24÷2×3+14
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Phương pháp giải:
- Muốn tìm một số hạng ta lấy tổng trừ đi số hạng kia.
- Muốn tìm một thừa số ta lấy tích chia cho thừa số kia.
Lời giải chi tiết:
a)● y + 2 = 14
y = 14 − 2
y = 12
● y × 2 = 14
y = 14:2
y = 7
b)● y + 3 = 24
y = 24 − 3
y = 21
● y × 3 = 24
y = 24 : 3
y = 8
d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37
=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37
=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37
=43/37.1+31/37=43/37.1+31/37
=2=2
E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12
=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12
=−5/24.1+7/12=−5/24.1+7/12
=3/8=3/8
a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7
=3/7−−11/14−2=3/7−−11/14−2
=3/7+11/14−2=3/7+11/14−2
=−11/14=−11/14
b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14
=4/5−3/7=4/5−3/7
=13/35
d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37
=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37
=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37
=43/37.1+31/37=43/37.1+31/37
=2=2
E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12
=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12
=−5/24.1+7/12=−5/24.1+7/12
=3/8=3/8
a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7
=3/7−−11/14−2=3/7−−11/14−2
=3/7+11/14−2=3/7+11/14−2
=−11/14=−11/14
b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14
=4/5−3/7=4/5−3/7
=13/35
\(a.\)
\(x+\left(-17\right)=-24\)
\(\Leftrightarrow x=-24+17=-7\)
\(b.\)
\(\dfrac{3}{7}x-\dfrac{1}{2}=\dfrac{3}{14}\)
\(\Leftrightarrow\dfrac{3}{7}x=\dfrac{3}{14}-\dfrac{1}{2}=\dfrac{3}{14}-\dfrac{7}{14}=-\dfrac{2}{7}\)
\(\Leftrightarrow x=-\dfrac{2}{7}:\dfrac{3}{7}=-\dfrac{2}{3}\)
Ta có: \(\dfrac{9^{14}\cdot225^2\cdot8^7}{18^{12}\cdot625^3\cdot24^3}\)
\(=\dfrac{3^{32}\cdot5^4\cdot2^{21}}{2^{12}\cdot3^{14}\cdot5^{12}\cdot2^9\cdot3^3}\)
\(=\dfrac{3^{15}}{5^8}\)
14/16:(-2/3+1/4).2-14/24
=14/16:-5/12.2-14/24
=-21/10.2-14/24
=-21/5-14/24
=-287/60
14/-16:(-2/3+1/4)2-14/24
=-7/8:(-8/12+3/12)2-7/12
=-7/8:(5/12)2-7/12
=-7/8:25/144-7/12
=-126/25+-7/12
=-1512/300=-175/300
=-1687/300
Ta có:
\(\dfrac{1}{20}=\dfrac{1}{4}-\dfrac{1}{5}\)
\(\dfrac{1}{14}=\dfrac{1}{10}-\dfrac{1}{35}\)
\(\dfrac{1}{56}=\dfrac{1}{7}-\dfrac{1}{8}\)
Thay vào ta được:
\(2 + \dfrac{1}{4}+ \dfrac{3}{4} - \dfrac{3}{5}+\dfrac{1}{10} + \dfrac{1}{10} - \dfrac{1}{35}+ \dfrac{3}{7} - \dfrac{3}{8} + \dfrac{1}{24} \)
\(= 3 - \dfrac{2}{5} - \dfrac{1}{35} + \dfrac{3}{7} - \dfrac{3}{8}+ \dfrac{1}{24} \)
\(= 3 + \dfrac{1}{35} - \dfrac{1}{35} + \dfrac{1}{24} - \dfrac{3}{8} \)
\(= 3 + \dfrac{1}{24} - \dfrac{3}{8}\)
\(= 2 + \dfrac{5}{8}+ \dfrac{1}{24} \)
\(= 2 + \dfrac{1}{8} (5 + \dfrac{1}{3}) \)
\(= 2 + \dfrac{16}{24} \)
\(=2+\dfrac{2}{3}\)
\(=\dfrac{8}{3}\)
Bài làm:
Ta có: \(\left(\frac{1}{2}x+\frac{3}{4}\right)^2\div\left(-\frac{3}{14}\right)=-\frac{7}{24}\)
\(\Leftrightarrow\left(\frac{1}{2}x+\frac{3}{4}\right)^2=\frac{1}{16}=\left(\frac{1}{4}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x+\frac{3}{4}=\frac{1}{4}\\\frac{1}{2}x+\frac{3}{4}=-\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x=-\frac{1}{2}\\\frac{1}{2}x=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=-2\end{cases}}\)
(\(\frac{1}{2}\).x+\(\frac{3}{4}\))2: \(\frac{-3}{14}\)=\(\frac{-7}{24}\)
(\(\frac{1}{2}\).x+\(\frac{3}{4}\))2 =\(\frac{1}{16}\)
(\(\frac{1}{2}\).x+\(\frac{3}{4}\))2=(\(\frac{1}{4}\))2
\(\hept{\begin{cases}\frac{1}{2}.x+\frac{3}{4}=\frac{1}{4}\\\frac{1}{2}.x+\frac{3}{4}=\frac{-1}{4}\end{cases}}\)<=>\(\hept{\begin{cases}\frac{1}{2}.x=\frac{1}{4}-\frac{3}{4}\\\frac{1}{2}.x=\frac{-1}{4}-\frac{3}{4}\end{cases}}\)<=>\(\hept{\begin{cases}\frac{1}{2}.x=-\frac{1}{2}\\\frac{1}{2}.x=-1\end{cases}}\)
<=>\(\hept{\begin{cases}x=\frac{-1}{2}:\frac{1}{2}=-1\\x=-1:\frac{1}{2}=-2\end{cases}}\)
\(24\div2\times3+14\)
\(=12\times3+14\)
\(=36+14\)
\(=50\)
\(.\)
24 : 2 x 3 + 14
= 12 x 3 + 14
= 36 + 14
= 50
#HOCTOT#