Rút gọn: (x-3)(x+7)-(x+5)(x-1)=?
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có: \(B=\left|x-\dfrac{1}{7}\right|-\left|x+\dfrac{3}{5}\right|+\dfrac{4}{5}\)
\(=-x+\dfrac{1}{7}-x-\dfrac{3}{5}+\dfrac{4}{5}\)
\(=-2x+\dfrac{12}{35}\)
a) ( x - 3 ) ( x + 7 ) - ( x + 5 ) ( x - 1 )
= ( x2 +7x - 3x - 21 ) - ( x2 -x + 5x - 5 )
= x2 + 4x -21 - x2 - 4x +5
= -16
a: Ta có: \(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)\)
\(=x^2+4x-21-x^2-4x+5\)
=-16
Câu 1. 3/2:5/4=? Nhớ rút gọn. Câu 2. Tìm x biết X x 18/5 = 7/10+3/5 nhớ rút gọn thank you các bạn🙏🏻😇
\(\frac{3}{2}:\frac{5}{4}=\frac{3}{2}\times\frac{4}{5}=\frac{12}{20}=\frac{3}{5}\)
X x 18/5 = 7/10 + 3/5
X x 18/5 = 13/10
X = 13/10 : 18/5
X = 13/36
k cho mik với
\(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)=x^2+7x-3x-21-x^2+x-5x+5\)
\(=-16\)
1: Ta có: \(x^2-2x+5-\left(x-7\right)\left(x+2\right)\)
\(=x^2-2x+5-x^2-2x+7x-14\)
\(=3x-9\)
2: Ta có: \(-5x\left(x-5\right)+\left(x-3\right)\left(x^2-7\right)\)
\(=-5x^2+25x+x^3-7x-3x^2+21\)
\(=x^3-8x^2+18x+21\)
3: Ta có: \(x\left(x^2-x-2\right)-\left(x+5\right)\left(x-1\right)\)
\(=x^3-x^2-2x-x^2-4x+5\)
\(=x^3-2x^2-6x+5\)
\(a,=5x-10+2x+6=7x-4\\ b,=x^2+2x+1-x^2+3x+10=5x+11\\ c,=x^2-49-x^2+1=-48\\ d,\text{Đề có sai ko vậy?}\)
\(\dfrac{45}{135}=\dfrac{45:45}{135:45}=\dfrac{1}{3}\)
\(\dfrac{117}{234}=\dfrac{117:117}{234:117}=\dfrac{1}{2}\)
\(\dfrac{1515}{2727}=\dfrac{1515:303}{2727:303}=\dfrac{5}{9}\)
\(\dfrac{232323}{494949}=\dfrac{232323:10101}{494949:10101}=\dfrac{23}{49}\)
\(\left(x-\dfrac{1}{3}\right)+\dfrac{1}{4}=\dfrac{1}{2}\)
\(x-\dfrac{1}{3}=\dfrac{1}{2}-\dfrac{1}{4}\)
\(x-\dfrac{1}{3}=\dfrac{2}{4}-\dfrac{1}{4}\)
\(x-\dfrac{1}{3}=\dfrac{1}{4}\)
\(x=\dfrac{1}{4}+\dfrac{1}{3}\)
\(x=\dfrac{3}{12}+\dfrac{4}{12}\)
\(x=\dfrac{7}{12}\)
\(x-\left(\dfrac{1}{7}+\dfrac{2}{5}\right)=\dfrac{16}{35}\)
\(x-\left(\dfrac{5}{35}+\dfrac{14}{35}\right)=\dfrac{16}{35}\)
\(x-\dfrac{19}{35}=\dfrac{16}{35}\)
\(x=\dfrac{16}{35}+\dfrac{19}{35}\)
\(x=\dfrac{35}{35}\)
\(x=1\)
\(x+\dfrac{3}{7}=\dfrac{2}{5}+\dfrac{3}{10}\)
\(x+\dfrac{3}{7}=\dfrac{4}{10}+\dfrac{3}{10}\)
\(x+\dfrac{3}{7}=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}-\dfrac{3}{7}\)
\(x=\dfrac{49}{70}-\dfrac{30}{70}\)
\(x=\dfrac{19}{30}\)
\(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)\)
\(=x^2+7x-3x-21-\left(x^2-x+5x-5\right)\)
\(=x^2+4x-21-x^2-4x+5\)
\(=-16\)