125-43-7.(-2)
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\(A=\frac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{43}}\)
\(A=\frac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{43}}\)
\(A=\frac{5^{30}.7^{48}.2^8.\left(1-7.2^2\right)}{5^{29}.2^8.7^{43}}=5.7^3.\left(1-7.2^2\right)=1715.\left(-27\right)=-46305\)
\(A=\frac{\left(7^2\right)^{24}.\left(5^3\right)^{10}.2^8-5^{30}.7^{49}.\left(2^2\right)^5}{5^{29}\left(2^4\right)^2.7^{43}}=\frac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{43}}=\frac{7^{48}.5^{30}.2^8\left(1-7.2^2\right)}{5^{29}.2^8.7^{43}}\)
=\(7^5.5.\left(-27\right)=-2268945\)
a,57*43-57*30-43*57-43*30
=(57*43-57*43)-(57*30-43*30)
=0-30(57-43)
=0-30*14
=0-420
=-420
b,[125*(-8)]*[(-79)*1]
=-1000*-79
=79000
câu c mik thấy như này thì đúng hơn!!!!
c,1-3+5-7+...+2009-2011
=(1-3)+(5-7)+...+(2009-2011)
1006 số hạng
=(-2)+(-2)+...+(-2)
503 số hạng
=(-2)*503=-1006
Bài 1:
a: =25+75=100
b: =60-17-43+12=12
c: =-2-18=-20
d: =-3+36-17=36-20=16
Bài 2:
a: =-102
b: =-1000
c: =12x15=180
d: =21x(-10)=-210
\(=125\left(\dfrac{1}{93}+\dfrac{1}{43}\right)=125\cdot\dfrac{136}{3999}=\dfrac{17000}{3999}\)
e, (-25).(-13).8.(-4).125
= (-25).(-4).8.125.(-13)
= 100.1000.(-13)=-1300000
f, 38.(-43)+43.(-79)-(-43).17
= 38.(-43)+(-43).79-(-43).17
= (-43).(38+79-17)
= (-43).100=-4300
a) ( -7) . 11 + 7 . ( - 89 )
= 7 . (-11) + 7 . (-89)
= 7 . [(-11)+(-89)]
= 7 . (-100)
= -700
\(2018\times\frac{3}{4}+2018\times\frac{1}{4}-2018\)
\(=2018\times\left(\frac{3}{4}+\frac{1}{4}-1\right)\)
\(=2018\times0=0\)
B-a:tương tự bài A
b,\(\frac{14}{18}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)
\(=\frac{7}{9}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)
\(=\frac{7}{9}\times\left(\frac{8}{5}-\frac{3}{5}\right)\)
\(=\frac{7}{9}\times1=\frac{7}{9}\)\
thanks
B-a,\(\frac{3\times125+3\times125}{6\times43+6\times57}=\frac{2\times3\times125}{6\times\left(43+57\right)}\)
\(=\frac{3\times250}{6\times100}=\frac{5}{2\times2}=\frac{5}{4}\)
thanks
43x125-125:52
=64x125-125:25
=64x125-125x\(\dfrac{1}{25}\)
=125(64-\(\dfrac{1}{25}\))=125x\(\dfrac{1599}{25}\)=7995.
\(31.82+125.48+31.43+125.67\)
\(=31.\left(82+43\right)+125.\left(48+67\right)\)
\(=31.125+125.115\)
\(=125.\left(31+115\right)\)
\(=125.146\)
\(=18250\)
Ủng hộ mk nha ^_^
96
Ta có: \(125-43-7\cdot\left(-2\right)\)
\(=125-43+14=96\)