-12.(x-5)+7.(3-x)=5
Giải cho mik nha.Thanks
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1 - 2/7 = 7/7 - 2/7 = 5/7
15/42 - 2/7 = 15/42 - 12/47 = 3/47
6/5 x 3 = 18/5
7/3 x 2/5 = 14/15
`1-2/7=7/7-1/7=6/7`
`15/42-2/7=15/42-12/42=3/42=1/14`
`6/5xx3=(6xx3)/5=18/5`
`7/3xx2/5=(7xx2)/(3xx5)=14/15`
\(\dfrac{4}{5}\times\dfrac{5}{8}=\dfrac{20}{40}=\dfrac{1}{2}\)
\(\dfrac{7}{15}+\dfrac{4}{5}=\dfrac{7}{15}+\dfrac{12}{15}=\dfrac{19}{15}\)
\(\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)
\(\dfrac{1}{2}\div\dfrac{2}{5}=\dfrac{1}{2}\times\dfrac{5}{2}=\dfrac{5}{4}\)
x + 3/4 x 7/10 = 53/40
x + 21/40 = 53/40
x = 53/40 - 21/40
x = 32/40
x = 4/5
34/35 : x = 17/5
x = 34/35 : 17/5
x = 34/35 x 5/17
x = 2/7
x + 3/4 x 7/10 = 53/40
x + ( 3/4 x 7/10 ) = 53/40
x + 21/40 = 53/40 ( tới đây bn cứ lm như bth )
x = 53/40 - 21/40
x = 4/5
34/35 : x = 17/5
x = 34/35 : 17/5
x = 2/7
a) \(\left(x+5\right)+9-x=x+2\)
\(\Leftrightarrow\left(x+5\right)+9-x-\left(x+2\right)=0\)
\(\Leftrightarrow x+5+9-x-x-2=0\)
\(\Leftrightarrow12-x=0\)
\(\Leftrightarrow x=12-0\)
\(\Leftrightarrow x=12\)
Vậy x=12
b) \(x+5+9-x=x+2\)
\(\Leftrightarrow x+5+9-x-\left(x+2\right)=0\)
\(\Leftrightarrow x+5+9-x-x-2=0\)
\(\Leftrightarrow12-x=0\)
\(\Leftrightarrow x=12-0\)
\(\Leftrightarrow x=12\)
Vậy x=12
c) \(x+5+x-9=x+2\)
\(\Leftrightarrow x+5+x-9-\left(x+2\right)=0\)
\(\Leftrightarrow x+5+x-9-x-2=0\)
\(\Leftrightarrow x-6=0\)
\(\Leftrightarrow x=6+0\)
\(\Leftrightarrow x=6\)
Vậy x=6
9/13 x 7/12 + 9/13 x 5/12 - 9/13
= 9/13 x (7/12 + 5/12 - 1)
= 9/13 x 0
= 0
4/13 x 5/12 + 4/13 x 7/12 - 4/3
= 4/13 x (5/12 + 7/12) - 4/3
= 4/13 x 1 - 4/3
= 4/13 - 4/3
= -40/39
CJ ẤY IU 1 NG HC Ở LƯƠNG THẾ VINH Đ KO
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