x / 6 = 98 dư 4
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1. \(x-8+32=68\)
\(x-8=68-32\)
\(x-8=36\)
\(x=36+8\)
\(x=44\)
_____
2. \(x+8+32=68\)
\(x+8=68-32\)
\(x+8=36\)
\(x=36-8\)
\(x=28\)
_____
3. \(98-x+34=43\)
\(98-x=43-34\)
\(98-x=9\)
\(x=98-9\)
\(x=89\)
_____
4. \(98+x-34=43\)
\(98+x=43+34\)
\(98+x=77\)
\(x=77-98\)
\(x=-21\)
_____
5. \(x:5:4=800\)
\(x:5=800.4\)
\(x:5=3200\)
\(x=3200.5\)
\(x=16000\)
_____
6. \(18+x=384:8\)
\(18+x=48\)
\(x=48-18\)
\(x=30\)
_____
7. \(\left(84,6-2\times x\right):3,02=5,1\)
\(84,6-2.x=5,1.3,02\)
\(84,6-2.x=15,402\)
\(2.x=84,6-15,402\)
\(2.x=69,198\)
\(x=69,198:2\)
\(x=34,599\)
_____
8. \(x\times5=120:6\)
\(x.5=20\)
\(x=20:5\)
\(x=4\)
_____
9. \(\left(15\times24-x\right):0,25=100:0,25\)
\(\left(15.24-x\right):0,25=400\)
\(15.24-x=400.0,25\)
\(15.24-x=100\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
1,x-8+32=68
=>x-8=68-32=36
=>x=36+8=42
2,x+8+32=68
=>x+8=68-32=36
=>x=36-8=28
3,98-x+34=43
=>98-x=43-34=9
=>x=98-9=89
4,98+x-34=43
=>98+x=43+34=77
=>x=77-98=-21
5,x:5:4=800
=>x:20=800
=>x=800x20=16000
6,18+x=384:8=48
=>x=48-18=30
7,(84,6-2x):3,02=5,1
=>84,6-2x=5,1x3,02=15,402
=>2x=84,6-15,402=69,198
=>x=69,198:2=34,599
8,5x=120:6=20
=>x=20:5=4
9,(15x24-x):0,25=100:0,25=400
=>360-x=400x0,25=100
=>x=360-100=260.
\(8\left(x+9\right)+4\left(6-x\right)=98\)
\(\Rightarrow8x+72+24-4x=98\)
\(\Rightarrow4x+98=98\)
\(\Rightarrow4x=98-98\)
\(\Rightarrow4x=0\Rightarrow x=0\)
8(x + 9) + 4(6 - x) + 2 = 98
8x + 72 + 4(6 - x) + 2 = 98
8x + 72 + 4(-x + 6) + 2 = 98
8x + 72-4x + 24 + 2 = 98
8x + 98 -4x = 98
4x + 98 = 98
4x + 98-98 = 98-98
4x = 98 - 98
4x = 0
4x/4 = 0/4
x = 0/4
x = 0
=2x(2/2x4+2/4x6+...+2/96x98
=2x(1/2-1/4+1/4-1/6+...+1/96-/98)
=2x(1/2-1/98)
=2x24/49
=48/49
tick nha
Một ô tô cứ chạy 50km thì dùng hết 4 lít xăng. Hỏi nếu ô tô đó chạy quãng đường 250km thì dùng hết bao nhiêu lít xăng? *
\(\Rightarrow6P=2.4.6+4.6.6+...+98.100.6\)
\(=2.4.6+4.6.\left(8-2\right)+...+98.100.\left(102-96\right)\)
\(=2.4.6+4.6.8-2.4.6+...+98.100.102-96.98.100\)
\(=98.100.102\)
\(\Rightarrow P=\frac{98.100.102}{2}=499800\)
Nhầm phải là \(\frac{98.100.102}{6}=166600\)
xin lỗi ghi nhầm
Tính tổng : 1 x 2 + 2 x 4 + 4 x 6 + .........+ 98 x 100
Gọi biểu thức trên là A, ta có :
A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100
A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
A x 3 = 99x100x101
A = 99x100x101 : 3
A = 333300
(1-2+3-4+.....-98+99)x(2013x6-2013-2013x5)
=(1-2+3-4+....-98+99)x[ 2013x(6-1-5)]
= (1-2+3-4+....-98+99)x(2013x0)
= (1-2+3-4+....-98+99)x0 = 0
x : 6 = 98 dư 4
x = 98 x 6 + 4
x = 592
Bạn nhé