62 : ( x - 5)
tìm x
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- 62 + x = ( - 14 ) + 46 - x
x + x = ( - 14 ) + 46 + 62
2x = 94
x = 47
\(-62+x=\left(-14\right)+46-x\\ \Rightarrow x-62=32-x\\ \Rightarrow x-62-32+x=0\\ \Rightarrow2x-94=0\\ \Rightarrow2x=94\\ \Rightarrow x=47\\ b,5^{x+2}-5^x=10^2.6\\ \Rightarrow25.5^x-5^x=100.6\\ \Rightarrow24.5^x=600\\ \Rightarrow5^x=25\\ \Rightarrow5^x=5^2\\ \Rightarrow x=2\)
`(x+2)+(x+5)+(x+8)+.....+(x+62)=714`
`=>(x+x+....+x)+(2+5+8+....+62)=714`
Từ 2 đến 62 có 21 số nên cũng có 21 x
`=>21x+((2+62).21)/2=714`
`=>21x+(64.21)/2=714`
`=>21x+32.21=714`
`=>21x+672=714`
`=>21x=714-672=42`
`=>x=42:21=2`
Vậy `x=2`
(x+2)+(x+5)+(x+8)+...+(x+62)=714 [ (62-2):3+1=21 hạng tử ]
= 21x X + (62-2):2 x 21= 714
<=> 21 x X + 630=714
<=>21x X= 714-630= 84
<=>X=84:21=4
Vậy: x=4
( x -4 ) x3 + 7 = 240
(x-4) x 3= 240 -7
(x-4) x 3 = 233
x-4= 233/3
x= 233/3 +4
x= 245/3
3 x ( X - 5 ) + 8 x X = 62
3 x X + 8 x X - 15 = 62
11 x X = 62 + 15
11 x X = 77
X=77:11
X=7
\(\left(x-4\right)\times3+7=240\)
\(\left(x-4\right)\times3=233\)
\(x-4=\dfrac{233}{3}\)
\(x=\dfrac{233}{3}+4\)
\(x=\dfrac{245}{3}\)
\(3\times\left(x-5\right)+8\times x=62\)
\(3\times x-15+8\times x=62\)
\(3\times x+8\times x=77\)
\(11\times x=77\)
\(x=\dfrac{77}{11}=7\)
\(x\) + \(x\) + \(x\) + \(x\) = 100
\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 = 100
\(x\) \(\times\) ( 1 + 1 + 1 + 1 + 1 ) = 100
\(x\) \(\times\) 5 = 100
\(x\) = 100 : 5
\(x\) = 20
\(x\) + \(x\) + \(x\) + \(x\) \(\times\) 5 = 200
\(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\)1 + \(x\) \(\times\) 5 = 200
\(x\) \(\times\) ( 1 + 1 + 1 + 5) = 200
\(x\) \(\times\) 8 = 200
\(x\) = 200 : 8
\(x\) = 25
(\(x\) + 1) + (\(x\) + 4) + ( \(x\) + 7) + (\(x\) + 10) = 62
\(x\) + 1 + \(x\) + 4 + \(x\)+ 7 + \(x\) + 10 = 62
( \(x\) + \(x\) + \(x\) + \(x\) ) + ( 1 + 4 + 7 + 10) = 62
( \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1 + \(x\) \(\times\) 1) + 22 = 62
\(x\) \(\times\) ( 1 + 1 + 1 + 1) + 22 = 62
\(x\) \(\times\) 4 + 22 = 62
\(x\) \(\times\) 4 = 62 - 22
\(x\) \(\times\) 4 = 40
\(x\) = 40 : 4
\(x\) = 10
c: -62+x=-14+46
=>\(x-62=46-14=32\)
=>\(x=32+62=94\)
d: \(25+\left(x-5\right)=-123-\left(15-123\right)\)
=>\(x-5+25=-123-15+123\)
=>\(x+20=-15\)
=>\(x=-15-20=-35\)
a) x × 5 = 50 – 15
x × 5 = 35
x = 35 : 5
x = 7
b) x : 4 = 38 – 33
x : 4 = 5
x = 5 × 4
x = 20
c) x + 356 = 414 + 62
x + 356 = 476
x = 476 – 356
x = 120
d) x : 4 = 2 × 3
x : 4 = 6
x = 6 × 4
x = 24
\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)
<=> \(\frac{1.2.3....31}{4.6.8....64}=2^n\Rightarrow\frac{1.2.3....30.31}{2\left(2.3.4.5...31\right).32}=2^n\Leftrightarrow\frac{1}{2.32}=2^n\Leftrightarrow\frac{1}{2^6}=2^n\)
=> 2^6.2^n = 1
=> 2^ (n + 6 ) = 2^0
=> n+ 6 = 0
=> n = - 6
\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}....\frac{31}{64}=\frac{1.2.3....31}{4.6.8....64}=\frac{1.2.3....31}{2.3.2.4....2.32}=\frac{1.2.3....31}{2^{30}.\left(3.4....32\right)}=\frac{2}{2^{30}.32}=\frac{1}{2^{34}}=2^{-34}=2^n=>n=-34\)
\(62:\left(x-5\right)\)
\(\Rightarrow62x-310\)
\(\Rightarrow62x=310\)
\(\Rightarrow x=5\)