Kết quả của phép chia ( 10 x 2 + 23 x – 5 ) : ( 2 x + 5 ) là:
A. 5x – 1
B. 5x + 1
C. 5x – 5
D. 5x + 5
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a)
<=> 10x - 35 + 16x - 10 = 5
<=> 10x + 16x = 5 + 35 + 10
<=> 26x = 50
<=> x = 50/26 = 25/13
A). (x^4+ax^2+1):(x^2+2x+1)
gọi g(x) là thương của phép chia (x^4+ax^2+1) cho (x^2+2x+1)
=>x^4+ax^2+1=(x^2+2x+1).g(x) đúng với mọi x
=>x^4+ax^2+1= (x+1)^2.g(x) đúng v mọi x
chọn x=-1=>(-1)^4+a.(-1)^2+1=0
=> 1+a+1=0=>a=-2
\(1)A=2x\left(x-y\right)-y\left(y-2x\right)\)
\(=2x^2-2xy-y^2+2xy\)
\(=2x^2-y^2=2.\left(-\dfrac{2}{3}\right)^2-\left(-\dfrac{1}{3}\right)^2\)
\(=\dfrac{8}{9}-\dfrac{1}{9}=\dfrac{7}{9}\)
\(2)B=5x\left(x-4y\right)-4y\left(y-5x\right)\)
\(=5x^2-20xy-4y^2+20xy\)
\(=5x^2-4y^2=5.\left(-\dfrac{1}{5}\right)^2-4.\left(-\dfrac{1}{2}\right)^2=\dfrac{1}{5}-1=-\dfrac{4}{5}\)
\(3)C=\text{x.(x^2-y^2)-x^2(x+y)+y(x^2-x)}\)
\(=x^3-xy^2-x^3-x^2y+x^2y-xy\)
\(=-xy\left(x+1\right)\)
1)
g) \(24+5x\text{=}7^5:7^3\)
\(24+5x\text{=}7^{5-3}\)
\(24+5x\text{=}7^2\text{=}49\)
\(5x\text{=}49-24\text{=}25\)
\(x\text{=}5\)
h) \(x:2^2\text{=}2^3\)
\(x\text{=}2^3.2^2\)
\(x\text{=}2^5\text{=}32\)
2)
a) \(2^{10}.8.2^3\text{=}2^{10}.2^3.2^3\text{=}2^{10+3+3}\text{=}2^{16}\)
\(b)3^5:27\text{=}3^5:3^3\text{=}3^{5-3}\text{=}3^2\)
\(c)5^2.125\text{=}5^2.5^3\text{=}5^{2+3}\text{=}5^5\)
\(d)6^6:36\text{=}6^6:6^2\text{=}6^{6-2}\text{=}6^4\)
1.
g) \(24+5x=7^5:7^3\left(=7^{5-3}\right)\) -> Trong ngoặc ko cần viết nha
\(24+5x=7^2=49\)
\(5x=49-24\)
\(5x=25\)
\(x=25:5\)
\(=>x=5\)
h) \(x:2^2=2^3\)
\(x=2^3.2^2\)
\(=>x=2^5\)
2.
a) \(2^{10}.8.2^3=2^{10}.\left(2^3\right)2^3=2^{10+3+3}=2^{16}\)
b) \(3^5:27=3^5:\left(3^3\right)=3^{5-3}=3^2\)
c) \(5^2.125=5^2.\left(5^3\right)=5^{2+3}=5^5\)
d) \(6^6:36=6^6:\left(6^2\right)=6^{6-2}=6^4\)
Công thức:
\(a^m.a^n=a^{m+n}\)
\(a^m:a^n=a^{m-n}\)
\(#Wendy.Dang\)
a: \(=\dfrac{5\left(x+2\right)}{10xy^2}\cdot\dfrac{12x}{x+2}=\dfrac{60x}{10xy^2}=\dfrac{6}{y^2}\)
b: \(=\dfrac{x-4}{3x-1}\cdot\dfrac{3\left(3x-1\right)}{\left(x-4\right)\left(x+4\right)}=\dfrac{3}{x+4}\)
c: \(=\dfrac{2\left(2x+1\right)}{\left(x+4\right)^2}\cdot\dfrac{\left(x+4\right)}{3\left(x+3\right)}=\dfrac{2\left(2x+1\right)}{3\left(x+3\right)\left(x+4\right)}\)
d: \(=\dfrac{5\left(x-1\right)}{3\left(x+1\right)}\cdot\dfrac{x+1}{x-1}=\dfrac{5}{3}\)
Chọn A
Thực hiện phép chia đa thức cho đa thức ta được:
(10x2 + 23x – 5) : (2x + 5) = 5x - 1