x=\dfrac{4}{3}\)
\(35-5\left(x-1\right)=10\\ \Leftrightarrow35-5x+5=10\\ \Rightarrow40-5x=10\)
\(\Rightarrow-5x=10-40\\ \Rightarrow-5x=-30\\ \Rightarrow x=\dfrac{-30}{-5}=6\)
c)
\(24\left(x-16\right)=12^2\)
\(\Rightarrow24x-384=144\\ \Rightarrow24x=144+384\\ \Rightarrow24x=528\\ \Rightarrow x=\dfrac{528}{24}=22\)
d)
\(\left(x^2-10\right)\div5=3\\ \Rightarrow\left(x^2-10\right)=3\times5\\ \Rightarrow x^2-10=15\)
\(\Rightarrow x^2=15+10\\ \Rightarrow x^2=25\\ \Rightarrow x^2=5^2\Rightarrow x=5\)
\(\Leftrightarrow\dfrac{1}{2}x+\dfrac{2}{3}x-x=-4\Leftrightarrow\dfrac{3x+4x-6x}{6}=-\dfrac{24}{6}\)
\(\Rightarrow x=-24\)
b) 50-3(x+4)=14
3(x+4)=36
x+4=13
x=9
c)2⁸‐ⁿ+75=107
2⁸-ⁿ=32
2⁸-ⁿ=2⁵
8-x=5
x=3
b ) - 25 + ( - 16 + x ) = 0
( - 16 + x ) = 0 - ( - 25 )
- 16 + x = 25
x = 25 - ( - 16 )
x = 41
Vậy x = 41