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a) \(7^2-7\left(13-x\right)=14\)
\(7\left(13-x\right)=49-14=35\)
\(13-x=5\)
\(x=13-5=8\)
b) \(5x-5^2=10\)
\(5x=10+25=35\)
\(x=7\)
c) \(4\left(x-5\right)-2^3=2^4.3=48\)
\(4\left(x-5\right)=48+8=56\)
\(x-5=14\)
\(x=19\)
4:
a: \(\Leftrightarrow49+7\left(x-13\right)=14\)
=>7(x-13)=35
=>x-13=5
=>x=18
b: \(5x-5^2=10\)
=>\(5x=10+25=35\)
=>x=7
c: \(4\left(x-5\right)-2^3=2^4\cdot3\)
=>\(4\left(x-5\right)=16\cdot3+8=56\)
=>x-5=14
=>x=19
Câu 4 :
\(n_{Fe2O3}=\dfrac{24}{160}=0,15\left(mol\right)\)
Pt : \(Fe_2O_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+3H_2O|\)
1 3 1 3
0,15 0,15
a) \(n_{Fe2\left(SO4\right)3}=\dfrac{0,15.1}{1}=0,15\left(mol\right)\)
⇒ \(m_{Fe2\left(SO4\right)3}=0,15.400=60\left(g\right)\)
b) \(C_{M_{Fe2\left(SO4\right)3}}=\dfrac{0,15}{0,5}=0,3\left(M\right)\)
Chúc bạn học tốt
a,\(n_{Fe_2O_3}=\dfrac{24}{160}=0,15\left(mol\right)\)
PTHH: Fe2O3 + 3H2SO4 → Fe2(SO4)3 + 3H2O
Mol: 0,15 0,45 0,15
\(m_{Fe_2\left(SO_4\right)_3}=0,15.400=60\left(g\right)\)
b,\(C_{M_{ddFe_2\left(SO_4\right)_3}}=\dfrac{0,15}{0,5}=0,3\left(mol\right)\)
Câu 9:
a) Ta có: \(9x^2-16=0\)
\(\Leftrightarrow\left(3x-4\right)\left(3x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{4}{3}\end{matrix}\right.\)
b) Ta có: \(4x^2=13\)
\(\Leftrightarrow x^2=\dfrac{13}{4}\)
\(\Leftrightarrow x\in\left\{\dfrac{\sqrt{13}}{2};-\dfrac{\sqrt{13}}{2}\right\}\)
c) Ta có: \(2x^2+9=0\)
\(\Leftrightarrow2x^2=-9\)(Vô lý)
d) Ta có: \(-x^2+324=0\)
\(\Leftrightarrow x^2=324\)
\(\Leftrightarrow\left[{}\begin{matrix}x=18\\x=-18\end{matrix}\right.\)
1 It is 78 for males and 85 for females
2 It is made from Soybeans
3 It contains less fat
4 Seafood like fish and vegetables