(290-x).4=400
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Đặt \(B=\dfrac{19}{1}+\dfrac{18}{2}+\dfrac{17}{3}+...+\dfrac{3}{17}+\dfrac{2}{18}+\dfrac{1}{19}\)
\(=\left(\dfrac{18}{2}+1\right)+\left(\dfrac{17}{3}+1\right)+...+\left(\dfrac{2}{18}+1\right)+\left(\dfrac{1}{19}+1\right)+1\)
\(=\dfrac{20}{2}+\dfrac{20}{3}+...+\dfrac{20}{17}+\dfrac{20}{18}+\dfrac{20}{19}+\dfrac{20}{20}\)
\(=20\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{18}+\dfrac{1}{19}+\dfrac{1}{20}\right)\)
\(\Rightarrow A=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{18}+\dfrac{1}{19}+\dfrac{1}{20}}{20\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{18}+\dfrac{1}{19}+\dfrac{1}{20}\right)}=\dfrac{1}{20}\)
Vậy \(A=\dfrac{1}{20}\)
400/ {5.[360-(290+2.5 mũ 2)]} =400/ {5.[360-(290+2.25)]} =400/{5.[360-(290+50)]} =400/{5.[360-340]} =400/{5.20} =400/100 =4
5 x ( 4 + 6 x X ) = 290
( 4 + 6 x X ) = 290 : 5
4 + 6 x X = 58
6 x X = 58 - 4
6 x X = 54
X = 54 : 6
X = 9
\(400\div\left\{5\left[360-\left(290+2.5^2\right)\right]\right\}\)
\(=400\div\left\{5\left[360-\left(290+50\right)\right]\right\}=400\div\left[5\left(360-340\right)\right]\)
\(=400\div\left(5.20\right)=400\div100=4\)
Bài giải
\(400\text{ : }\left[5\left\{360-\left(290+2\cdot5^2\right)\right\}\right]\)
\(=400\text{ : }\left[5\left\{360-\left(290+50\right)\right\}\right]\)
\(=400\text{ : }\left[5\left\{360-340\right\}\right]\)
\(=400\text{ : }\left[5\cdot20\right]\)
\(=400\text{ : }100\)
\(=4\)
5 x ( 4 + 6 x X ) = 290
4 + 6 x X = 290 : 5
4 + 6 x X = 58
6 x X = 58 - 4
6 x X = 54
X = 54 : 6
X = 9
Học tốt #
5 x (4+6 x X)=290
(4+6 x X)=290:5
(4+6 x X)=58
6 x X=58-4
6 x X=54
X=54:6
X=9
Tk mk nha chúc bạn học tốt!!
Ủng hộ mk nha mọi người!!
400 : { 5. [ 360 - ( 290 + 2.52 ) ] }
=400:{5.[360-(290+50)]}
=400:[5.(360-340)]
=400:(5.20)
=400:100
=4
TÍCH NHA
400: {5.[360-(290+2.52)]}
=400: {5.[360-(290+2.25)]}
=400: {5.[360-(290+50)]}
=400: {5.[360-340]}
=400: {5.20}
=400:100
=4
5 x ( 4 + 6 . x ) = 290
4 + 6 . x = 290 : 5
4 + 6 . x = 58
6 . x = 58 - 4
6 . x = 54
x = 54 : 6
x = 9
Vậy x = 9
245,7 - 58+ 0,3= 4 x ( x:4 + 2,7)
188= 4x( x:4 + 2,7)
4x ( x:4 + 2,7)= 188
(x:4 + 2,7) = 188 :4
(x:4 +2,7)= 47
(x:4) = 47 - 2,7
(x:4) =44,3
x = 44,3 x 4
x= 177,2
Ta có: \(\left(290-x\right)\cdot4=400\)
\(\Leftrightarrow290-x=100\)
hay x=190
Vậy:x=190