2016-100.(x+11)=27:23
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VM
1
TT
21 tháng 9 2023
a) 2016 - 100.(x+31)=27:23
<=> 2016 - 100.(x+31) = 24 = 16
<=> 100.(x+31) = 2016 - 16 = 2000
<=> x+31 = 2000:100 = 20
<=> x = 20 - 31 = -11
b) (x+8)3 = 125
<=> (x+8)3 = 53
<=> x+8 = 5
<=> x = 5 - 8
<=> x = -3
18 tháng 1 2016
a, <=> (x-5/100) -1 +(x-4/101) -1 +(x-3/102) -1= (x-100/5) -1+(x-101/4) -1 +(x-102/3) -1
<=> (x-105)(1/100 +1/101 +1/102)= (x-105)(1/5+1/4+1/3)
<=> (x-105)(1/100+1/101+1/102-1/5-1/4-1/3)=0
vì 1/100+1/101+1/102-1/5-1/4-1/3 khác 0 <=> x-105=0
<=> x=105
18 tháng 1 2016
b, 29-x/21 +1+27-x/23 +1+25-x/25 +1+23-x/27 +1+21-x/29 +1=0
<=> 50-x/21 +50-x/23 +50-x/25 +50-x/27 +50-x/29=0
<=> (50-x)(1/21 +1/23 +1/25 +1/27 +1/29)=0
vì 1/21+1/23+1/25+1/27+1/29 lớn hơn 0
nên 50-x=0
<=> x=50
TT
13 tháng 9 2021
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27 tháng 3 2019
a. = 23 . (55-45) + 230
= 23 . 10 +230
= 230 + 230
= 460
b. = 71 . (66 - 41 - 1)
= 71 . 24
= 1704
c. = 50 . (11 + 22) - 100
= 50 . 33 - 100
= 1650 - 100
= 1550
d. = 27. (54 - 50) + 50
= 27 . 4 + 50
= 108 + 50
= 158
27 tháng 3 2019
a) 23.55-45.23+230
=23.(55-45)+230
=23.10+230
=230+230
=460
b) 71.66-41.71-71
=71.(66-41-1)
=71.24
=1704
c) 11.50+50.22-100
=50.(11+22)-100
=50.33-100
=1550
d) 54.27-27.50+50
=27.(54-50)+50
=27.4+50
=108+50
=158
# Bé_Bông #
26 tháng 7 2019
\(\frac{34}{11}\cdot\frac{27}{46}\cdot\frac{23}{17}\cdot\frac{22}{9}\)
\(=\frac{34\cdot27\cdot23\cdot22}{11\cdot46\cdot17\cdot9}\)
\(=\frac{2\cdot17\cdot3\cdot3\cdot3\cdot23\cdot2\cdot11}{11\cdot2\cdot23\cdot17\cdot3\cdot3}\)
\(=\frac{3\cdot2}{1}\)
\(=6\)
=))
PT
1
CM
30 tháng 8 2019
= 1 - 1 3 + 1 3 - 1 5 + 1 5 - 1 7 + 1 7 - 1 11 + 1 11 = 1 - 1 11 = 10 11
DN
25 tháng 12 2017
a) \(\frac{x-5}{100}+\frac{x-4}{101}+\frac{x-3}{102}=\frac{x-100}{5}+\frac{x-101}{4}+\frac{x-102}{3}\)
\(\Leftrightarrow\left(\frac{x-5}{100}-1\right)+\left(\frac{x-4}{101}-1\right)+\left(\frac{x-3}{102}-1\right)=\left(\frac{x-100}{5}-1\right)+\left(\frac{x-101}{4}-1\right)+\left(\frac{x-102}{3}-1\right)\)
\(\Leftrightarrow\frac{x-105}{100}+\frac{x-105}{101}+\frac{x-105}{102}=\frac{x-105}{5}+\frac{x-105}{4}+\frac{x-105}{3}\)
\(\Leftrightarrow\left(x-105\right)\left(\frac{1}{100}+\frac{1}{101}+\frac{1}{102}-\frac{1}{5}-\frac{1}{4}-\frac{1}{3}\right)=0\)
\(\Leftrightarrow x=105\)
b) \(\frac{29-x}{21}+\frac{27-x}{23}+\frac{25-x}{25}+\frac{23-x}{27}+\frac{21-x}{29}=-5\)
\(\Leftrightarrow\left(\frac{29-x}{21}+1\right)+\left(\frac{27-x}{23}+1\right)+\left(\frac{25-x}{25}+1\right)+\left(\frac{23-x}{27}+1\right)+\left(\frac{21-x}{29}+1\right)=0\)
\(\Leftrightarrow\frac{50-x}{21}+\frac{50-x}{23}+\frac{50-x}{25}+\frac{50-x}{27}+\frac{50-x}{29}=0\)
\(\Leftrightarrow\left(50-x\right)\left(\frac{1}{21}+\frac{1}{23}+\frac{1}{25}+\frac{1}{27}+\frac{1}{29}\right)=0\)
\(\Leftrightarrow x=50\)
2016 - 100. (x+11)= \(2^7:2^3\)
<=> 2016 - 100 (x+11) = 16
<=> 100(x+11)= 2000
<=> x+11= 10
<=> x = -1
Vậy ...
2016-100.(x+11)=27 : 23
<=>2016 -100x-1100=24
<=>-100x=16+1100-2016
<=> -100x=-900
<=> x=9