12 nh kjjnnn
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\(\dfrac{12}{1.5}+\dfrac{12}{5.9}+...+\dfrac{12}{93.97}+\dfrac{12}{97.101}\)
= \(3.\left(\dfrac{4}{1.5}+\dfrac{4}{5.9}+...+\dfrac{4}{93.97}+\dfrac{4}{97.101}\right)\)
= \(3.\left(1-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+...+\dfrac{1}{93}-\dfrac{1}{97}+\dfrac{1}{97}-\dfrac{1}{101}\right)\)
= \(3.\left(1-\dfrac{1}{101}\right)\)
= \(3.\dfrac{100}{101}\)
= \(\dfrac{300}{101}=2\dfrac{98}{101}\)
\(B=12+12^2+12^3+...+12^{99}\)
\(12B=12^2+12^3+12^4+...+12^{100}\)
\(11B=12B-B=12^{100}-12\)
\(\Rightarrow B=\dfrac{12^{100}-12}{11}\)
Vậy \(B=\dfrac{12^{100}-12}{11}\)
Tik mik nha!!!
B = 12 + 12.2 + ... + 12.99
= 12.(1 + 2 + ... + 99)
= 12.4950
= 59400
@Trần Huyền Trang
D= [(-5)+(-12)] +[(-12)+5] +[-5+12]
D= -17+ (-7)+ 7
D= -17
CHÚC BẠN HOK TỐT
1. x2 + x - 12 = x2 + 4x - 3x - 12
= x(x + 4) - 3(x + 4)
= (x - 3)(x + 4)
2. x2 - x - 12 = x2 - 4x + 3x - 12
= x(x - 4) + 3(x - 4)
= (x + 3)(x - 4)
3. x2 + 4x - 12 = x2 + 6x - 2x - 12
= x(x + 6) - 2(x + 6)
= (x - 2)(x + 6)
4. x2 + 8x + 15 = x2 + 3x + 5x + 15
= x(x + 3) + 5(x + 3)
= (x + 5)(x + 3)
5. 5x2 - 4x - 1 = 5x2 - 5x + x - 1
= 5x(x - 1) + (x - 1)
= (5x + 1)(x - 1)
x12 - 3x6y6 + y12
= ( x6)2 - 2x6y6 + ( y6)2 - ( x3y3)2
= ( x6 - y6)2 - ( x3y3)2
= ( x6 - y6 - x3y3)(x6 - y6 + x3y3)
a) \(\left(-17+\left|91\right|\right)-\left(91-\left|-17\right|-2011\right)\)
\(=\left(-17+91\right)-\left(91-17-2011\right)\)
\(=74-\left(74-2011\right)\)
\(=74-74+2011\)
\(=0+2011\)
\(=2011\)
b) \(\dfrac{4}{7}+\dfrac{5}{6}:5-0,375.\left(-2\right)^2\)
\(=\dfrac{4}{7}+\dfrac{1}{6}-\dfrac{3}{8}.4\)
\(=\dfrac{24}{42}+\dfrac{7}{42}-\dfrac{3}{2}\)
\(=\dfrac{31}{42}-\dfrac{63}{42}\)
\(=\dfrac{-16}{21}\)
c) \(\left(\dfrac{-17}{11}:\dfrac{5}{12}+\dfrac{-4}{12}:\dfrac{5}{12}\right).2.\dfrac{\left|-5\right|}{3}\)
\(=\left(\dfrac{-17}{11}+\dfrac{-4}{12}\right):\dfrac{5}{12}.\dfrac{2.\left|-5\right|}{3}\)
\(=\left(\dfrac{-204}{132}+\dfrac{-44}{132}\right):\dfrac{5}{12}.\dfrac{2.5}{3}\)
\(=\dfrac{-62}{33}:\dfrac{5}{12}.\dfrac{10}{3}\)
\(=\dfrac{-248}{55}.\dfrac{10}{3}\)
\(=\dfrac{-496}{33}\)
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https://iostudy.net/ref/132310
ai vào mình tích đúng 5 lần
a: \(=\dfrac{6}{4}\left(\dfrac{4}{4\cdot8}+\dfrac{4}{8\cdot12}+...+\dfrac{4}{76\cdot80}\right)\)
\(=\dfrac{3}{2}\left(\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{12}+...+\dfrac{1}{76}-\dfrac{1}{80}\right)\)
\(=\dfrac{3}{2}\cdot\dfrac{19}{80}=\dfrac{57}{160}\)
b: \(=2\left(\dfrac{6}{6\cdot12}+\dfrac{6}{12\cdot18}+...+\dfrac{6}{54\cdot60}\right)\)
\(=2\left(\dfrac{1}{6}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{18}+...+\dfrac{1}{54}-\dfrac{1}{60}\right)\)
\(=2\cdot\dfrac{9}{60}=\dfrac{18}{60}=\dfrac{3}{10}\)
kjjnnn là gì vậy