23+3x=5^6:5^3 cam on ae
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c)3(2x-1)-5(x-3)+6(3x-4)=24
<=>6x-3-5x-15+18x-24=24
<=>19x-12=24
<=>19x=36
<=>x=\(\frac{36}{19}\)
d)2x(5-3x)+2x(3x-5)-3(x-7)=3
<=>10x-6x2+6x2-10x-3x-21=3
<=>-3(x-7)=3
<=>21-3x=3
<=>-3x=-18
<=>x=6
1: x^2-9+3x(x-3)
=(x-3)(x+3)+3x(x-3)
=(x-3)(x+3+3x)
=(4x+3)(x-3)
2: =x^4+5x^2+4x+5
=x^4+x^3+x^2-x^3-x^2-x+5x^2+5x+5
=(x^2+x+1)(x^2-x+5)
3: =x^4+2x^2+1-x^2
=(x^2+1)^2-x^2
=(x^2-x+1)(x^2+x+1)
1) \(x^2-9+3x\left(x-3\right)\)
\(=\left(x^2-9\right)+3x\left(x-3\right)\)
\(=\left(x+3\right)\left(x-3\right)+3x\left(x-3\right)\)
\(=\left(x-3\right)\left(x+3+3x\right)\)
\(=\left(x-3\right)\left(4x+3\right)\)
2) \(x^4+5x^2+4x+5\)
\(=x^4+x^3+x^2-x^3-x^2-x+5x^2+5x+5\)
\(=x^2\left(x^2+x+1\right)-x\left(x^2+x+1\right)+5\left(x^2+x+1\right)\)
\(=\left(x^2-x+5\right)\left(x^2+x+1\right)\)
3) \(x^4+x^2+1\)
\(=x^4+x^3+x^2-x^3-x^2-x+x^2+x+1\)
\(=x^2\left(x^2+x+1\right)-x\left(x^2+x+1\right)+\left(x^2+x+1\right)\)
\(=\left(x^2-x+1\right)\left(x^2+x+1\right)\)
23 + 3x = 56 : 53
23 + 3x = 53
23 + 3x = 125
3x = 125 : 23
3x = 102
x = 102 : 3
x = 34
23 + 3x = 56 : 53
23 + 3x = 53
23 + 3x = 125
3x = 125 - 23
3x = 102
x = 102 : 3
x = 34
23+3x=5 mũ 6:5 mũ 3
23+3x=5 mũ 3
23+3x=125
3x=125-23
3x=102
x=102:3
x=34
23+3x=53
23+3x=125
3x=125-23
3x=102
x=102:3
x=34
chúc bạn học tốt!
23+3x=15625:125
23+3x=125
3x=125-23
3x=102
x=102:3
x=34