Tìmx biết:
x/8=5/4
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X + 1+2+3+4+5-6-7-8-9=1-2-3-4-5+6+7+8+9
X+ (-15) = 17
X = 17-(-15)
X = 32
vậy x = 32
tk nha
Ta có :
\(x-\dfrac{8}{5}< -6\\ \Rightarrow x< -6+\dfrac{8}{5}\\ \Rightarrow x< -\dfrac{22}{5}=-4\dfrac{2}{5}\\ \Rightarrow-6< x< -1\dfrac{2}{5}\\ \Rightarrow x=-5\)
Vậy...
ở dòng -6<x<-1\(\dfrac{2}{5}\) thì số -1\(\dfrac{2}{5}\) lấy đâu ra thế bạn
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{8}{5}< -6\\-6< x\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x< -6+\dfrac{8}{5}\\x>-6\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x< -\dfrac{22}{5}\\x>-6\end{matrix}\right.\\ \Rightarrow-6< x< -\dfrac{22}{5}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{8}{7}\)
\(\frac{3}{2}x=\frac{8}{7}+\frac{11}{5}=\frac{117}{35}\)
\(x=\frac{117}{35}:\frac{3}{2}=\frac{78}{35}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{7}{8}.\frac{64}{49}\)
\(\frac{3}{2}x-\frac{11}{5}=\frac{8}{7}\)
\(\frac{3}{2}x=\frac{8}{7}+\frac{11}{5}\)
\(\frac{3}{2}x=\frac{117}{35}\)
\(x=\frac{117}{35}:\frac{3}{2}\)
\(x=\frac{78}{35}\)
\(\frac{5}{7}:x+\frac{4}{5}=\frac{1}{6}\)
\(\frac{5}{7}:x=\frac{1}{6}-\frac{4}{5}=-\frac{19}{30}\)
\(x=\frac{5}{7}:\frac{-19}{30}=-\frac{150}{133}\)
\(\frac{5}{7}:x+\frac{4}{5}=\frac{1}{6}\Rightarrow\frac{5}{7}:x=\frac{1}{6}-\frac{4}{5}=-\frac{19}{30}\Rightarrow x=\frac{5}{7}:-\frac{19}{30}=\frac{5}{7}.-\frac{30}{19}=-\frac{150}{133}\)
\(...\Rightarrow x+x+\dfrac{x}{43}+\dfrac{x}{8}=14+148+\dfrac{10}{30}+\dfrac{5}{95}\)
\(\Rightarrow\left(1+1+\dfrac{1}{43}+\dfrac{1}{8}\right)x=162+\dfrac{1}{3}+\dfrac{1}{19}\)
\(\Rightarrow\left(\dfrac{2.43.8}{43.8}+\dfrac{1.8}{43.8}+\dfrac{1.43}{43.8}\right)x=\dfrac{162.3.19}{3.19}+\dfrac{1.19}{3.19}+\dfrac{1.3}{19.3}\)
\(\Rightarrow\left(\dfrac{688}{344}+\dfrac{8}{344}+\dfrac{43}{344}\right)x=\dfrac{9234}{57}+\dfrac{19}{57}+\dfrac{3}{57}\)
\(\Rightarrow\dfrac{739}{344}x=\dfrac{9256}{57}\)
\(\Rightarrow x=\dfrac{9256}{57}:\dfrac{739}{344}=\dfrac{9256}{57}.\dfrac{344}{739}=\dfrac{\text{3184064}}{\text{42123}}\)
\(x^4-8=2x^2-12x\)
\(\Rightarrow x^4-8-2x^2+12x=0\)
\(\Rightarrow x^4-8-2x\left(x-6\right)=0\)
Từ đây bạn khai triển bằng cách đặt nhân tử chung nhé!
Chúc bạn học tốt!
x=10 nha
x là 10 nha