tìm x
4/3x X 125 = 1000
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chú ý:(x là x cần tìm,còn X là dấu nhân)
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\(\frac{2}{3}x\times125=1000\)
\(\frac{2}{3}x\) \(=1000\div125\)
\(\frac{2}{3}x\) \(=8\)
\(x\) \(=8\div\frac{2}{3}\)
\(x\) \(=8\times\frac{3}{2}\)
\(x\) \(=12\)
Bài làm
\(\frac{2}{3}x\times125=1000\)
\(\frac{2}{3}x=\frac{1000}{125}\)
\(\frac{2}{3}x=8\)
\(x=8:\frac{2}{3}\)
\(x=8X\frac{3}{2}\)
\(x=\frac{24}{2}\)
\(x=12\)
Vậy x = 12
a) \(\left(5x+3^4\right).6^8=6^9.3^4\)
\(=>6x+3^4=3^4.6^9:6^8\)
\(=>6x+3^4=3^4.6\)
\(=>6x=6.3^4-3^4\)
\(=>6x=0\)
\(=>x=0:6\)
\(=>x=0\)
a/(5x + 34).68=69.34
(5x + 34) = 69:68.34
5x + 81 = 6.81
5x = 6.81 - 81
5x = 486 - 81
5x = 425
x = 425:5
x = 85
b/92 - 2x = 2.42- 3.4 + 120:15
92 - 2x = 2.16 - 12 + 8
92 - 2x = 32 - 12 + 8
92 - 2x = 28
2x = 92 - 28
2x = 64
x = 64:2
x = 32
c/53.(3x + 2) : 13 = 103: (135:134)
125.(3x + 2) : 13 = 1000:13
125.(3x+2) = 1000:13.13
125.(3x+2) = 1000
3x + 2 = 1000:125
3x + 2 = 8
3x = 8 - 2
3x = 6
x = 6:3
x = 2
Bạn nhớ tick cho mình nhé!
\(\frac{2}{5}.\frac{1}{x}+\frac{1}{x}.2+\frac{2}{5}=0,5\)
\(\Rightarrow\frac{2}{5x}+\frac{2}{x}+\frac{2}{5}=\frac{1}{2}\)
\(\Rightarrow2.\left(\frac{1}{5x}+\frac{1}{x}+\frac{1}{5}\right)=\frac{1}{2}\)
\(\Rightarrow\frac{1}{5x}+\frac{5}{5x}+\frac{x}{5x}=\frac{1}{2}:2=\frac{1}{4}\)
\(\Rightarrow\frac{1+5+x}{5x}=\frac{1}{4}\)
\(\Rightarrow4.\left(1+5+x\right)=5x\)
\(\Rightarrow4+20+4x=5x\)
\(\Rightarrow24+4x=5x\)
\(\Rightarrow5x-4x=24\)
\(\Rightarrow x=24\)
a) 5.(x-20) = 35
(x-20) = 35:5
x-20 = 7
x = 27
b) (x+125) -301 = 56
x+125 -301 = 56
x - 176 = 56
x = 56 +176
x= 232
c) 215 + (x-21):2 = 235
(x-21):2 = 235 - 215
(x-21):2 = 20
x-21 = 20 .2
x-21 = 40
x = 61
d) (x:23 +45) .67 = 8911
(x:23 +45) = 8911 : 67
x:23+45 = 133
x:23 = 133-45
x:23 = 88
x = 88.23
x = 2024
a) 5.(x - 20) = 35
⇒ x - 20 = 35 : 5
⇒ x - 20 = 7
⇒ x = 7 + 20
⇒ x = 27
b) (x + 125) - 301 = 56
⇒ x + 125 = 56 + 301
⇒ x + 125 = 357
⇒ x = 357 - 125
⇒ x = 232
c) 215 + (x - 21) : 2 = 235
⇒ (x - 21) : 2 = 235 - 215
⇒ (x - 21) : 2 = 20
⇒ x - 21 = 20 x 2
⇒ x - 21 = 40
⇒ x = 21 + 40
⇒ x = 61
d) (x : 23 + 45).67 = 8911
⇒ x : 23 + 45 = 8911 : 67
