Tính
136 + − 36 − 15 + − 7 − 48 + 6 175 + − 175 − 327 + 1000 − 42 + + 18
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\(a,x:\left(354-293\right)=32\cdot6\\ \Leftrightarrow x:61=192\\ \Leftrightarrow x=11712\)
b, x : 65 = 36 dư 7
\(\Rightarrow x=36\cdot65+7\\ \Leftrightarrow x=2347\)
\(c,\left(376+534\right):x=175:35\\ \Leftrightarrow910:x=5\\ \Leftrightarrow x=182\\ d,5\cdot\left(4+6x\right)=290\\ \Leftrightarrow6x+4=58\\ \Leftrightarrow6x=54\\ \Leftrightarrow x=9\)
Bài 1:
a) Ta có: 49+(11-25)
=49+11-25
=24+11
=35
b) Ta có: \(-8+5\cdot\left(-9\right)\)
\(=-8-45\)
=-53
Bài 2:
a) Ta có: \(x-2=-6+17\)
\(\Leftrightarrow x-2=11\)
hay x=13
Vậy: x=13
b) Ta có: \(x+9=2-17\)
\(\Leftrightarrow x+9=-15\)
hay x=-24
Vậy: x=-24
dễ mà : a, 5 - ( 1997 - 2005 ) +1997
= ( 2005 + 5 ) - ( 1997 - 1997 )
= 2010 - 0
= 2010
a, 5 - (1997 -2005 ) + 1997
= 5 - 1997 + 2005 +1997
= (5 + 2005 ) - ( 1997 - 1997)
= 2010 - 0
= 2010
b, 4567 + (1234 - 4567 )-4
= 4567 + 1234 - 4567 -4
= (4567 - 4567 ) + (1234 - 4)
= 0 + 1230
= 1230
c, 173 - ( 36 + 173 ) + [(175 - 27 ) - 175 - ( -36 + 50 )]
= 173 - 36 - 173 + 175 - 27 - 175 - 36 - 50
= ( 173 - 173 ) + (175 - 175 ) - ( 36 + 36 ) - (27 + 50)
= 72 - 77
= -5
d, 3 . (25 : 5 - 14 : 2 ) - 5 . ( 6 : 2)
= 3 (-2) - 5 .3
= 3 ( -2 - 5 )
= 3 . (-7 )
= - 21
-173-(36+173)+(172-27)-(-36+50)=-173-36-173+36-50
=(-173-173)+(36-36)-50
=-346+0-50
=-346-50=-396
175 x 54 + 525 x 15 + 175
= 175 x 54 + 175 x (3 x 15) + 175
= 175 x 54 + 175 x 45 + 175
= 175 x (54 + 45 + 1) = 175 x 100 = 17500
a: \(65\cdot48+35\cdot48+12\cdot58-12\cdot38\)
\(=48\left(65+35\right)+12\left(58-38\right)\)
\(=48\cdot100+12\cdot20\)
\(=4800+240=5040\)
b: \(2018^2+\left\{15^2:\left[175-\left(2^3\cdot5^2-6\cdot25\right)\right]\right\}\)
\(=1+\left\{\dfrac{225}{175-\left(8\cdot25-150\right)}\right\}\)
\(=1+\dfrac{225}{175-\left(200-150\right)}\)
\(=1+\dfrac{225}{175-50}=1+\dfrac{225}{125}=1+\dfrac{5}{3}=\dfrac{8}{3}\)