tìm x biết
\(\frac{2-3x}{x-2}=-1\frac{2}{5}\)
đúng mk tick cho
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\(\frac{2}{3}+\frac{8}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}+\frac{1}{3}\)
\(\frac{94}{105}< \frac{x}{105}< \frac{92}{105}\)
\(\Rightarrow94< x< 92\)
mà x là số tựu nhiên => \(x\in\varnothing\)
\(\frac{x-2}{2}-\frac{1+x}{3}=\frac{4-3x}{4}-1\)
\(\Leftrightarrow\frac{3\left(x-2\right)-2\left(1+x\right)}{6}=\frac{4-3x-4}{4}\)
\(\Leftrightarrow\frac{3x-6-2-2x}{6}=-\frac{3x}{4}\)
\(\Leftrightarrow\frac{x-8}{6}=-\frac{3x}{4}\)
\(\Leftrightarrow4x-32=-18x\)
\(\Rightarrow x=\frac{16}{11}\)
\(2^{3x+5}+5.2^{x+1}.2^{2x+3}+2^{3x}=904\)
\(\Leftrightarrow2^{3x}.2^5+5.2^{3x}.2^4+2^{3x}=904\)
\(\Leftrightarrow2^{3x}\left(2^5+5.2^4+1\right)=904\)
\(\Leftrightarrow8^x\left(32+80+1\right)=904\)
\(\Leftrightarrow8^x.113=904\)
\(\Leftrightarrow8^x=8\)
\(\Leftrightarrow x=1\)
V...
\(\frac{2-3x}{x-2}=-1\frac{2}{5}\)
\(\Rightarrow\frac{2-3x}{x-2}=\frac{-7}{5}\)
\(\Rightarrow5\left(2-3x\right)=-7\left(x-2\right)\)
\(\Rightarrow10-15x=-7x+14\)
\(\Rightarrow-15x+7x=14-10\)
\(\Rightarrow-8x=4\)
\(\Rightarrow x=\frac{-1}{2}\)
Vậy \(x=\frac{-1}{2}\)
\(\frac{2-3x}{x-2}=-1\frac{2}{5}\)ĐK : x khác 2
\(\Leftrightarrow\frac{2-3x}{x-2}=-\frac{7}{5}\Leftrightarrow10-15x=-7x+14\)
\(\Leftrightarrow-4-8x=0\Leftrightarrow x=-\frac{1}{2}\)