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\(1)5-(1997-2005)+1997\)
\(=5-1997+2005+1997\)
\(=(-1997+1997)+(5+2005)\)
\(=0+2010\)
\(=2010\)
\(2)4567+(1234-4567)-4\)
\(=4567+1234-4567-4\)
\(=(4567-4567)+(1234-4)\)
\(=0+1230\)
\(=1230\)
-173-(36+173)+(172-27)-(-36+50)=-173-36-173+36-50
=(-173-173)+(36-36)-50
=-346+0-50
=-346-50=-396
\(5-\left(1997-2005\right)+1997\)
\(=5-1997+2005+1997\)
\(=2010\)
\(1579-\left(53+1579\right)-\left(-53\right)\)
\(=1579-53-1579+53\)
\(=0\)
\(-48-\left(357-48\right)+300\)
\(=\)\(-48-357+48+300\)
\(=-57\)
\(173-\left(36+173\right)+\left(175-27\right)-175-\left(-36+50\right)\)
\(=173-36-173+175-27-175+36-50\)
\(=-27-50\)
\(=-77\)
\(\)
\(-\left[-171+171+23\right]-\left[172-\left(38+172\right)\right]-49\)
\(=171-171-23-172+38+172-49\)
\(=-23+38-49=-34\)
Bài 1:
a) - | 12 - 14 | - | 98 - 15 + 2 | - 14
= - | - 2 | - | 85 | - 14
= -2 - 85 - 14
= -101
b) ( -24 ) - ( 12 - 19 ) - | 15 - 12 - 7 |
= ( -24 ) - ( - 7 ) - | -4 |
= ( -24 ) + 7 - 4
= -21
Bài 2:
a) 5 - ( 1997 - 2005 ) + 1997
= 5 - 1997 + 2005 + 1997
= ( 5 + 2005 ) + ( 1997 - 1997 )
= 2010 + 0
= 2010
b) 1579 - ( 53 + 1679 ) - ( -53 )
= 1579 - 53 - 1679 + 53
= ( 1579 - 1679 ) + ( 53 - 53 )
= ( -100 ) + 0
= -100
c) -48725 - ( 357 - 48725 ) + 300
= -48725 - 357 + 48725 + 300
= [( -48725 ) + 48725 ] + ( 357 - 300 )
= 0 + ( -57 )
= -57
d) 4567 + ( 1234 - 4567 ) - 4
= 4567 + 1234 - 4567 - 4
= ( 4567 - 4567 ) + ( 1234 - 4 )
= 0 + 1230
= 1230
a) \(-\left|12-14\right|-\left|98-15+2\right|-14\)
\(=-\left|2\right|-\left|85\right|-14\)
\(=\left(-2\right)-85-14\)
\(=\left(-2\right)-\left(85+14\right)\)
\(=\left(-2\right)-99\)
\(=\left(-2\right)+\left(-99\right)=-101\)
Câu 5:
a: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
b: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=\left(-12\right)\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
c: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot10=450\)
d: \(-48+48\left(-78\right)+48\left(-21\right)\)
\(=48\left(-1-78-21\right)\)
\(=48\left(-100\right)=-4800\)
Câu 4:
a: \(\left(-6-2\right)\left(-6+2\right)=\left(-8\right)\cdot\left(-4\right)=32\)
b: \(\dfrac{\left(7\cdot3-3\right)}{-6}=\dfrac{21-3}{-6}=\dfrac{18}{-6}=-3\)
c: \(\left(-5+9\right)\cdot\left(-4\right)=4\cdot\left(-4\right)=-16\)
d: \(\dfrac{72}{-6\cdot2+4}=\dfrac{72}{-12+4}=\dfrac{72}{-8}=-9\)
dễ mà : a, 5 - ( 1997 - 2005 ) +1997
= ( 2005 + 5 ) - ( 1997 - 1997 )
= 2010 - 0
= 2010
a, 5 - (1997 -2005 ) + 1997
= 5 - 1997 + 2005 +1997
= (5 + 2005 ) - ( 1997 - 1997)
= 2010 - 0
= 2010
b, 4567 + (1234 - 4567 )-4
= 4567 + 1234 - 4567 -4
= (4567 - 4567 ) + (1234 - 4)
= 0 + 1230
= 1230
c, 173 - ( 36 + 173 ) + [(175 - 27 ) - 175 - ( -36 + 50 )]
= 173 - 36 - 173 + 175 - 27 - 175 - 36 - 50
= ( 173 - 173 ) + (175 - 175 ) - ( 36 + 36 ) - (27 + 50)
= 72 - 77
= -5
d, 3 . (25 : 5 - 14 : 2 ) - 5 . ( 6 : 2)
= 3 (-2) - 5 .3
= 3 ( -2 - 5 )
= 3 . (-7 )
= - 21