a)(x+1)(x+3)(x+5)(x+7) - 384
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1. \(x-8+32=68\)
\(x-8=68-32\)
\(x-8=36\)
\(x=36+8\)
\(x=44\)
_____
2. \(x+8+32=68\)
\(x+8=68-32\)
\(x+8=36\)
\(x=36-8\)
\(x=28\)
_____
3. \(98-x+34=43\)
\(98-x=43-34\)
\(98-x=9\)
\(x=98-9\)
\(x=89\)
_____
4. \(98+x-34=43\)
\(98+x=43+34\)
\(98+x=77\)
\(x=77-98\)
\(x=-21\)
_____
5. \(x:5:4=800\)
\(x:5=800.4\)
\(x:5=3200\)
\(x=3200.5\)
\(x=16000\)
_____
6. \(18+x=384:8\)
\(18+x=48\)
\(x=48-18\)
\(x=30\)
_____
7. \(\left(84,6-2\times x\right):3,02=5,1\)
\(84,6-2.x=5,1.3,02\)
\(84,6-2.x=15,402\)
\(2.x=84,6-15,402\)
\(2.x=69,198\)
\(x=69,198:2\)
\(x=34,599\)
_____
8. \(x\times5=120:6\)
\(x.5=20\)
\(x=20:5\)
\(x=4\)
_____
9. \(\left(15\times24-x\right):0,25=100:0,25\)
\(\left(15.24-x\right):0,25=400\)
\(15.24-x=400.0,25\)
\(15.24-x=100\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
1,x-8+32=68
=>x-8=68-32=36
=>x=36+8=42
2,x+8+32=68
=>x+8=68-32=36
=>x=36-8=28
3,98-x+34=43
=>98-x=43-34=9
=>x=98-9=89
4,98+x-34=43
=>98+x=43+34=77
=>x=77-98=-21
5,x:5:4=800
=>x:20=800
=>x=800x20=16000
6,18+x=384:8=48
=>x=48-18=30
7,(84,6-2x):3,02=5,1
=>84,6-2x=5,1x3,02=15,402
=>2x=84,6-15,402=69,198
=>x=69,198:2=34,599
8,5x=120:6=20
=>x=20:5=4
9,(15x24-x):0,25=100:0,25=400
=>360-x=400x0,25=100
=>x=360-100=260.
<(x-1)(x+1)(x+3)(x+5)-384=0
<=>(x-1)(x+5)(x+1)(x+3)-384=0
<=>(x2+4x-5)(x2+4x+3)-384=0
đặt y=x2+4x-5 ta được:
y(y+8)-384=0
<=>y2+8y-384=0
<=>y2-16y+24y-384=0
<=>y(y-16)+24(y-16)=0
<=>(y-16)(y+24)=0
<=>y-16=0 hoặc y+24 =0
<=>y=16 hoặc y=-24
thay y=x2+4x-5 ta được
x2+4x-5=16 hoặc x2+4x-5=-24
<=>x2+4x-21=0 hoặc x2+4x+19=0
mà x2+4x+19=x2+4x+4+15=(x+2)2+15>0
loại x2+4x+19=0
=>x2+4x-21=0
<=>x2+7x-3x-21=0
<=>x(x+7)-3(x+7)=0
<=>(x+7)(x-3)=0
<=>x=-7 hoặc x=3
vậy S={-7;3}
a: \(\Leftrightarrow2^x\cdot2\cdot2^{-2}\cdot5=384\)
\(\Leftrightarrow2^x\cdot\dfrac{5}{2}=384\)
\(\Leftrightarrow2^x=153,6\)(vô lý)
b: Sửa đề:\(3^{x+2}\cdot5^y=45^x\)
\(\Leftrightarrow3^{x+2}\cdot5^y=3^{2x}\cdot5^x\)
=>x=y và 2x=x+2
=>x=y=2
xin lỗi các bạn là toán lớp 7 nha mình chân thành xin lỗi
a: =>(x-5)^3+1/16=31/64
=>(x-5)^3=31/64-4/64=27/64
=>x-5=3/4
=>x=5,75
b: =>x-2,5=2/3 hoặc x-5/2=-2/3
=>x=19/6 hoặc x=11/6
c: =>\(5\cdot2^x-2^x=384\)
=>2^x*4=384
=>2^x=96
hay \(x\in\varnothing\)
d: =>x+2=4
=>x=2
a, đầu bài sai hay sao đó bn
b,\(\dfrac{2}{3}\).3x+1 - 7.3x = -405
3x(\(\dfrac{2}{3}\).3 - 7) = -405
3x . (-5) = -405
3x = 81 mà 81 = 34 suy ra x = 4
Câu x ) là bằng - 5 nhé mấy bạn. Làm giúp mình tất cả nhé ! Mình cảm ơn nhiều lắm !
a/ \(\frac{2}{3}.3^{x+1}-7.3^x=405\)
<=> 2.3x-7.3x=-405
<=> 5.3x=405
<=> 3x=81 = 34
=> x=4
b/ (0,4x-1,3)2=5,29=(2,3)2
=> \(\hept{\begin{cases}0,4x-1,3=2,3\\0,4x-1,3=-2,3\end{cases}}\)=> \(\hept{\begin{cases}x=9\\x=-\frac{5}{2}\end{cases}}\)
c/ 5.2x+1.2-2-2x=384
<=> 5.2x-1-2.2x-1=384
<=> 3.2x-1=384
<=> 2x-1=128=27
=> x-1=7 => x=8
d/ 3x+2.5y=45x
<=> 3x+2.5y=32x.5x
=> \(\hept{\begin{cases}x+2=2x\\x=y\end{cases}}\)=> x=y=2
a) Ta có: \(\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)-384\)
\(=\left[\left(x+1\right)\left(x+7\right)\right]\left[\left(x+3\right)\left(x+5\right)\right]-384\)
\(=\left(x^2+8x+7\right)\left(x^2+8x+15\right)-384\)
\(=\left(x^2+8x\right)^2+22\left(x^2+8x\right)+105-384\)
\(=\left(x^2+8x\right)^2+22\left(x^2+8x\right)-279\)
\(=\left(x^2+8x\right)^2+31\left(x^2+8x\right)-9\left(x^2+8x\right)-279\)
\(=\left(x^2+8x\right)\left(x^2+8x+31\right)-9\left(x^2+8x+31\right)\)
\(=\left(x^2+8x+31\right)\left(x^2+8x-9\right)\)
\(=\left(x^2+8x+31\right)\left(x+9\right)\left(x-1\right)\)