-12 + ( x - 6)+ 5 = 12
|x|+(-12)=6-18
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5 x 6 = 30 2 x 6 = 12 3 x 6 = 18 4 x 6 = 24
6 x 5 = 30 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24
\(\frac{8}{12}\cdot x\cdot4-\frac{18}{12}\cdot x\cdot6=\frac{5}{12}\)
\(x\left(\frac{8}{12}\cdot4-\frac{18}{12}\cdot6\right)=\frac{5}{12}\)
\(x\left(\frac{32}{12}-\frac{108}{12}\right)=\frac{5}{12}\)
\(x\left(-\frac{19}{3}\right)=\frac{5}{12}\)
\(x=\frac{5}{12}\div\left(-\frac{19}{3}\right)=-\frac{5}{76}\)
Vậy \(x=-\frac{5}{76}\)
Chúc bạn học tốt ^^!!!
`a)`
`6 \times 1 = 6`
`6 \times 4 = 24`
`6 \times 6 = 36`
`b)`
`12 \div 6 = 2`
`18 \div 6 = 3`
`48 \div 6 = 8`
`c)`
`6 \times 5 = 30`
`30 \div 6 = 5`
`30 \div 5 = 6`
a, \(\dfrac{5\times11\times15\times18}{6\times15\times22\times10}\)
= \(\dfrac{5\times11\times15\times6\times3}{6\times15\times11\times2\times2\times5}\)
= \(\dfrac{5\times11\times15\times6}{5\times11\times15\times6}\) \(\times\) \(\dfrac{3}{2\times2}\)
= 1 \(\times\) \(\dfrac{3}{4}\)
= \(\dfrac{3}{4}\)
b, \(\dfrac{7}{12}\) \(\times\) \(\dfrac{3}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{5}{12}\)
= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{7}{12}+\dfrac{5}{12}\))
= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{12}{12}\)
= \(\dfrac{3}{5}\) \(\times\) 1
= \(\dfrac{3}{5}\)
1: Ta có: \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
\(\Leftrightarrow5x+20+12x-28=7x+2\)
\(\Leftrightarrow17x-7x=2+8=10\)
hay x=1
2: Ta có: \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
\(\Leftrightarrow\dfrac{6x}{36}+\dfrac{4\left(1-3x\right)}{36}=\dfrac{3\left(-x+1\right)}{36}\)
\(\Leftrightarrow6x+4-12x=-3x+3\)
\(\Leftrightarrow-6x+3x=3-4\)
hay \(x=\dfrac{1}{3}\)
3: Ta có: \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
\(\Leftrightarrow4x-12-x-2=6x-3\)
\(\Leftrightarrow3x-14-6x+3=0\)
\(\Leftrightarrow-3x=11\)
hay \(x=-\dfrac{11}{3}\)
4: Ta có: \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
\(\Leftrightarrow3x-6-8x-12=x+6\)
\(\Leftrightarrow-5x-x=6+18\)
hay x=-4
5: Ta có: \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
\(\Leftrightarrow6x-3+2x-6=-1\)
\(\Leftrightarrow8x=8\)
hay x=1
\(\frac{3}{3.6.9}+\frac{3}{6.9.12}+\frac{3}{9.12.15}+\frac{3}{12.15.18}=\frac{3}{6}\left(\frac{6}{3.6.9}+\frac{6}{6.9.12}+\frac{6}{9.12.15}+\frac{6}{12.15.18}\right)\)
= \(\frac{1}{2}\left(\frac{1}{3.6}-\frac{1}{6.9}+\frac{1}{6.9}-\frac{1}{9.12}+\frac{1}{9.12}-\frac{1}{12.15}+\frac{1}{12.15}-\frac{1}{15.18}\right)\)
\(=\frac{1}{2}\left(\frac{1}{3.6}-\frac{1}{15.18}\right)=\frac{1}{2}.\frac{14}{270}=\frac{7}{270}\)
1) 3(x - 4) - (8 - x) = 12
3x - 12 - 8 + x = 12
4x - 20 = 12
4x = 12 + 20
4x = 32
x = 8
2) 5(x - 6) - 2(x + 3) = 12
5x - 30 - 2x - 6 = 12
3x - 36 = 12
3x = 12 + 36
3x = 48
x = 16
3) 5 - | x + 7| = 4
|x + 7| = 4 - 5
|x + 7| = -1 x + 7 = 1; -1 x + 7 = 1 hoặc x + 7 = -1 x = 1 - 7 x = -1 - 7 x = -6 x = -8 => x = -6 hoặc x = -8 4) 6|x - 7| = 18 : (-3) 6|x - 7| = -6 6|x - 7| = -6 : 6 |x - 7| = -1 x - 7 = 1; -1 x - 7 = 1 hoặc x - 7 = -1 x = 1 + 7 x = -1 + 7 x = 8 x = 6 => x = 8 hoặc x = 6