giúp mình giải câu hỏi này:
455 + (241 - x) = 652
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\(-2,5\times\left(x+\dfrac{1}{5}\right)=\dfrac{7}{5}\)
\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}:\left(-2,5\right)\)
\(\Leftrightarrow x+\dfrac{1}{5}=\dfrac{7}{5}\times\left(-\dfrac{2}{5}\right)\)
\(\Leftrightarrow x+\dfrac{1}{5}=-\dfrac{14}{25}\)
\(\Leftrightarrow x=-\dfrac{19}{25}\)
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Làm thế này nhé
(2x-6)y+x-3=18
(2x-6)y+x-18-3=0
(2x-6)y+x-21=0
sau đó bạn rút gọn nhé, ta làm như sau
2(x-3)=0
=> 2x= 2 x 3
=> x=3 nhé
giúp mình llàm câu b với nhé đã k cho bạn rồi nha
b, y = \(\frac{23}{x+7}\)
455 + (241 - x) = 652
241 - x = 652 - 455
241 - x = 197
x = 241 - 197
x = 44
Hok tốt
455 + (241 - x) = 652
241 - x = 652 - 455
241 - x = 197
x = 241 - 197
x = 44
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