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\(24\div2\times3+14\)

\(=12\times3+14\)

\(=36+14\)

\(=50\)

\(.\)

5 tháng 5 2020

24 : 2 x 3 + 14

= 12 x 3 + 14

= 36 + 14

= 50

#HOCTOT#

24 tháng 8 2019

Phương pháp giải:

- Muốn tìm một số hạng ta lấy tổng trừ đi số hạng kia.

- Muốn tìm một thừa số ta lấy tích chia cho thừa số kia. 

Lời giải chi tiết:

a)● y + 2 = 14

      y = 14 − 2

      y = 12

  ● y × 2 = 14

       y = 14:2

       y = 7

b)● y + 3 = 24

      y = 24 − 3

      y = 21

   ● y × 3 = 24

       y = 24 : 3

       y = 8

17 tháng 4 2020

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

17 tháng 4 2020

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

16 tháng 12 2015

= [ 32.(14+31) - 45] . [ 32.(25-24) ]

= ( 32 . 45 - 45 ) . (32.1)

= 45.(32-1) . 32

= 45.8.9

= 3240

11 tháng 3 2021

\(a.\)

\(x+\left(-17\right)=-24\)

\(\Leftrightarrow x=-24+17=-7\)

\(b.\)

\(\dfrac{3}{7}x-\dfrac{1}{2}=\dfrac{3}{14}\)

\(\Leftrightarrow\dfrac{3}{7}x=\dfrac{3}{14}-\dfrac{1}{2}=\dfrac{3}{14}-\dfrac{7}{14}=-\dfrac{2}{7}\)

\(\Leftrightarrow x=-\dfrac{2}{7}:\dfrac{3}{7}=-\dfrac{2}{3}\)

Ta có: \(\dfrac{9^{14}\cdot225^2\cdot8^7}{18^{12}\cdot625^3\cdot24^3}\)

\(=\dfrac{3^{32}\cdot5^4\cdot2^{21}}{2^{12}\cdot3^{14}\cdot5^{12}\cdot2^9\cdot3^3}\)

\(=\dfrac{3^{15}}{5^8}\)

15 tháng 7 2021

\(\dfrac{9^{14}.225^2.8^7}{18^{12}.625^3.24^3}=\dfrac{3^{28}.3^2.5^2.2^{21}}{2^{12}.3^{24}.5^{12}.2^9.3^3}=\dfrac{3^3}{5^{10}}\)

17 tháng 9 2017

14/16:(-2/3+1/4).2-14/24

=14/16:-5/12.2-14/24

=-21/10.2-14/24

=-21/5-14/24

=-287/60

4 tháng 11 2017

14/-16:(-2/3+1/4)2-14/24

=-7/8:(-8/12+3/12)2-7/12

=-7/8:(5/12)2-7/12

=-7/8:25/144-7/12

=-126/25+-7/12

=-1512/300=-175/300

=-1687/300

11 tháng 8 2017

Ta có:

\(\dfrac{1}{20}=\dfrac{1}{4}-\dfrac{1}{5}\)

\(\dfrac{1}{14}=\dfrac{1}{10}-\dfrac{1}{35}\)

\(\dfrac{1}{56}=\dfrac{1}{7}-\dfrac{1}{8}\)

Thay vào ta được:

\(2 + \dfrac{1}{4}+ \dfrac{3}{4} - \dfrac{3}{5}+\dfrac{1}{10} + \dfrac{1}{10} - \dfrac{1}{35}+ \dfrac{3}{7} - \dfrac{3}{8} + \dfrac{1}{24} \)

\(= 3 - \dfrac{2}{5} - \dfrac{1}{35} + \dfrac{3}{7} - \dfrac{3}{8}+ \dfrac{1}{24} \)

\(= 3 + \dfrac{1}{35} - \dfrac{1}{35} + \dfrac{1}{24} - \dfrac{3}{8} \)

\(= 3 + \dfrac{1}{24} - \dfrac{3}{8}\)

\(= 2 + \dfrac{5}{8}+ \dfrac{1}{24} \)

\(= 2 + \dfrac{1}{8} (5 + \dfrac{1}{3}) \)

\(= 2 + \dfrac{16}{24} \)

\(=2+\dfrac{2}{3}\)

\(=\dfrac{8}{3}\)

15 tháng 8 2020

Bài làm:

Ta có: \(\left(\frac{1}{2}x+\frac{3}{4}\right)^2\div\left(-\frac{3}{14}\right)=-\frac{7}{24}\)

\(\Leftrightarrow\left(\frac{1}{2}x+\frac{3}{4}\right)^2=\frac{1}{16}=\left(\frac{1}{4}\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x+\frac{3}{4}=\frac{1}{4}\\\frac{1}{2}x+\frac{3}{4}=-\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}\frac{1}{2}x=-\frac{1}{2}\\\frac{1}{2}x=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=-2\end{cases}}\)

15 tháng 8 2020

(\(\frac{1}{2}\).x+\(\frac{3}{4}\))2: \(\frac{-3}{14}\)=\(\frac{-7}{24}\)
  (\(\frac{1}{2}\).x+\(\frac{3}{4}\))=\(\frac{1}{16}\)
   (\(\frac{1}{2}\).x+\(\frac{3}{4}\))2=(\(\frac{1}{4}\))2
\(\hept{\begin{cases}\frac{1}{2}.x+\frac{3}{4}=\frac{1}{4}\\\frac{1}{2}.x+\frac{3}{4}=\frac{-1}{4}\end{cases}}\)<=>\(\hept{\begin{cases}\frac{1}{2}.x=\frac{1}{4}-\frac{3}{4}\\\frac{1}{2}.x=\frac{-1}{4}-\frac{3}{4}\end{cases}}\)<=>\(\hept{\begin{cases}\frac{1}{2}.x=-\frac{1}{2}\\\frac{1}{2}.x=-1\end{cases}}\)
<=>\(\hept{\begin{cases}x=\frac{-1}{2}:\frac{1}{2}=-1\\x=-1:\frac{1}{2}=-2\end{cases}}\)