3^2 * 22-3^3 * 19
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a,25/100 +19/22+19/35+3/4+3/22+16/35
=(19/22+3/22)+(19/35+16/35)+(25/100+3/4)
= 22/22 + 35/35 + ( 1/4 + 3/4)
= 22/22 + 35/35 + 4/4
= 1 + 1 + 1
= 3
b, 2/5 : 4/7 - 2/5 : 2/3
=(2/5 - 2/5) : (4/7 : 2/3)
= 0 : 6/7
=0
( 99 - 1 ) : 2 + 1 = 50 ( số )
làm bừa thui,ai tích mình mình tích lại
Số số hạng là :
Có số cặp là :
50 : 2 = 25 ( cặp )
Mỗi cặp có giá trị là :
99 - 97 = 2
Tổng dãy trên là :
25 x 2 = 50
Đáp số : 50
\(3^2.x-22=2^2.2^3\Leftrightarrow9x-22=4.8\)
\(\Leftrightarrow9x-22=32\Leftrightarrow9x=32+22\)
\(\Leftrightarrow9x=54\Leftrightarrow x=54:9\)
\(\Leftrightarrow x=6\)
Vậy x = 6
\(3^2.22-3^3.19=3^2.\left(22-19.3\right)\)
\(=3^2.\left(22-57\right)\)
\(=9.\left(-35\right)\)
\(=-315\)
= \(3^2x22-3^3x19=3^2x22-3^2x3x19=3^2x\left(22-19x3\right)=9x\left(-35\right)=\left(-315\right)\)
2:
a: =4+3/8+5+2/3
=9+3/8+2/3
=216/24+9/24+16/24
=216/24+25/24
=241/24
b; =2+3/8+1+1/4+3+6/7
=6+3/8+1/4+6/7
=6+5/8+6/7
=419/56
c: \(=2+\dfrac{3}{8}-1-\dfrac{1}{4}+5+\dfrac{1}{3}\)
=6+3/8-1/4+1/3
=6+1/8+1/3
=6+11/24
=155/24
d: \(=3+\dfrac{5}{6}+6\cdot\dfrac{13}{6}\)
=3+13+5/6
=16+5/6
=101/6
e: =3+1/2+4+5/7-5-5/14
=3+4-5+1/2+5/7-5/14
=2+7/14+10/14-5/14
=2+12/14
=2+6/7=20/7
f: =9/2+1/2:11/2
=9/2+1/11
=99/22+2/22=101/22
2:
a: =4+3/8+5+2/3
=9+3/8+2/3
=216/24+9/24+16/24
=216/24+25/24
=241/24
b; =2+3/8+1+1/4+3+6/7
=6+3/8+1/4+6/7
=6+5/8+6/7
=419/56
c: \(=2+\dfrac{3}{8}-1-\dfrac{1}{4}+5+\dfrac{1}{3}\)
=6+3/8-1/4+1/3
=6+1/8+1/3
=6+11/24
=155/24
d: \(=3+\dfrac{5}{6}+6\cdot\dfrac{13}{6}\)
=3+13+5/6
=16+5/6
=101/6
e: =3+1/2+4+5/7-5-5/14
=3+4-5+1/2+5/7-5/14
=2+7/14+10/14-5/14
=2+12/14
=2+6/7=20/7
f: =9/2+1/2:11/2
=9/2+1/11
=99/22+2/22=101/22
a) \(\dfrac{\dfrac{3}{14}-\dfrac{3}{17}+\dfrac{3}{19}}{\dfrac{5}{19}+\dfrac{5}{14}-\dfrac{5}{17}}=\dfrac{3\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}{5\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}=\dfrac{3}{5}\)
c) \(\dfrac{\dfrac{2}{7}+\dfrac{2}{5}+\dfrac{2}{17}-\dfrac{2}{193}}{\dfrac{3}{7}+\dfrac{3}{5}+\dfrac{3}{17}-\dfrac{3}{293}}=\dfrac{2\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}{3\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}=\dfrac{2}{3}\)
d)
\(=3^2.22-3^3.19\)
\(=3^2.22-3^2.57\)
\(=3^2\left(22-57\right)\)
\(=3^2.-35\)
\(=-9.35=-315.\)