⇒ x : 23 + 45 = 133
⇒ x : 23 = 133 - 45
⇒ x : 23 = 88
⇒ x = 88 x 23
⇒ x = 2024
a, (\(x+4\)) ⋮ (\(x\) + 1) đk \(x\) \(\in\) Z; \(x\ne\) -1
\(\left(x+1\right)+3\) ⋮ (\(x+1\))
3 ⋮ \(x\) + 1
\(x+1\) \(\in\) Ư(3) = {-3; -1; 1; 3}
Lập bảng ta có:
\(x+1\) | -3 | -1 | 1 | 3 |
\(x\) | -4 | -2 | 0 | 2 |
Theo bảng trên ta có
\(x\) \(\in\) {-4; -2; 0; 2}
\(3x.\left(x-\frac{11}{7}\right)=0\)
=> \(\orbr{\begin{cases}3x=0\\x-\frac{11}{7}=0\end{cases}}=>\orbr{\begin{cases}x=0\\x=\frac{11}{7}\end{cases}}\)
Chú ý :
Dấu \(.\)là dấu nhân đấy
\(1.x^2+11x=0\)
\(\Leftrightarrow x\left(x+11\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+11=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-11\end{cases}}\)
\(2.\left(x^2-1\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)\left(x+9\right)\left(x-9\right)=0\)
chia thành 4 TH :
\(TH1:X-1=0\)
\(\Leftrightarrow x=1\)
\(TH2:x+1=0\)
\(\Leftrightarrow x=-1\)
\(TH3:X+9=0\)
\(\Leftrightarrow X=-9\)
\(TH4:x-9=0\)
\(\Leftrightarrow x=9\)
Kết luận ....
\(3.\left(\left|x+1\right|-5\right)\left(x^2-9\right)\)
\(\Leftrightarrow\left(\left|x+1\right|-5\right)\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}\left|x+1\right|-5=0\\x-3=0\\x+3=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}\left|x+1\right|=5\\x=3\\x=-3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x+1=+_-5\Leftrightarrow x+1=5,x+1=-5\Leftrightarrow x=4,x=-6\\x=3x\\x=-3\end{cases}}\)
kết luận x=.....
\(4.\left(3x-16\right)⋮\left(x+2\right)\)
\(\Leftrightarrow\left(3x+6\right)-22\)
\(\Leftrightarrow3\left(x+2\right)-22⋮\left(x+2\right)\)
Vì\(\left(x+2\right)⋮\left(x+2\right)\)
\(\Rightarrow\left(3x-16\right)⋮\left(x+2\right)\)
Kết luận x=.....
a)
x= 43
b) 2X-12=8
2X =8+12
2X=20
X=20:2
x =10
c)45:(3X-17)=32
45 : (3X-17)=9
3X-17=45:9
3X-17=5
3X=5+17
3X=22
x=22:3
x= 7,33
d)(2X-8)x2=24
( 2X-8)x2 =16
2X-8 =16:2
2X-8 =8
2X =8+8
2X =16
x =16:2
X =8
Đúng thì tk nếu sai thì thôi
Làm ẩu ^^
\(4,3x\times125=1000\)
=> \(4,3x=1000:125\)
=> \(4,3x=8\)
=> \(x=\frac{8}{4,3}=\frac{8}{\frac{43}{10}}=8\cdot\frac{10}{43}=\frac{80}{43}\)
\(\frac{4}{3}x\times125=1000\)
\(\frac{4}{3}x=1000:125\)
\(\frac{4}{3}x=8\)
\(x=8:\frac{4}{3}\)
\(x=6\)
Vậy : x = 6